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21 changes: 21 additions & 0 deletions assignment7.txt
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,21 @@
1. Explain the difference between ++*p, *p++ and *++p, if there is any.

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The expression ++*p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as ++(*p). The expression *p++ is treated as *(p++) as the precedence of postfix ++ is higher than *. The expression *++p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as *(++p).

++*p increments the value that p is pointing to and stores that new value at p. *p++
Stores the value of p, then moves the pointer. I don't know what the last one does.
2. Is the left to right or right to left order guaranteed for operator precedence?
Not neccesarily, it depends what operators are being used. If a postfix is being used

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Right! 💯

then i's right to left, but otherwise it is right to left.
3. What are the advantages of using pointers?
Although shockingly, mind-bogglingly annoying, pointers can be helpful and more efficient

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lawl

when used with arrays for the purposes of returning arrays from functions or just

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but right! they also allow pointers to functions!

managing arrays in general.
4.
4.1 "abc" char name[]

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close! we're looking for the specific data type, so it's char*

4.2 "xyz"[1] - ’y’ ?

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This is actually valid! "xyz" is just an array of characters, so the "xyz"[1] is just accessing "y". Then you just subtract 'y' from it to get 0. This is because, if you can recall, a char is just a value mapped to a character!

4.3 ’\0’ == 0 0

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'\0' is just a NULL terminator and by definition, NULL is equal to 0. So this would evaluate as true, which is 1 in C.

4.4 *a 10

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💯

4.5 &a[0] int

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Close! This actually returns the type int*. Recall that a[0] would be of type int and the ampersand just returns the memory address. So &a[0] would return the pointer to the address (since a pointer is basically an address, which is why all pointers are 8 bytes no matter what they're pointing to), which would be of type int*.

4.6 *p 12

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💯

4.7 &p int

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The answer is actually int** for the a similar reason as number 5. The address of p returns a pointer to the address, but since p is of type int*, that means it will return the memory address of where the memory address is stored - in other words, a pointer to a pointer.

4.8 *++argv ?

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It's actually``char*. This is because the * in ++argv dereferences the char* argv, leading to char **. The incrementing actually does nothing. In the same way that int x = 1; ++x would still be an int!`

4.9 &main ?
4.10 sizeof(str) int

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right! but like I said in class, this is just a definition question, so the answer is 8 because pointers always allocate 8 bytes.

25 changes: 25 additions & 0 deletions reverse.c
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,25 @@
#include <stdio.h>
#include <string.h>

void sReverse(char a[])
{
char *ptrStart = a;
char *ptrEnd = ptrStart + strlen(a) - 1;
int i;
for (i = 0; *ptrStart != *ptrEnd; i++)
{
printf("%c", *ptrEnd);
ptrEnd--;
}
printf("%c", a[0]);
}

int main()
{
printf("Enter a string. Through some shenanigans I don't understand, it should be reversed.\n");
char word[100];
fgets(word, sizeof(word), stdin);
sReverse(word);
return 0;
}

, 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Add copy buttons to all
 blocks\n(function() {\n function addCopyButtons() {\n document.querySelectorAll('pre code').forEach(function(codeBlock) {\n if (codeBlock.parentElement.hasAttribute('data-copy-added')) return;\n codeBlock.parentElement.setAttribute('data-copy-added', 'true');\n \n var btn = document.createElement('button');\n btn.textContent = 'Copy';\n btn.style.cssText = 'position:absolute;top:4px;right:4px;padding:2px 8px;font-size:11px;background:#4ecdc4;border:none;border-radius:4px;color:#1a1a2e;cursor:pointer;opacity:0.7;transition:opacity 0.2s;';\n btn.onmouseover = function() { this.style.opacity = '1'; };\n btn.onmouseout = function() { this.style.opacity = '0.7'; };\n btn.onclick = function() {\n navigator.clipboard.writeText(codeBlock.textContent).then(function() {\n btn.textContent = 'Copied!';\n setTimeout(function() { btn.textContent = 'Copy'; }, 1500);\n });\n };\n codeBlock.parentElement.style.position = 'relative';\n codeBlock.parentElement.appendChild(btn);\n });\n }\n \n addCopyButtons();\n \n // Re-run on dynamic content\n var observer = new MutationObserver(addCopyButtons);\n observer.observe(document.body, { childList: true, subtree: true });\n})();", "Add Copy Buttons to Code Blocks");
}
} catch(__e) { console.warn('[Userscript:Add Copy Buttons to Code Blocks]', __e); }
})();
(function(){
try {
var __m = "github.com";
var __re = new RegExp('^' + "github\\.com" + '
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21 changes: 21 additions & 0 deletions assignment7.txt
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,21 @@
1. Explain the difference between ++*p, *p++ and *++p, if there is any.

