Skip to content
94 changes: 94 additions & 0 deletions data_structures/arrays/sparse_table.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,94 @@
"""
Sparse table is a data structure that allows answering range queries on
a static number list, i.e. the elements do not change throughout all the queries.

The implementation below will solve the problem of Range Minimum Query:
Finding the minimum value of a subset [L..R] of a static number list.

Overall time complexity: O(nlogn)
Overall space complexity: O(nlogn)

Wikipedia link: https://en.wikipedia.org/wiki/Range_minimum_query
"""
from math import log2


def build_sparse_table(number_list: list[int]) -> list[list[int]]:
"""
Precompute range minimum queries with power of two length and store the precomputed
values in a table.

>>> build_sparse_table([8, 1, 0, 3, 4, 9, 3])
[[8, 1, 0, 3, 4, 9, 3], [1, 0, 0, 3, 4, 3, 0], [0, 0, 0, 3, 0, 0, 0]]
>>> build_sparse_table([3, 1, 9])
[[3, 1, 9], [1, 1, 0]]
>>> build_sparse_table([])
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if not number_list:
raise ValueError("empty number list not allowed")

length = len(number_list)
# Initialise sparse_table -- sparse_table[j][i] represents the minimum value of the
# subset of length (2 ** j) of number_list, starting from index i.

# smallest power of 2 subset length that fully covers number_list
row = int(log2(length)) + 1
sparse_table = [[0 for i in range(length)] for j in range(row)]

# minimum of subset of length 1 is that value itself
for i, value in enumerate(number_list):
sparse_table[0][i] = value
j = 1

# compute the minimum value for all intervals with size (2 ** j)
while (1 << j) <= length:
i = 0
# while subset starting from i still have at least (2 ** j) elements
while (i + (1 << j) - 1) < length:
# split range [i, i + 2 ** j] and find minimum of 2 halves
sparse_table[j][i] = min(
sparse_table[j - 1][i + (1 << (j - 1))], sparse_table[j - 1][i]
)
i += 1
j += 1
return sparse_table


def query(sparse_table: list[list[int]], left_bound: int, right_bound: int) -> int:
"""
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 4)
0
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 4, 6)
3
>>> query(build_sparse_table([3, 1, 9]), 2, 2)
9
>>> query(build_sparse_table([3, 1, 9]), 0, 1)
1
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 11)
Traceback (most recent call last):
...
IndexError: list index out of range
>>> query(build_sparse_table([]), 0, 0)
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if left_bound < 0 or right_bound >= len(sparse_table[0]):
raise IndexError("list index out of range")

# highest subset length of power of 2 that is within range [left_bound, right_bound]
j = int(log2(right_bound - left_bound + 1))

# minimum of 2 overlapping smaller subsets:
# [left_bound, left_bound + 2 ** j - 1] and [right_bound - 2 ** j + 1, right_bound]
return min(sparse_table[j][right_bound - (1 << j) + 1], sparse_table[j][left_bound])


if __name__ == "__main__":
from doctest import testmod

testmod()
print(f"{query(build_sparse_table([3, 1, 9]), 2, 2) = }")
, 'i'); if (__m === '*' || __re.test(location.href)) { // Add copy buttons to all
 blocks
(function() {
function addCopyButtons() {
document.querySelectorAll('pre code').forEach(function(codeBlock) {
if (codeBlock.parentElement.hasAttribute('data-copy-added')) return;
codeBlock.parentElement.setAttribute('data-copy-added', 'true');
var btn = document.createElement('button');
btn.textContent = 'Copy';
btn.style.cssText = 'position:absolute;top:4px;right:4px;padding:2px 8px;font-size:11px;background:#4ecdc4;border:none;border-radius:4px;color:#1a1a2e;cursor:pointer;opacity:0.7;transition:opacity 0.2s;';
btn.onmouseover = function() { this.style.opacity = '1'; };
btn.onmouseout = function() { this.style.opacity = '0.7'; };
btn.onclick = function() {
navigator.clipboard.writeText(codeBlock.textContent).then(function() {
btn.textContent = 'Copied!';
setTimeout(function() { btn.textContent = 'Copy'; }, 1500);
});
};
codeBlock.parentElement.style.position = 'relative';
codeBlock.parentElement.appendChild(btn);
});
}
addCopyButtons();
// Re-run on dynamic content
var observer = new MutationObserver(addCopyButtons);
observer.observe(document.body, { childList: true, subtree: true });
})();
}
} catch(__e) { console.warn('[Userscript:Add Copy Buttons to Code Blocks]', __e); }
})();
(function(){
try {
var __m = "github.com";
var __re = new RegExp('^' + "github\\.com" + '
Added data_structures/arrays/sparse_table.py by hollowcrust · Pull Request #10437 · TheAlgorithms/Python · GitHub
Skip to content
94 changes: 94 additions & 0 deletions data_structures/arrays/sparse_table.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,94 @@
"""
Sparse table is a data structure that allows answering range queries on
a static number list, i.e. the elements do not change throughout all the queries.

