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/**
* Sliding Window:
* This pattern involve creating a window which can either be
* an array or numbers from one position to another.
*
* Depending on a certain condition, the window either increases
* or closes (and a new window is created).
*
* Very useful for keeping track of a subset of data in an
* array/string etc.
*
* Time Complexity: Best - O(n);
*
* Examples:
* maxSubarraySum([1,2,5,2,8,1,5],2) // returns 10
* maxSubarraySum([1,2,5,2,8,1,5],15) // returns null
* maxSubarraySum([5,2,6,9],3) // returns 17
* @param {[Int]} arr - An array of integers on which we will perform the test.
* @param {Int} num - An integer that displays the size of the window you want to check.
* @returns {Int / Null} - Returns a total of N consecutive numbers or null
*/
functionslidingWindow(arr,num){
// Edge Case:
// If the length of the array shorter than the window size (num) return null.
if(arr.length<num)returnnull
// The highest amount of consecutive numbers
letmaxSum=0
// Temp amount of consecutive numbers - For comparative purposes
lettempSum=0
// loop over the array {num} times and save their total amount in {maxSum}
for(leti=0;i<num;i++){
maxSum+=arr[i]
}
// initialize {tempSum} to {maxSum}.
tempSum=maxSum
// loop over the array n times
for(leti=num;i<arr.length;i++){
// Add the next num in the array and remove the first one
tempSum=tempSum-arr[i-num]+arr[i]
// save the largest number between {maxNum} and {tempNum} in maxSum.
maxSum=Math.max(maxSum,tempSum)
}
returnmaxSum
}
export{slidingWindow}