Python-code/calc.py at main · markart25/Python-code · GitHub

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#if 5,6,7 used it will work with the first number and wont ask for a second
#made by markthecoderguy on github
importmath
num1=int(input("number:\n "))
option=int(input("operation:\n1 for +\n2 for -\n3 for *\n4 for /\n5 for ²(square) \n6 for √(square root)\n7 for circumference of a circle(will work with diameter if chosen)\n "))
ifoption==5:
print( float(num1*num1) )
elifoption==6:
print(math.sqrt(num1))
elifoption==7:
print (float(num1) * (3.141592653589793238462643))

else:
num2=int(input("number:\n "))

ifoption==1:
print(num1+num2)

elifoption==2:
print (float(num1-num2))

elifoption==3:
print (float(num1*num2))

elifoption==4:
print (float(num1/num2))

else:
print("error")