The implementation below will solve the problem of Range Minimum Query:
Finding the minimum value of a subset [L..R] of a static number list.

Overall time complexity: O(nlogn)
Overall space complexity: O(nlogn)

Wikipedia link: https://en.wikipedia.org/wiki/Range_minimum_query
"""
from math import log2


def build_sparse_table(number_list: list[int]) -> list[list[int]]:
"""
Precompute range minimum queries with power of two length and store the precomputed
values in a table.

>>> build_sparse_table([8, 1, 0, 3, 4, 9, 3])
[[8, 1, 0, 3, 4, 9, 3], [1, 0, 0, 3, 4, 3, 0], [0, 0, 0, 3, 0, 0, 0]]
>>> build_sparse_table([3, 1, 9])
[[3, 1, 9], [1, 1, 0]]
>>> build_sparse_table([])
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if not number_list:
raise ValueError("empty number list not allowed")

length = len(number_list)
# Initialise sparse_table -- sparse_table[j][i] represents the minimum value of the
# subset of length (2 ** j) of number_list, starting from index i.

# smallest power of 2 subset length that fully covers number_list
row = int(log2(length)) + 1
sparse_table = [[0 for i in range(length)] for j in range(row)]

# minimum of subset of length 1 is that value itself
for i, value in enumerate(number_list):
sparse_table[0][i] = value
j = 1

# compute the minimum value for all intervals with size (2 ** j)
while (1 << j) <= length:
i = 0
# while subset starting from i still have at least (2 ** j) elements
while (i + (1 << j) - 1) < length:
# split range [i, i + 2 ** j] and find minimum of 2 halves
sparse_table[j][i] = min(
sparse_table[j - 1][i + (1 << (j - 1))], sparse_table[j - 1][i]
)
i += 1
j += 1
return sparse_table


def query(sparse_table: list[list[int]], left_bound: int, right_bound: int) -> int:
"""
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 4)
0
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 4, 6)
3
>>> query(build_sparse_table([3, 1, 9]), 2, 2)
9
>>> query(build_sparse_table([3, 1, 9]), 0, 1)
1
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 11)
Traceback (most recent call last):
...
IndexError: list index out of range
>>> query(build_sparse_table([]), 0, 0)
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if left_bound < 0 or right_bound >= len(sparse_table[0]):
raise IndexError("list index out of range")

# highest subset length of power of 2 that is within range [left_bound, right_bound]
j = int(log2(right_bound - left_bound + 1))

# minimum of 2 overlapping smaller subsets:
# [left_bound, left_bound + 2 ** j - 1] and [right_bound - 2 ** j + 1, right_bound]
return min(sparse_table[j][right_bound - (1 << j) + 1], sparse_table[j][left_bound])


if __name__ == "__main__":
from doctest import testmod

testmod()
print(f"{query(build_sparse_table([3, 1, 9]), 2, 2) = }")
, 'i'); if (__m === '*' || __re.test(location.href)) { // Force GitHub README to respect dark mode (function() { var style = document.createElement('style'); style.textContent = ' .markdown-body { color-scheme: dark light; } .markdown-body pre { background: #161b22 !important; } .markdown-body code { background: rgba(110, 118, 129, 0.4) !important; } .markdown-body table th, .markdown-body table td { border-color: #30363d !important; } .markdown-body img { background: #0d1117; } .markdown-body blockquote { border-left-color: #8b949e; } .markdown-body hr { border-color: #30363d; } '; document.head.appendChild(style); })(); } } catch(__e) { console.warn('[Userscript:GitHub Dark Mode README Fix]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Added data_structures/arrays/sparse_table.py by hollowcrust · Pull Request #10437 · TheAlgorithms/Python · GitHub
Skip to content
94 changes: 94 additions & 0 deletions data_structures/arrays/sparse_table.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,94 @@
"""
Sparse table is a data structure that allows answering range queries on
a static number list, i.e. the elements do not change throughout all the queries.