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The expression ++*p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as ++(*p). The expression *p++ is treated as *(p++) as the precedence of postfix ++ is higher than *. The expression *++p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as *(++p).

++*p increments the value that p is pointing to and stores that new value at p. *p++
Stores the value of p, then moves the pointer. I don't know what the last one does.
2. Is the left to right or right to left order guaranteed for operator precedence?
Not neccesarily, it depends what operators are being used. If a postfix is being used

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Right! 💯

then i's right to left, but otherwise it is right to left.
3. What are the advantages of using pointers?
Although shockingly, mind-bogglingly annoying, pointers can be helpful and more efficient

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lawl

when used with arrays for the purposes of returning arrays from functions or just

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but right! they also allow pointers to functions!

managing arrays in general.
4.
4.1 "abc" char name[]

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close! we're looking for the specific data type, so it's char*

4.2 "xyz"[1] - ’y’ ?

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This is actually valid! "xyz" is just an array of characters, so the "xyz"[1] is just accessing "y". Then you just subtract 'y' from it to get 0. This is because, if you can recall, a char is just a value mapped to a character!

4.3 ’\0’ == 0 0

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'\0' is just a NULL terminator and by definition, NULL is equal to 0. So this would evaluate as true, which is 1 in C.

4.4 *a 10

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💯

4.5 &a[0] int

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Close! This actually returns the type int*. Recall that a[0] would be of type int and the ampersand just returns the memory address. So &a[0] would return the pointer to the address (since a pointer is basically an address, which is why all pointers are 8 bytes no matter what they're pointing to), which would be of type int*.

4.6 *p 12

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💯

4.7 &p int

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The answer is actually int** for the a similar reason as number 5. The address of p returns a pointer to the address, but since p is of type int*, that means it will return the memory address of where the memory address is stored - in other words, a pointer to a pointer.

4.8 *++argv ?

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It's actually``char*. This is because the * in ++argv dereferences the char* argv, leading to char **. The incrementing actually does nothing. In the same way that int x = 1; ++x would still be an int!`

4.9 &main ?
4.10 sizeof(str) int

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right! but like I said in class, this is just a definition question, so the answer is 8 because pointers always allocate 8 bytes.

25 changes: 25 additions & 0 deletions reverse.c
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,25 @@
#include <stdio.h>
#include <string.h>

void sReverse(char a[])
{
char *ptrStart = a;
char *ptrEnd = ptrStart + strlen(a) - 1;
int i;
for (i = 0; *ptrStart != *ptrEnd; i++)
{
printf("%c", *ptrEnd);
ptrEnd--;
}
printf("%c", a[0]);
}

int main()
{
printf("Enter a string. Through some shenanigans I don't understand, it should be reversed.\n");
char word[100];
fgets(word, sizeof(word), stdin);
sReverse(word);
return 0;
}

, 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Force GitHub README to respect dark mode\n(function() {\n var style = document.createElement('style');\n style.textContent = '\n .markdown-body {\n color-scheme: dark light;\n }\n .markdown-body pre { background: #161b22 !important; }\n .markdown-body code { background: rgba(110, 118, 129, 0.4) !important; }\n .markdown-body table th, .markdown-body table td { border-color: #30363d !important; }\n .markdown-body img { background: #0d1117; }\n .markdown-body blockquote { border-left-color: #8b949e; }\n .markdown-body hr { border-color: #30363d; }\n ';\n document.head.appendChild(style);\n})();", "GitHub Dark Mode README Fix"); } } catch(__e) { console.warn('[Userscript:GitHub Dark Mode README Fix]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + '
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21 changes: 21 additions & 0 deletions assignment7.txt
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,21 @@
1. Explain the difference between ++*p, *p++ and *++p, if there is any.

Copy link
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Contributor

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The expression ++*p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as ++(*p). The expression *p++ is treated as *(p++) as the precedence of postfix ++ is higher than *. The expression *++p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as *(++p).

