Region cannot be set using url parameters

[sdorgancs]

Hello,
I would like to be able to set the region using url parameters, like in the example below:

fs = open_fs('s3://testbucket?endpoint_url=localhost:9000&region=us-east-1')

But S3FSOpener in opener.py doest not get it

class S3FSOpener(Opener):
 protocols = ["s3"]

 def open_fs(self, fs_url, parse_result, writeable, create, cwd):
 bucket_name, _, dir_path = parse_result.resource.partition("/")
 if not bucket_name:
 raise OpenerError("invalid bucket name in '{}'".format(fs_url))
 strict = (
 parse_result.params["strict"] == "1"
 if "strict" in parse_result.params
 else True
 )
 s3fs = S3FS(
 bucket_name,
 dir_path=dir_path or "/",
 aws_access_key_id=parse_result.username or None,
 aws_secret_access_key=parse_result.password or None,
 endpoint_url=parse_result.params.get("endpoint_url", None),
 acl=parse_result.params.get("acl", None),
 cache_control=parse_result.params.get("cache_control", None),
 strict=strict,
 )
 return s3fs

The change to make it working is very simple

class S3FSOpener(Opener):
 protocols = ["s3"]

 def open_fs(self, fs_url, parse_result, writeable, create, cwd):
 bucket_name, _, dir_path = parse_result.resource.partition("/")
 if not bucket_name:
 raise OpenerError("invalid bucket name in '{}'".format(fs_url))
 strict = (
 parse_result.params["strict"] == "1"
 if "strict" in parse_result.params
 else True
 )
 s3fs = S3FS(
 bucket_name,
 dir_path=dir_path or "/",
 aws_access_key_id=parse_result.username or None,
 aws_secret_access_key=parse_result.password or None,
 endpoint_url=parse_result.params.get("endpoint_url", None),
 # line to add
 region=parse_result.params.get("region", None),
 acl=parse_result.params.get("acl", None),
 cache_control=parse_result.params.get("cache_control", None),
 strict=strict,
 )
 return s3fs

Could you manage this?