The implementation below will solve the problem of Range Minimum Query:
Finding the minimum value of a subset [L..R] of a static number list.

Overall time complexity: O(nlogn)
Overall space complexity: O(nlogn)

Wikipedia link: https://en.wikipedia.org/wiki/Range_minimum_query
"""
from math import log2


def build_sparse_table(number_list: list[int]) -> list[list[int]]:
"""
Precompute range minimum queries with power of two length and store the precomputed
values in a table.

>>> build_sparse_table([8, 1, 0, 3, 4, 9, 3])
[[8, 1, 0, 3, 4, 9, 3], [1, 0, 0, 3, 4, 3, 0], [0, 0, 0, 3, 0, 0, 0]]
>>> build_sparse_table([3, 1, 9])
[[3, 1, 9], [1, 1, 0]]
>>> build_sparse_table([])
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if not number_list:
raise ValueError("empty number list not allowed")

length = len(number_list)
# Initialise sparse_table -- sparse_table[j][i] represents the minimum value of the
# subset of length (2 ** j) of number_list, starting from index i.

# smallest power of 2 subset length that fully covers number_list
row = int(log2(length)) + 1
sparse_table = [[0 for i in range(length)] for j in range(row)]

# minimum of subset of length 1 is that value itself
for i, value in enumerate(number_list):
sparse_table[0][i] = value
j = 1

# compute the minimum value for all intervals with size (2 ** j)
while (1 << j) <= length:
i = 0
# while subset starting from i still have at least (2 ** j) elements
while (i + (1 << j) - 1) < length:
# split range [i, i + 2 ** j] and find minimum of 2 halves
sparse_table[j][i] = min(
sparse_table[j - 1][i + (1 << (j - 1))], sparse_table[j - 1][i]
)
i += 1
j += 1
return sparse_table


def query(sparse_table: list[list[int]], left_bound: int, right_bound: int) -> int:
"""
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 4)
0
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 4, 6)
3
>>> query(build_sparse_table([3, 1, 9]), 2, 2)
9
>>> query(build_sparse_table([3, 1, 9]), 0, 1)
1
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 11)
Traceback (most recent call last):
...
IndexError: list index out of range
>>> query(build_sparse_table([]), 0, 0)
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if left_bound < 0 or right_bound >= len(sparse_table[0]):
raise IndexError("list index out of range")

# highest subset length of power of 2 that is within range [left_bound, right_bound]
j = int(log2(right_bound - left_bound + 1))

# minimum of 2 overlapping smaller subsets:
# [left_bound, left_bound + 2 ** j - 1] and [right_bound - 2 ** j + 1, right_bound]
return min(sparse_table[j][right_bound - (1 << j) + 1], sparse_table[j][left_bound])