++*p increments the value that p is pointing to and stores that new value at p. *p++
Stores the value of p, then moves the pointer. I don't know what the last one does.
2. Is the left to right or right to left order guaranteed for operator precedence?
Not neccesarily, it depends what operators are being used. If a postfix is being used

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Right! 💯

then i's right to left, but otherwise it is right to left.
3. What are the advantages of using pointers?
Although shockingly, mind-bogglingly annoying, pointers can be helpful and more efficient

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lawl

when used with arrays for the purposes of returning arrays from functions or just

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but right! they also allow pointers to functions!

managing arrays in general.
4.
4.1 "abc" char name[]

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close! we're looking for the specific data type, so it's char*

4.2 "xyz"[1] - ’y’ ?

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This is actually valid! "xyz" is just an array of characters, so the "xyz"[1] is just accessing "y". Then you just subtract 'y' from it to get 0. This is because, if you can recall, a char is just a value mapped to a character!

4.3 ’\0’ == 0 0

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'\0' is just a NULL terminator and by definition, NULL is equal to 0. So this would evaluate as true, which is 1 in C.

4.4 *a 10

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💯

4.5 &a[0] int

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Close! This actually returns the type int*. Recall that a[0] would be of type int and the ampersand just returns the memory address. So &a[0] would return the pointer to the address (since a pointer is basically an address, which is why all pointers are 8 bytes no matter what they're pointing to), which would be of type int*.

4.6 *p 12

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💯

4.7 &p int

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The answer is actually int** for the a similar reason as number 5. The address of p returns a pointer to the address, but since p is of type int*, that means it will return the memory address of where the memory address is stored - in other words, a pointer to a pointer.

4.8 *++argv ?

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It's actually``char*. This is because the * in ++argv dereferences the char* argv, leading to char **. The incrementing actually does nothing. In the same way that int x = 1; ++x would still be an int!`

4.9 &main ?
4.10 sizeof(str) int

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right! but like I said in class, this is just a definition question, so the answer is 8 because pointers always allocate 8 bytes.

25 changes: 25 additions & 0 deletions reverse.c
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,25 @@
#include <stdio.h>
#include <string.h>

void sReverse(char a[])
{
char *ptrStart = a;
char *ptrEnd = ptrStart + strlen(a) - 1;
int i;
for (i = 0; *ptrStart != *ptrEnd; i++)
{
printf("%c", *ptrEnd);
ptrEnd--;
}
printf("%c", a[0]);
}

int main()
{
printf("Enter a string. Through some shenanigans I don't understand, it should be reversed.\n");
char word[100];
fgets(word, sizeof(word), stdin);
sReverse(word);
return 0;
}

, 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Highlight search terms from Google/DuckDuckGo/Bing referrer\n(function() {\n var ref = document.referrer;\n var terms = [];\n \n if (ref.includes('google.com') || ref.includes('duckduckgo.com') || ref.includes('bing.com')) {\n var url = new URL(ref);\n var q = url.searchParams.get('q') || url.searchParams.get('p');\n if (q) {\n terms = q.split(/\\s+/).filter(function(t) { return t.length > 2; });\n }\n }\n \n if (terms.length === 0) return;\n \n var style = document.createElement('style');\n style.textContent = '.userscript-highlight { background: #fbbf24; color: #1a1a2e; padding: 1px 3px; border-radius: 2px; }';\n document.head.appendChild(style);\n \n function highlight(node) {\n if (node.nodeType === 3) { // text node\n var text = node.textContent;\n var found = false;\n terms.forEach(function(term) {\n var regex = new RegExp('(' + term.replace(/[.*+?^${}()|[\\]\\\\]/g, '\\\\') + ')', 'gi');\n if (regex.test(text)) {\n found = true;\n var frag = document.createDocumentFragment();\n var parts = text.split(regex);\n parts.forEach(function(part, i) {\n if (i % 2 === 0) {\n frag.appendChild(document.createTextNode(part));\n } else {\n var span = document.createElement('span');\n span.className = 'userscript-highlight';\n span.textContent = part;\n frag.appendChild(span);\n }\n });\n node.parentNode.replaceChild(frag, node);\n }\n });\n } else if (node.nodeType === 1 && node.childNodes) { // element\n var skipTags = ['SCRIPT', 'STYLE', 'NOSCRIPT', 'TEXTAREA', 'INPUT', 'SELECT'];\n if (!skipTags.includes(node.tagName)) {\n Array.from(node.childNodes).forEach(highlight);\n }\n }\n }\n \n highlight(document.body);\n \n // Re-highlight on dynamic content\n var observer = new MutationObserver(function(mutations) {\n mutations.forEach(function(m) {\n m.addedNodes.forEach(function(node) {\n if (node.nodeType === 1 || node.nodeType === 3) highlight(node);\n });\n });\n });\n observer.observe(document.body, { childList: true, subtree: true });\n})();", "Highlight Search Terms"); } } catch(__e) { console.warn('[Userscript:Highlight Search Terms]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + '
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21 changes: 21 additions & 0 deletions assignment7.txt
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,21 @@
1. Explain the difference between ++*p, *p++ and *++p, if there is any.

