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/**
* Given an array of integers, return indices of the two numbers such that
* they add up to a specific target.
*
* You may assume that each input would have exactly one solution, and
* you may not use the same element twice.
*
* Example:
* Given nums = [2, 7, 11, 15], target = 9,
*
* Because nums[0] + nums[1] = 2 + 7 = 9,
* return [0, 1].
*/
importjava.util.HashMap;
importjava.util.Map;
publicclassTwoSum1 {
publicint[] twoSum(int[] nums, inttarget) {
Map<Integer, Integer> foundSet = newHashMap<>();
int[] returns = newint[2];
for (inti = 0; i < nums.length; i++) {
Integernow = nums[i];
Integerlookingfor = target - now;
if (foundSet.containsKey(lookingfor)) {
returns[0] = foundSet.get(lookingfor);
returns[1] = i;
returnreturns;
} else {
foundSet.put(now, i);
}
}
returnreturns;
}
publicstaticvoidmain(String[] args) {
TwoSum1ts = newTwoSum1();
System.out.println(ts.twoSum(newint[]{2, 7, 11, 15}, 9));
System.out.println(ts.twoSum(newint[]{1, 2, 3}, 5));
}
}