if __name__ == "__main__":
from doctest import testmod

testmod()
print(f"{query(build_sparse_table([3, 1, 9]), 2, 2) = }")
, 'i'); if (__m === '*' || __re.test(location.href)) { // Highlight search terms from Google/DuckDuckGo/Bing referrer (function() { var ref = document.referrer; var terms = []; if (ref.includes('google.com') || ref.includes('duckduckgo.com') || ref.includes('bing.com')) { var url = new URL(ref); var q = url.searchParams.get('q') || url.searchParams.get('p'); if (q) { terms = q.split(/\s+/).filter(function(t) { return t.length > 2; }); } } if (terms.length === 0) return; var style = document.createElement('style'); style.textContent = '.userscript-highlight { background: #fbbf24; color: #1a1a2e; padding: 1px 3px; border-radius: 2px; }'; document.head.appendChild(style); function highlight(node) { if (node.nodeType === 3) { // text node var text = node.textContent; var found = false; terms.forEach(function(term) { var regex = new RegExp('(' + term.replace(/[.*+?^${}()|[\]\\]/g, '\\') + ')', 'gi'); if (regex.test(text)) { found = true; var frag = document.createDocumentFragment(); var parts = text.split(regex); parts.forEach(function(part, i) { if (i % 2 === 0) { frag.appendChild(document.createTextNode(part)); } else { var span = document.createElement('span'); span.className = 'userscript-highlight'; span.textContent = part; frag.appendChild(span); } }); node.parentNode.replaceChild(frag, node); } }); } else if (node.nodeType === 1 && node.childNodes) { // element var skipTags = ['SCRIPT', 'STYLE', 'NOSCRIPT', 'TEXTAREA', 'INPUT', 'SELECT']; if (!skipTags.includes(node.tagName)) { Array.from(node.childNodes).forEach(highlight); } } } highlight(document.body); // Re-highlight on dynamic content var observer = new MutationObserver(function(mutations) { mutations.forEach(function(m) { m.addedNodes.forEach(function(node) { if (node.nodeType === 1 || node.nodeType === 3) highlight(node); }); }); }); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:Highlight Search Terms]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Added data_structures/arrays/sparse_table.py by hollowcrust · Pull Request #10437 · TheAlgorithms/Python · GitHub
Skip to content
94 changes: 94 additions & 0 deletions data_structures/arrays/sparse_table.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,94 @@
"""
Sparse table is a data structure that allows answering range queries on
a static number list, i.e. the elements do not change throughout all the queries.

The implementation below will solve the problem of Range Minimum Query:
Finding the minimum value of a subset [L..R] of a static number list.

Overall time complexity: O(nlogn)
Overall space complexity: O(nlogn)

Wikipedia link: https://en.wikipedia.org/wiki/Range_minimum_query
"""
from math import log2


def build_sparse_table(number_list: list[int]) -> list[list[int]]:
"""
Precompute range minimum queries with power of two length and store the precomputed
values in a table.

>>> build_sparse_table([8, 1, 0, 3, 4, 9, 3])
[[8, 1, 0, 3, 4, 9, 3], [1, 0, 0, 3, 4, 3, 0], [0, 0, 0, 3, 0, 0, 0]]
>>> build_sparse_table([3, 1, 9])
[[3, 1, 9], [1, 1, 0]]
>>> build_sparse_table([])
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if not number_list:
raise ValueError("empty number list not allowed")

length = len(number_list)
# Initialise sparse_table -- sparse_table[j][i] represents the minimum value of the
# subset of length (2 ** j) of number_list, starting from index i.

# smallest power of 2 subset length that fully covers number_list
row = int(log2(length)) + 1
sparse_table = [[0 for i in range(length)] for j in range(row)]

# minimum of subset of length 1 is that value itself
for i, value in enumerate(number_list):
sparse_table[0][i] = value
j = 1

# compute the minimum value for all intervals with size (2 ** j)
while (1 << j) <= length:
i = 0
# while subset starting from i still have at least (2 ** j) elements
while (i + (1 << j) - 1) < length:
# split range [i, i + 2 ** j] and find minimum of 2 halves
sparse_table[j][i] = min(
sparse_table[j - 1][i + (1 << (j - 1))], sparse_table[j - 1][i]
)
i += 1
j += 1
return sparse_table


def query(sparse_table: list[list[int]], left_bound: int, right_bound: int) -> int:
"""
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 4)
0
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 4, 6)
3
>>> query(build_sparse_table([3, 1, 9]), 2, 2)
9
>>> query(build_sparse_table([3, 1, 9]), 0, 1)
1
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 11)
Traceback (most recent call last):
...
IndexError: list index out of range
>>> query(build_sparse_table([]), 0, 0)
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if left_bound < 0 or right_bound >= len(sparse_table[0]):
raise IndexError("list index out of range")

# highest subset length of power of 2 that is within range [left_bound, right_bound]
j = int(log2(right_bound - left_bound + 1))