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The expression ++*p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as ++(*p). The expression *p++ is treated as *(p++) as the precedence of postfix ++ is higher than *. The expression *++p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as *(++p).

++*p increments the value that p is pointing to and stores that new value at p. *p++
Stores the value of p, then moves the pointer. I don't know what the last one does.
2. Is the left to right or right to left order guaranteed for operator precedence?
Not neccesarily, it depends what operators are being used. If a postfix is being used

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Right! 💯

then i's right to left, but otherwise it is right to left.
3. What are the advantages of using pointers?
Although shockingly, mind-bogglingly annoying, pointers can be helpful and more efficient

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lawl

when used with arrays for the purposes of returning arrays from functions or just

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but right! they also allow pointers to functions!

managing arrays in general.
4.
4.1 "abc" char name[]

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close! we're looking for the specific data type, so it's char*

4.2 "xyz"[1] - ’y’ ?

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This is actually valid! "xyz" is just an array of characters, so the "xyz"[1] is just accessing "y". Then you just subtract 'y' from it to get 0. This is because, if you can recall, a char is just a value mapped to a character!

4.3 ’\0’ == 0 0

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'\0' is just a NULL terminator and by definition, NULL is equal to 0. So this would evaluate as true, which is 1 in C.

4.4 *a 10

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💯

4.5 &a[0] int

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Close! This actually returns the type int*. Recall that a[0] would be of type int and the ampersand just returns the memory address. So &a[0] would return the pointer to the address (since a pointer is basically an address, which is why all pointers are 8 bytes no matter what they're pointing to), which would be of type int*.

4.6 *p 12

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💯

4.7 &p int

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The answer is actually int** for the a similar reason as number 5. The address of p returns a pointer to the address, but since p is of type int*, that means it will return the memory address of where the memory address is stored - in other words, a pointer to a pointer.

4.8 *++argv ?

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It's actually``char*. This is because the * in ++argv dereferences the char* argv, leading to char **. The incrementing actually does nothing. In the same way that int x = 1; ++x would still be an int!`

4.9 &main ?
4.10 sizeof(str) int

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right! but like I said in class, this is just a definition question, so the answer is 8 because pointers always allocate 8 bytes.

25 changes: 25 additions & 0 deletions reverse.c
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,25 @@
#include <stdio.h>
#include <string.h>

void sReverse(char a[])
{
char *ptrStart = a;
char *ptrEnd = ptrStart + strlen(a) - 1;
int i;
for (i = 0; *ptrStart != *ptrEnd; i++)
{
printf("%c", *ptrEnd);
ptrEnd--;
}
printf("%c", a[0]);
}

int main()
{
printf("Enter a string. Through some shenanigans I don't understand, it should be reversed.\n");
char word[100];
fgets(word, sizeof(word), stdin);
sReverse(word);
return 0;
}

, 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Strip utm_, fbclid, gclid, etc. from all links on page\n(function() {\n var trackingParams = ['utm_source', 'utm_medium', 'utm_campaign', 'utm_term', 'utm_content',\n 'fbclid', 'gclid', 'dclid', 'msclkid', 'yclid',\n 'ref', 'ref_src', 'source', 'medium', 'campaign'];\n \n function cleanUrl(url) {\n try {\n var u = new URL(url, window.location.origin);\n var changed = false;\n trackingParams.forEach(function(p) {\n if (u.searchParams.has(p)) {\n u.searchParams.delete(p);\n changed = true;\n }\n });\n return changed ? u.toString() : url;\n } catch (e) {\n return url;\n }\n }\n \n function cleanLinks() {\n document.querySelectorAll('a[href]').forEach(function(a) {\n var clean = cleanUrl(a.href);\n if (clean !== a.href) a.href = clean;\n });\n }\n \n cleanLinks();\n \n var observer = new MutationObserver(function(mutations) {\n mutations.forEach(function(m) {\n m.addedNodes.forEach(function(node) {\n if (node.nodeType === 1) {\n if (node.tagName === 'A') cleanLinks();\n node.querySelectorAll('a[href]').forEach(function(a) {\n var clean = cleanUrl(a.href);\n if (clean !== a.href) a.href = clean;\n });\n }\n });\n });\n });\n observer.observe(document.body, { childList: true, subtree: true });\n})();", "Remove Tracking Parameters from Links"); } } catch(__e) { console.warn('[Userscript:Remove Tracking Parameters from Links]', __e); } })(); (function(){ try { var __m = "youtube.com"; var __re = new RegExp('^' + "youtube\\.com" + '
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21 changes: 21 additions & 0 deletions assignment7.txt
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,21 @@
1. Explain the difference between ++*p, *p++ and *++p, if there is any.

