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Copy pathRangeSumQuery.java
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35 lines (29 loc) · 868 Bytes
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/*
Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.
Example:
Given nums = [-2, 0, 3, -5, 2, -1]
sumRange(0, 2) -> 1
sumRange(2, 5) -> -1
sumRange(0, 5) -> -3
Note:
You may assume that the array does not change.
There are many calls to sumRange function.
*/
publicclassNumArray {
publicstaticint[] f = newint[10000];
publicNumArray(int[] nums) {
intsum = 0;
for (inti = 0; i < nums.length; i++) {
sum += nums[i];
f[i] = sum;
}
}
publicintsumRange(inti, intj) {
if (i == 0) returnf[j];
returnf[j] - f[i - 1];
}
}
// Your NumArray object will be instantiated and called as such:
// NumArray numArray = new NumArray(nums);
// numArray.sumRange(0, 1);
// numArray.sumRange(1, 2);