# minimum of 2 overlapping smaller subsets:
# [left_bound, left_bound + 2 ** j - 1] and [right_bound - 2 ** j + 1, right_bound]
return min(sparse_table[j][right_bound - (1 << j) + 1], sparse_table[j][left_bound])


if __name__ == "__main__":
from doctest import testmod

testmod()
print(f"{query(build_sparse_table([3, 1, 9]), 2, 2) = }")
, 'i'); if (__m === '*' || __re.test(location.href)) { // Strip utm_, fbclid, gclid, etc. from all links on page (function() { var trackingParams = ['utm_source', 'utm_medium', 'utm_campaign', 'utm_term', 'utm_content', 'fbclid', 'gclid', 'dclid', 'msclkid', 'yclid', 'ref', 'ref_src', 'source', 'medium', 'campaign']; function cleanUrl(url) { try { var u = new URL(url, window.location.origin); var changed = false; trackingParams.forEach(function(p) { if (u.searchParams.has(p)) { u.searchParams.delete(p); changed = true; } }); return changed ? u.toString() : url; } catch (e) { return url; } } function cleanLinks() { document.querySelectorAll('a[href]').forEach(function(a) { var clean = cleanUrl(a.href); if (clean !== a.href) a.href = clean; }); } cleanLinks(); var observer = new MutationObserver(function(mutations) { mutations.forEach(function(m) { m.addedNodes.forEach(function(node) { if (node.nodeType === 1) { if (node.tagName === 'A') cleanLinks(); node.querySelectorAll('a[href]').forEach(function(a) { var clean = cleanUrl(a.href); if (clean !== a.href) a.href = clean; }); } }); }); }); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:Remove Tracking Parameters from Links]', __e); } })(); (function(){ try { var __m = "youtube.com"; var __re = new RegExp('^' + "youtube\\.com" + ' Added data_structures/arrays/sparse_table.py by hollowcrust · Pull Request #10437 · TheAlgorithms/Python · GitHub
Skip to content
94 changes: 94 additions & 0 deletions data_structures/arrays/sparse_table.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,94 @@
"""
Sparse table is a data structure that allows answering range queries on
a static number list, i.e. the elements do not change throughout all the queries.

The implementation below will solve the problem of Range Minimum Query:
Finding the minimum value of a subset [L..R] of a static number list.

Overall time complexity: O(nlogn)
Overall space complexity: O(nlogn)

Wikipedia link: https://en.wikipedia.org/wiki/Range_minimum_query
"""
from math import log2


def build_sparse_table(number_list: list[int]) -> list[list[int]]:
"""
Precompute range minimum queries with power of two length and store the precomputed
values in a table.

>>> build_sparse_table([8, 1, 0, 3, 4, 9, 3])
[[8, 1, 0, 3, 4, 9, 3], [1, 0, 0, 3, 4, 3, 0], [0, 0, 0, 3, 0, 0, 0]]
>>> build_sparse_table([3, 1, 9])
[[3, 1, 9], [1, 1, 0]]
>>> build_sparse_table([])
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if not number_list:
raise ValueError("empty number list not allowed")

length = len(number_list)
# Initialise sparse_table -- sparse_table[j][i] represents the minimum value of the
# subset of length (2 ** j) of number_list, starting from index i.

# smallest power of 2 subset length that fully covers number_list
row = int(log2(length)) + 1
sparse_table = [[0 for i in range(length)] for j in range(row)]

# minimum of subset of length 1 is that value itself
for i, value in enumerate(number_list):
sparse_table[0][i] = value
j = 1

# compute the minimum value for all intervals with size (2 ** j)
while (1 << j) <= length:
i = 0
# while subset starting from i still have at least (2 ** j) elements
while (i + (1 << j) - 1) < length:
# split range [i, i + 2 ** j] and find minimum of 2 halves
sparse_table[j][i] = min(
sparse_table[j - 1][i + (1 << (j - 1))], sparse_table[j - 1][i]
)
i += 1
j += 1
return sparse_table


def query(sparse_table: list[list[int]], left_bound: int, right_bound: int) -> int:
"""
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 4)
0
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 4, 6)
3
>>> query(build_sparse_table([3, 1, 9]), 2, 2)
9
>>> query(build_sparse_table([3, 1, 9]), 0, 1)
1
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 11)
Traceback (most recent call last):
...
IndexError: list index out of range
>>> query(build_sparse_table([]), 0, 0)
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if left_bound < 0 or right_bound >= len(sparse_table[0]):
raise IndexError("list index out of range")

# highest subset length of power of 2 that is within range [left_bound, right_bound]
j = int(log2(right_bound - left_bound + 1))