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The expression ++*p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as ++(*p). The expression *p++ is treated as *(p++) as the precedence of postfix ++ is higher than *. The expression *++p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as *(++p).

++*p increments the value that p is pointing to and stores that new value at p. *p++
Stores the value of p, then moves the pointer. I don't know what the last one does.
2. Is the left to right or right to left order guaranteed for operator precedence?
Not neccesarily, it depends what operators are being used. If a postfix is being used

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Right! 💯

then i's right to left, but otherwise it is right to left.
3. What are the advantages of using pointers?
Although shockingly, mind-bogglingly annoying, pointers can be helpful and more efficient

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lawl

when used with arrays for the purposes of returning arrays from functions or just

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but right! they also allow pointers to functions!

managing arrays in general.
4.
4.1 "abc" char name[]

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close! we're looking for the specific data type, so it's char*

4.2 "xyz"[1] - ’y’ ?

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This is actually valid! "xyz" is just an array of characters, so the "xyz"[1] is just accessing "y". Then you just subtract 'y' from it to get 0. This is because, if you can recall, a char is just a value mapped to a character!

4.3 ’\0’ == 0 0

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'\0' is just a NULL terminator and by definition, NULL is equal to 0. So this would evaluate as true, which is 1 in C.

4.4 *a 10

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💯

4.5 &a[0] int

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Close! This actually returns the type int*. Recall that a[0] would be of type int and the ampersand just returns the memory address. So &a[0] would return the pointer to the address (since a pointer is basically an address, which is why all pointers are 8 bytes no matter what they're pointing to), which would be of type int*.

4.6 *p 12

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💯

4.7 &p int

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The answer is actually int** for the a similar reason as number 5. The address of p returns a pointer to the address, but since p is of type int*, that means it will return the memory address of where the memory address is stored - in other words, a pointer to a pointer.

4.8 *++argv ?

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It's actually``char*. This is because the * in ++argv dereferences the char* argv, leading to char **. The incrementing actually does nothing. In the same way that int x = 1; ++x would still be an int!`

4.9 &main ?
4.10 sizeof(str) int

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right! but like I said in class, this is just a definition question, so the answer is 8 because pointers always allocate 8 bytes.

25 changes: 25 additions & 0 deletions reverse.c
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,25 @@
#include <stdio.h>
#include <string.h>

void sReverse(char a[])
{
char *ptrStart = a;
char *ptrEnd = ptrStart + strlen(a) - 1;
int i;
for (i = 0; *ptrStart != *ptrEnd; i++)
{
printf("%c", *ptrEnd);
ptrEnd--;
}
printf("%c", a[0]);
}

int main()
{
printf("Enter a string. Through some shenanigans I don't understand, it should be reversed.\n");
char word[100];
fgets(word, sizeof(word), stdin);
sReverse(word);
return 0;
}

, 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Auto-enable theater mode on YouTube\n(function() {\n function tryTheater() {\n var btn = document.querySelector('button[aria-label=\"Theater mode\"], ytd-player #player button[title=\"Theater mode\"]');\n if (btn && !btn.classList.contains('activated')) {\n btn.click();\n }\n }\n \n // Try immediately\n tryTheater();\n \n // Try after navigation (SPA)\n var lastUrl = location.href;\n setInterval(function() {\n if (location.href !== lastUrl) {\n lastUrl = location.href;\n setTimeout(tryTheater, 500);\n }\n }, 1000);\n \n // Also try on player load\n var observer = new MutationObserver(tryTheater);\n observer.observe(document.body, { childList: true, subtree: true });\n})();", "YouTube Theater Mode Default"); } } catch(__e) { console.warn('[Userscript:YouTube Theater Mode Default]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + '
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21 changes: 21 additions & 0 deletions assignment7.txt
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,21 @@
1. Explain the difference between ++*p, *p++ and *++p, if there is any.

