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76 lines (70 loc) · 1.96 KB
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/**
* Given a sorted array of integers nums and integer values a, b and c. Apply
* a quadratic function of the form f(x) = ax2 + bx + c to each element x in
* the array.
*
* The returned array must be in sorted order.
*
* Expected time complexity: O(n)
*
* Example:
* nums = [-4, -2, 2, 4], a = 1, b = 3, c = 5,
*
* Result: [3, 9, 15, 33]
*
* nums = [-4, -2, 2, 4], a = -1, b = 3, c = 5
*
* Result: [-23, -5, 1, 7]
*/
publicclassSortTransformedArray360 {
publicint[] sortTransformedArray(int[] nums, inta, intb, intc) {
if (nums == null || nums.length == 0) returnnewint[0];
intn = nums.length;
int[] res = newint[n];
inti = 0;
intj = n - 1;
intindex = a >= 0 ? n - 1 : 0;
while (i <= j) {
intii = result(nums[i], a, b, c);
intjj = result(nums[j], a, b, c);
if (a >= 0) {
if (ii >= jj) {
res[index] = ii;
i++;
} else {
res[index] = jj;
j--;
}
index--;
} else {
if (ii >= jj) {
res[index] = jj;
j--;
} else {
res[index] = ii;
i++;
}
index++;
}
}
returnres;
}
privateintresult(intx, inta, intb, intc) {
returna * x * x + b * x + c;
}
publicint[] sortTransformedArray2(int[] nums, inta, intb, intc) {
PriorityQueue<Integer> pq = newPriorityQueue<>();
for (intx: nums) {
pq.add(transfer(x, a, b, c));
}
int[] res = newint[nums.length];
inti = 0;
while (!pq.isEmpty()) {
res[i++] = pq.poll();
}
returnres;
}
privateinttransfer(intx, inta, intb, intc) {
returna * x * x + b * x + c;
}
}