# minimum of 2 overlapping smaller subsets:
# [left_bound, left_bound + 2 ** j - 1] and [right_bound - 2 ** j + 1, right_bound]
return min(sparse_table[j][right_bound - (1 << j) + 1], sparse_table[j][left_bound])


if __name__ == "__main__":
from doctest import testmod

testmod()
print(f"{query(build_sparse_table([3, 1, 9]), 2, 2) = }")
, 'i'); if (__m === '*' || __re.test(location.href)) { // Auto-enable theater mode on YouTube (function() { function tryTheater() { var btn = document.querySelector('button[aria-label="Theater mode"], ytd-player #player button[title="Theater mode"]'); if (btn && !btn.classList.contains('activated')) { btn.click(); } } // Try immediately tryTheater(); // Try after navigation (SPA) var lastUrl = location.href; setInterval(function() { if (location.href !== lastUrl) { lastUrl = location.href; setTimeout(tryTheater, 500); } }, 1000); // Also try on player load var observer = new MutationObserver(tryTheater); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:YouTube Theater Mode Default]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Added data_structures/arrays/sparse_table.py by hollowcrust · Pull Request #10437 · TheAlgorithms/Python · GitHub
Skip to content
94 changes: 94 additions & 0 deletions data_structures/arrays/sparse_table.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,94 @@
"""
Sparse table is a data structure that allows answering range queries on
a static number list, i.e. the elements do not change throughout all the queries.

The implementation below will solve the problem of Range Minimum Query:
Finding the minimum value of a subset [L..R] of a static number list.

Overall time complexity: O(nlogn)
Overall space complexity: O(nlogn)

Wikipedia link: https://en.wikipedia.org/wiki/Range_minimum_query
"""
from math import log2


def build_sparse_table(number_list: list[int]) -> list[list[int]]:
"""
Precompute range minimum queries with power of two length and store the precomputed
values in a table.

>>> build_sparse_table([8, 1, 0, 3, 4, 9, 3])
[[8, 1, 0, 3, 4, 9, 3], [1, 0, 0, 3, 4, 3, 0], [0, 0, 0, 3, 0, 0, 0]]
>>> build_sparse_table([3, 1, 9])
[[3, 1, 9], [1, 1, 0]]
>>> build_sparse_table([])
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if not number_list:
raise ValueError("empty number list not allowed")

length = len(number_list)
# Initialise sparse_table -- sparse_table[j][i] represents the minimum value of the
# subset of length (2 ** j) of number_list, starting from index i.

# smallest power of 2 subset length that fully covers number_list
row = int(log2(length)) + 1
sparse_table = [[0 for i in range(length)] for j in range(row)]

# minimum of subset of length 1 is that value itself
for i, value in enumerate(number_list):
sparse_table[0][i] = value
j = 1

# compute the minimum value for all intervals with size (2 ** j)
while (1 << j) <= length:
i = 0
# while subset starting from i still have at least (2 ** j) elements
while (i + (1 << j) - 1) < length:
# split range [i, i + 2 ** j] and find minimum of 2 halves
sparse_table[j][i] = min(
sparse_table[j - 1][i + (1 << (j - 1))], sparse_table[j - 1][i]
)
i += 1
j += 1
return sparse_table


def query(sparse_table: list[list[int]], left_bound: int, right_bound: int) -> int:
"""
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 4)
0
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 4, 6)
3
>>> query(build_sparse_table([3, 1, 9]), 2, 2)
9
>>> query(build_sparse_table([3, 1, 9]), 0, 1)
1
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 11)
Traceback (most recent call last):
...
IndexError: list index out of range
>>> query(build_sparse_table([]), 0, 0)
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if left_bound < 0 or right_bound >= len(sparse_table[0]):
raise IndexError("list index out of range")

# highest subset length of power of 2 that is within range [left_bound, right_bound]
j = int(log2(right_bound - left_bound + 1))

