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/**
* Interpolation Search
*
* Time Complexity:
* -Best case: O(1)
* -Worst case: O(n)
* -O((log(log(n))) If the data are uniformly distributed
*
*
*/
exportfunctioninterpolationSearch(arr,key){
constlength=arr.length-1
letlow=0
lethigh=length
letposition=-1
letdelta=-1
// Because the array is sorted the key must be between low and high
while(low<=high&&key>=arr[low]&&key<=arr[high]){
delta=(key-arr[low])/(arr[high]-arr[low])
position=low+Math.floor((high-low)*delta)
// Target found return its position
if(arr[position]===key){
returnposition
}
// If the key is larger then it is in the upper part of the array
if(arr[position]<key){
low=position+1
// If the key is smaller then it is in the lower part of the array
}else{
high=position-1
}
}
return-1
}