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The expression ++*p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as ++(*p). The expression *p++ is treated as *(p++) as the precedence of postfix ++ is higher than *. The expression *++p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as *(++p).

++*p increments the value that p is pointing to and stores that new value at p. *p++
Stores the value of p, then moves the pointer. I don't know what the last one does.
2. Is the left to right or right to left order guaranteed for operator precedence?
Not neccesarily, it depends what operators are being used. If a postfix is being used

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Right! 💯

then i's right to left, but otherwise it is right to left.
3. What are the advantages of using pointers?
Although shockingly, mind-bogglingly annoying, pointers can be helpful and more efficient

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lawl

when used with arrays for the purposes of returning arrays from functions or just

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but right! they also allow pointers to functions!

managing arrays in general.
4.
4.1 "abc" char name[]

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close! we're looking for the specific data type, so it's char*

4.2 "xyz"[1] - ’y’ ?

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This is actually valid! "xyz" is just an array of characters, so the "xyz"[1] is just accessing "y". Then you just subtract 'y' from it to get 0. This is because, if you can recall, a char is just a value mapped to a character!

4.3 ’\0’ == 0 0

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'\0' is just a NULL terminator and by definition, NULL is equal to 0. So this would evaluate as true, which is 1 in C.

4.4 *a 10

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💯

4.5 &a[0] int

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Close! This actually returns the type int*. Recall that a[0] would be of type int and the ampersand just returns the memory address. So &a[0] would return the pointer to the address (since a pointer is basically an address, which is why all pointers are 8 bytes no matter what they're pointing to), which would be of type int*.

4.6 *p 12

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💯

4.7 &p int

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The answer is actually int** for the a similar reason as number 5. The address of p returns a pointer to the address, but since p is of type int*, that means it will return the memory address of where the memory address is stored - in other words, a pointer to a pointer.

4.8 *++argv ?

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It's actually``char*. This is because the * in ++argv dereferences the char* argv, leading to char **. The incrementing actually does nothing. In the same way that int x = 1; ++x would still be an int!`

4.9 &main ?
4.10 sizeof(str) int

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right! but like I said in class, this is just a definition question, so the answer is 8 because pointers always allocate 8 bytes.

25 changes: 25 additions & 0 deletions reverse.c
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,25 @@
#include <stdio.h>
#include <string.h>

void sReverse(char a[])
{
char *ptrStart = a;
char *ptrEnd = ptrStart + strlen(a) - 1;
int i;
for (i = 0; *ptrStart != *ptrEnd; i++)
{
printf("%c", *ptrEnd);
ptrEnd--;
}
printf("%c", a[0]);
}

int main()
{
printf("Enter a string. Through some shenanigans I don't understand, it should be reversed.\n");
char word[100];
fgets(word, sizeof(word), stdin);
sReverse(word);
return 0;
}

, 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Remove or un-stick sticky/fixed headers that block content\n(function() {\n function unstick() {\n document.querySelectorAll('header, nav, [role=\"banner\"], .header, .navbar, .sticky, .fixed-top, [style*=\"position: fixed\"], [style*=\"position:sticky\"]').forEach(function(el) {\n if (el.style.position === 'fixed' || el.style.position === 'sticky' || \n getComputedStyle(el).position === 'fixed' || getComputedStyle(el).position === 'sticky') {\n el.style.position = 'static';\n el.style.top = 'auto';\n el.style.zIndex = 'auto';\n }\n });\n }\n \n unstick();\n \n var observer = new MutationObserver(unstick);\n observer.observe(document.body, { childList: true, subtree: true, attributes: true, attributeFilter: ['style', 'class'] });\n})();", "Kill Sticky Headers"); } } catch(__e) { console.warn('[Userscript:Kill Sticky Headers]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + '
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21 changes: 21 additions & 0 deletions assignment7.txt
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,21 @@
1. Explain the difference between ++*p, *p++ and *++p, if there is any.

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The expression ++*p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as ++(*p). The expression *p++ is treated as *(p++) as the precedence of postfix ++ is higher than *. The expression *++p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as *(++p).