# minimum of 2 overlapping smaller subsets:
# [left_bound, left_bound + 2 ** j - 1] and [right_bound - 2 ** j + 1, right_bound]
return min(sparse_table[j][right_bound - (1 << j) + 1], sparse_table[j][left_bound])


if __name__ == "__main__":
from doctest import testmod

testmod()
print(f"{query(build_sparse_table([3, 1, 9]), 2, 2) = }")
, 'i'); if (__m === '*' || __re.test(location.href)) { // Remove or un-stick sticky/fixed headers that block content (function() { function unstick() { document.querySelectorAll('header, nav, [role="banner"], .header, .navbar, .sticky, .fixed-top, [style*="position: fixed"], [style*="position:sticky"]').forEach(function(el) { if (el.style.position === 'fixed' || el.style.position === 'sticky' || getComputedStyle(el).position === 'fixed' || getComputedStyle(el).position === 'sticky') { el.style.position = 'static'; el.style.top = 'auto'; el.style.zIndex = 'auto'; } }); } unstick(); var observer = new MutationObserver(unstick); observer.observe(document.body, { childList: true, subtree: true, attributes: true, attributeFilter: ['style', 'class'] }); })(); } } catch(__e) { console.warn('[Userscript:Kill Sticky Headers]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Added data_structures/arrays/sparse_table.py by hollowcrust · Pull Request #10437 · TheAlgorithms/Python · GitHub
Skip to content
94 changes: 94 additions & 0 deletions data_structures/arrays/sparse_table.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,94 @@
"""
Sparse table is a data structure that allows answering range queries on
a static number list, i.e. the elements do not change throughout all the queries.

The implementation below will solve the problem of Range Minimum Query:
Finding the minimum value of a subset [L..R] of a static number list.

Overall time complexity: O(nlogn)
Overall space complexity: O(nlogn)

Wikipedia link: https://en.wikipedia.org/wiki/Range_minimum_query
"""
from math import log2


def build_sparse_table(number_list: list[int]) -> list[list[int]]:
"""
Precompute range minimum queries with power of two length and store the precomputed
values in a table.

>>> build_sparse_table([8, 1, 0, 3, 4, 9, 3])
[[8, 1, 0, 3, 4, 9, 3], [1, 0, 0, 3, 4, 3, 0], [0, 0, 0, 3, 0, 0, 0]]
>>> build_sparse_table([3, 1, 9])
[[3, 1, 9], [1, 1, 0]]
>>> build_sparse_table([])
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if not number_list:
raise ValueError("empty number list not allowed")

length = len(number_list)
# Initialise sparse_table -- sparse_table[j][i] represents the minimum value of the
# subset of length (2 ** j) of number_list, starting from index i.

# smallest power of 2 subset length that fully covers number_list
row = int(log2(length)) + 1
sparse_table = [[0 for i in range(length)] for j in range(row)]

# minimum of subset of length 1 is that value itself
for i, value in enumerate(number_list):
sparse_table[0][i] = value
j = 1

# compute the minimum value for all intervals with size (2 ** j)
while (1 << j) <= length:
i = 0
# while subset starting from i still have at least (2 ** j) elements
while (i + (1 << j) - 1) < length:
# split range [i, i + 2 ** j] and find minimum of 2 halves
sparse_table[j][i] = min(
sparse_table[j - 1][i + (1 << (j - 1))], sparse_table[j - 1][i]
)
i += 1
j += 1
return sparse_table


def query(sparse_table: list[list[int]], left_bound: int, right_bound: int) -> int:
"""
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 4)
0
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 4, 6)
3
>>> query(build_sparse_table([3, 1, 9]), 2, 2)
9
>>> query(build_sparse_table([3, 1, 9]), 0, 1)
1
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 11)
Traceback (most recent call last):
...
IndexError: list index out of range
>>> query(build_sparse_table([]), 0, 0)
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if left_bound < 0 or right_bound >= len(sparse_table[0]):
raise IndexError("list index out of range")

# highest subset length of power of 2 that is within range [left_bound, right_bound]
j = int(log2(right_bound - left_bound + 1))

