check_input.py

def get_user_input(start,end):

 testcase = False
 while testcase == False:
 try:
 userInput = int(input("Enter Your choice: "))
 if userInput > 6 or userInput < 1:
 print("Please try again.")
 testcase = False
 else:
 return userInput

 except ValueError:
 print("Please try again.") 
 

x = get_user_input(1,6)
print(x)


###Asks user to enter something, ie. a number option from a menu.
###While type != interger, and not in the given range,
###Program gives error message and asks for new input.