How can I get the command output even its exit code is not 0?

[0x7FFFFFFFFFFFFFFF]

I have a command pslist -nobanner non-existent-process. When I run it on the command line directly, I got this:

c:\>pslist -nobanner non-existent-process
Process information for Server1:
process non-existent-process was not found on Server1
c:\>echo Exit Code is %errorlevel%
Exit Code is 1
c:\>

As you can see, it outputs some text and have 1 as its exit code. When I run the same command with run_fun!:

 let output:String = cmd_lib::run_fun!(
pslist -nobanner non-existent-process
)?;
if output.contains("was not found on") {
println!("{}", "not running");
} else {
println!("{}", "running...");
}

I got this error:

Error: Running ["pslist", "-nobanner", "non-existent-process"] exited with error; status code: 1

How can I get the command output even its exit code is not 0? Thanks.

[tao-guo]

You can use ignore builtin command, see README or doc.

[0x7FFFFFFFFFFFFFFF]

Thank you! It works.

[0x7FFFFFFFFFFFFFFF]

You can use ignore builtin command, see README or doc.

Btw, I tried ignore but it seems only text written to stdout were returned. How can I get both stdout and stderr merged as the result?

[rust-shell-script]

You can always do redirection, like let res = run_fun!(ignore xxxx 2>&1);. It should be working, right ?