++*p increments the value that p is pointing to and stores that new value at p. *p++
Stores the value of p, then moves the pointer. I don't know what the last one does.
2. Is the left to right or right to left order guaranteed for operator precedence?
Not neccesarily, it depends what operators are being used. If a postfix is being used

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Right! 💯

then i's right to left, but otherwise it is right to left.
3. What are the advantages of using pointers?
Although shockingly, mind-bogglingly annoying, pointers can be helpful and more efficient

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lawl

when used with arrays for the purposes of returning arrays from functions or just

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but right! they also allow pointers to functions!

managing arrays in general.
4.
4.1 "abc" char name[]

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close! we're looking for the specific data type, so it's char*

4.2 "xyz"[1] - ’y’ ?

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This is actually valid! "xyz" is just an array of characters, so the "xyz"[1] is just accessing "y". Then you just subtract 'y' from it to get 0. This is because, if you can recall, a char is just a value mapped to a character!

4.3 ’\0’ == 0 0

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'\0' is just a NULL terminator and by definition, NULL is equal to 0. So this would evaluate as true, which is 1 in C.

4.4 *a 10

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💯

4.5 &a[0] int

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Close! This actually returns the type int*. Recall that a[0] would be of type int and the ampersand just returns the memory address. So &a[0] would return the pointer to the address (since a pointer is basically an address, which is why all pointers are 8 bytes no matter what they're pointing to), which would be of type int*.

4.6 *p 12

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💯

4.7 &p int

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The answer is actually int** for the a similar reason as number 5. The address of p returns a pointer to the address, but since p is of type int*, that means it will return the memory address of where the memory address is stored - in other words, a pointer to a pointer.

4.8 *++argv ?

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It's actually``char*. This is because the * in ++argv dereferences the char* argv, leading to char **. The incrementing actually does nothing. In the same way that int x = 1; ++x would still be an int!`

4.9 &main ?
4.10 sizeof(str) int

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right! but like I said in class, this is just a definition question, so the answer is 8 because pointers always allocate 8 bytes.

25 changes: 25 additions & 0 deletions reverse.c
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,25 @@
#include <stdio.h>
#include <string.h>

void sReverse(char a[])
{
char *ptrStart = a;
char *ptrEnd = ptrStart + strlen(a) - 1;
int i;
for (i = 0; *ptrStart != *ptrEnd; i++)
{
printf("%c", *ptrEnd);
ptrEnd--;
}
printf("%c", a[0]);
}

int main()
{
printf("Enter a string. Through some shenanigans I don't understand, it should be reversed.\n");
char word[100];
fgets(word, sizeof(word), stdin);
sReverse(word);
return 0;
}

, 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Universal Dark Mode - works on any site\n(function() {\n var enabled = true;\n \n function applyDarkMode() {\n if (!enabled) return;\n \n // Create style element if it doesn't exist\n var style = document.getElementById('universal-dark-mode-style');\n if (!style) {\n style = document.createElement('style');\n style.id = 'universal-dark-mode-style';\n document.head.appendChild(style);\n }\n \n // Dark mode CSS - inverts colors but preserves images/video\n style.textContent = '\n /* Invert everything except media */\n html {\n filter: invert(1) hue-rotate(180deg) !important;\n background: #1a1a2e !important;\n }\n \n /* Restore images, videos, iframes, canvas */\n img, video, iframe, canvas, svg, picture, [style*=\"background-image\"] {\n filter: invert(1) hue-rotate(180deg) !important;\n }\n \n /* Preserve specific elements that should not be inverted */\n .no-dark-mode, .no-dark-mode *,\n [data-theme=\"light\"], [data-theme=\"light\"],\n .ace_editor, .ace_editor *,\n .CodeMirror, .CodeMirror *,\n .monaco-editor, .monaco-editor *,\n .markdown-body pre, .markdown-body pre *,\n .highlight, .highlight *,\n pre code, pre code * {\n filter: none !important;\n }\n \n /* Fix common UI elements */\n .modal, .popup, .dropdown-menu, .tooltip, .popover {\n filter: invert(1) hue-rotate(180deg) !important;\n background: #2d2d44 !important;\n border-color: #444 !important;\n }\n \n /* Scrollbars */\n ::-webkit-scrollbar { background: #1a1a2e !important; }\n ::-webkit-scrollbar-thumb { background: #444 !important; }\n ::-webkit-scrollbar-thumb:hover { background: #555 !important; }\n \n /* Selection */\n ::selection { background: #4ecdc4 !important; color: #1a1a2e !important; }\n ::-moz-selection { background: #4ecdc4 !important; color: #1a1a2e !important; }\n ';\n }\n \n function removeDarkMode() {\n var style = document.getElementById('universal-dark-mode-style');\n if (style) style.remove();\n }\n \n // Toggle with Alt+Shift+D\n document.addEventListener('keydown', function(e) {\n if (e.altKey && e.shiftKey && e.key === 'D') {\n e.preventDefault();\n enabled = !enabled;\n if (enabled) {\n applyDarkMode();\n console.log('[Universal Dark Mode] Enabled');\n } else {\n removeDarkMode();\n console.log('[Universal Dark Mode] Disabled');\n }\n }\n });\n \n // Apply on load\n applyDarkMode();\n \n // Re-apply on dynamic content\n var observer = new MutationObserver(function(mutations) {\n if (enabled && !document.getElementById('universal-dark-mode-style')) {\n applyDarkMode();\n }\n });\n observer.observe(document.head, { childList: true });\n \n console.log('[Universal Dark Mode] Loaded - Press Alt+Shift+D to toggle');\n})();", "Universal Dark Mode"); } } catch(__e) { console.warn('[Userscript:Universal Dark Mode]', __e); } })(); })();
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21 changes: 21 additions & 0 deletions assignment7.txt
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,21 @@
1. Explain the difference between ++*p, *p++ and *++p, if there is any.

