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/* The Score Card to go with the Yahtzee game.
* At times it is a bit verbose but I did generally
* try to reuse common calls and consolidate when I
* felt it was efficient and still readable/easy to use. */
importjava.util.*;
importjavax.swing.*;
publicclassScoreCard
{
privateint [] scores;
publicScoreCard()
{
scores = newint[15];
for (inti = 0; i < 15; i++)
{
scores[i] = -1;
}
}
publicvoidsetScore(intn, intscore)
{
scores[n] = score;
}
publicintgetScore(intn)
{
returnscores[n];
}
publicintupperScore()
{
intupperScore = 0;
for (inti = 0; i < 6; i++)
if (scores[i] != -1)
upperScore += scores[i];
returnupperScore;
}
publicintbonusScore()
{
if (bonus())
return35;
return0;
}
publicinttotalUpperScore()
{
returnupperScore() + bonusScore();
}
publicintlowerScore()
{
intlowerScore = 0;
for (inti = 6; i < scores.length; i++)
if (scores[i] != -1)
lowerScore += scores[i];
returnlowerScore;
}
publicintgrandTotal()
{
returnupperScore() + lowerScore();
}
publicbooleanbonus()
{
returnupperScore() >= 63;
}
publicbooleanfilled()
{
booleanans = true;
for (inti = 0; i < 13; i++)
if (scores[i] == -1)
ans = false;
returnans;
}
/* use this to test for aces-sixes
* Ex: num(1, dice) will return true if and only if
* they have not yet played 1's, and they have a 1 */
publicbooleannum(intn, Die [] dice)
{
booleanans = false;
for (inti = 0; i < 5; i++)
if (dice[i].value() == n)
ans = true;
returnans;
}
/* use this to test for 3/4 of a kind, and yahtzee.
* Ex: numOfAKind(4, dice) will return true if and only if
* they have not yet played 4 of a kind, and they have it */
publicbooleannumOfAKind(intn, Die [] dice)
{
booleanans = false;
intones = 0, twos = 0, threes = 0, fours = 0, fives = 0, sixes = 0;
for (inti = 0; i < 5; i++)
{
if (dice[i].value() == 1)
ones++;
if (dice[i].value() == 2)
twos++;
if (dice[i].value() == 3)
threes++;
if (dice[i].value() == 4)
fours++;
if (dice[i].value() == 5)
fives++;
if (dice[i].value() == 6)
sixes++;
}
ans = (ones >= n) || (twos >= n) || (threes >= n) || (fours >= n)
|| (fives >= n) || (sixes >= n);
returnans;
}
// brute force calculation, but it gets the job done.
publicbooleanfullHouse(Die [] dice)
{
booleanans = false;
intones = 0, twos = 0, threes = 0, fours = 0, fives = 0, sixes = 0;
for (inti = 0; i < 5; i++)
{
if (dice[i].value() == 1)
ones++;
if (dice[i].value() == 2)
twos++;
if (dice[i].value() == 3)
threes++;
if (dice[i].value() == 4)
fours++;
if (dice[i].value() == 5)
fives++;
if (dice[i].value() == 6)
sixes++;
}
ans = (ones == 3 && (twos == 2 || threes == 2 || fours == 2 ||
fives == 2 || sixes == 2)) || (twos == 3 && (ones == 2 ||
threes == 2 || fours == 2 || fives == 2 || sixes == 2)) ||
(threes == 3 && (ones == 2 || twos == 2 || fours == 2 ||
fives == 2 || sixes == 2)) || (fours == 3 && (ones == 2 ||
threes == 2 || twos == 2 || fives == 2 || sixes == 2))
|| (fives == 3 && (ones == 2 || threes == 2 || fours == 2 ||
twos == 2 || sixes == 2)) || (sixes == 3 && (ones == 2 ||
threes == 2 || fours == 2 || fives == 2 || twos == 2));
returnans;
}
// n == 4 for small, n == 5 for large
publicbooleannumStraight(intn, Die [] dice)
{
booleanans = false;
intones = 0, twos = 0, threes = 0, fours = 0, fives = 0, sixes = 0;
for (inti = 0; i < 5; i++)
{
if (dice[i].value() == 1)
ones++;
if (dice[i].value() == 2)
twos++;
if (dice[i].value() == 3)
threes++;
if (dice[i].value() == 4)
fours++;
if (dice[i].value() == 5)
fives++;
if (dice[i].value() == 6)
sixes++;
}
if (n == 4)
ans = (ones >= 1 && twos >= 1 && threes >= 1 && fours >= 1) ||
(twos >= 1 && threes >= 1 && fours >= 1 && fives >= 1) ||
(threes >= 1 && fours >= 1 && fives >= 1 && sixes >= 1);
if (n == 5)
ans = (ones >= 1 && twos >= 1 && threes >= 1 && fours >= 1 &&
fives >= 1) || (twos >= 1 && threes >= 1 && fours >= 1 &&
fives >= 1 && sixes >= 1);
returnans;
}
publicbooleanchance()
{
returnscores[12] == -1;
}
// true iff there's been a yahtzee, and they have a yahtzee
publicbooleanyahtzeeBonus(Die [] dice)
{
return (numOfAKind(5, dice) && scores[11] == 50);
}
}