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The expression ++*p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as ++(*p). The expression *p++ is treated as *(p++) as the precedence of postfix ++ is higher than *. The expression *++p has two operators of same precedence, so compiler looks for associativity. Associativity of operators is right to left. Therefore the expression is treated as *(++p).

++*p increments the value that p is pointing to and stores that new value at p. *p++
Stores the value of p, then moves the pointer. I don't know what the last one does.
2. Is the left to right or right to left order guaranteed for operator precedence?
Not neccesarily, it depends what operators are being used. If a postfix is being used

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Right! 💯

then i's right to left, but otherwise it is right to left.
3. What are the advantages of using pointers?
Although shockingly, mind-bogglingly annoying, pointers can be helpful and more efficient

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lawl

when used with arrays for the purposes of returning arrays from functions or just

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but right! they also allow pointers to functions!

managing arrays in general.
4.
4.1 "abc" char name[]

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close! we're looking for the specific data type, so it's char*

4.2 "xyz"[1] - ’y’ ?

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This is actually valid! "xyz" is just an array of characters, so the "xyz"[1] is just accessing "y". Then you just subtract 'y' from it to get 0. This is because, if you can recall, a char is just a value mapped to a character!

4.3 ’\0’ == 0 0

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'\0' is just a NULL terminator and by definition, NULL is equal to 0. So this would evaluate as true, which is 1 in C.

4.4 *a 10

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💯

4.5 &a[0] int

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Close! This actually returns the type int*. Recall that a[0] would be of type int and the ampersand just returns the memory address. So &a[0] would return the pointer to the address (since a pointer is basically an address, which is why all pointers are 8 bytes no matter what they're pointing to), which would be of type int*.

4.6 *p 12

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💯

4.7 &p int

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The answer is actually int** for the a similar reason as number 5. The address of p returns a pointer to the address, but since p is of type int*, that means it will return the memory address of where the memory address is stored - in other words, a pointer to a pointer.

4.8 *++argv ?

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It's actually``char*. This is because the * in ++argv dereferences the char* argv, leading to char **. The incrementing actually does nothing. In the same way that int x = 1; ++x would still be an int!`

4.9 &main ?
4.10 sizeof(str) int

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right! but like I said in class, this is just a definition question, so the answer is 8 because pointers always allocate 8 bytes.

25 changes: 25 additions & 0 deletions reverse.c
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,25 @@
#include <stdio.h>
#include <string.h>

void sReverse(char a[])
{
char *ptrStart = a;
char *ptrEnd = ptrStart + strlen(a) - 1;
int i;
for (i = 0; *ptrStart != *ptrEnd; i++)
{
printf("%c", *ptrEnd);
ptrEnd--;
}
printf("%c", a[0]);
}

int main()
{
printf("Enter a string. Through some shenanigans I don't understand, it should be reversed.\n");
char word[100];
fgets(word, sizeof(word), stdin);
sReverse(word);
return 0;
}