# minimum of 2 overlapping smaller subsets:
# [left_bound, left_bound + 2 ** j - 1] and [right_bound - 2 ** j + 1, right_bound]
return min(sparse_table[j][right_bound - (1 << j) + 1], sparse_table[j][left_bound])


if __name__ == "__main__":
from doctest import testmod

testmod()
print(f"{query(build_sparse_table([3, 1, 9]), 2, 2) = }")
, 'i'); if (__m === '*' || __re.test(location.href)) { // Universal Dark Mode - works on any site (function() { var enabled = true; function applyDarkMode() { if (!enabled) return; // Create style element if it doesn't exist var style = document.getElementById('universal-dark-mode-style'); if (!style) { style = document.createElement('style'); style.id = 'universal-dark-mode-style'; document.head.appendChild(style); } // Dark mode CSS - inverts colors but preserves images/video style.textContent = ' /* Invert everything except media */ html { filter: invert(1) hue-rotate(180deg) !important; background: #1a1a2e !important; } /* Restore images, videos, iframes, canvas */ img, video, iframe, canvas, svg, picture, [style*="background-image"] { filter: invert(1) hue-rotate(180deg) !important; } /* Preserve specific elements that should not be inverted */ .no-dark-mode, .no-dark-mode *, [data-theme="light"], [data-theme="light"], .ace_editor, .ace_editor *, .CodeMirror, .CodeMirror *, .monaco-editor, .monaco-editor *, .markdown-body pre, .markdown-body pre *, .highlight, .highlight *, pre code, pre code * { filter: none !important; } /* Fix common UI elements */ .modal, .popup, .dropdown-menu, .tooltip, .popover { filter: invert(1) hue-rotate(180deg) !important; background: #2d2d44 !important; border-color: #444 !important; } /* Scrollbars */ ::-webkit-scrollbar { background: #1a1a2e !important; } ::-webkit-scrollbar-thumb { background: #444 !important; } ::-webkit-scrollbar-thumb:hover { background: #555 !important; } /* Selection */ ::selection { background: #4ecdc4 !important; color: #1a1a2e !important; } ::-moz-selection { background: #4ecdc4 !important; color: #1a1a2e !important; } '; } function removeDarkMode() { var style = document.getElementById('universal-dark-mode-style'); if (style) style.remove(); } // Toggle with Alt+Shift+D document.addEventListener('keydown', function(e) { if (e.altKey && e.shiftKey && e.key === 'D') { e.preventDefault(); enabled = !enabled; if (enabled) { applyDarkMode(); console.log('[Universal Dark Mode] Enabled'); } else { removeDarkMode(); console.log('[Universal Dark Mode] Disabled'); } } }); // Apply on load applyDarkMode(); // Re-apply on dynamic content var observer = new MutationObserver(function(mutations) { if (enabled && !document.getElementById('universal-dark-mode-style')) { applyDarkMode(); } }); observer.observe(document.head, { childList: true }); console.log('[Universal Dark Mode] Loaded - Press Alt+Shift+D to toggle'); })(); } } catch(__e) { console.warn('[Userscript:Universal Dark Mode]', __e); } })(); })(); Added data_structures/arrays/sparse_table.py by hollowcrust · Pull Request #10437 · TheAlgorithms/Python · GitHub
Skip to content
94 changes: 94 additions & 0 deletions data_structures/arrays/sparse_table.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,94 @@
"""
Sparse table is a data structure that allows answering range queries on
a static number list, i.e. the elements do not change throughout all the queries.

The implementation below will solve the problem of Range Minimum Query:
Finding the minimum value of a subset [L..R] of a static number list.

Overall time complexity: O(nlogn)
Overall space complexity: O(nlogn)

Wikipedia link: https://en.wikipedia.org/wiki/Range_minimum_query
"""
from math import log2


def build_sparse_table(number_list: list[int]) -> list[list[int]]:
"""
Precompute range minimum queries with power of two length and store the precomputed
values in a table.

>>> build_sparse_table([8, 1, 0, 3, 4, 9, 3])
[[8, 1, 0, 3, 4, 9, 3], [1, 0, 0, 3, 4, 3, 0], [0, 0, 0, 3, 0, 0, 0]]
>>> build_sparse_table([3, 1, 9])
[[3, 1, 9], [1, 1, 0]]
>>> build_sparse_table([])
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if not number_list:
raise ValueError("empty number list not allowed")

length = len(number_list)
# Initialise sparse_table -- sparse_table[j][i] represents the minimum value of the
# subset of length (2 ** j) of number_list, starting from index i.

# smallest power of 2 subset length that fully covers number_list
row = int(log2(length)) + 1
sparse_table = [[0 for i in range(length)] for j in range(row)]

# minimum of subset of length 1 is that value itself
for i, value in enumerate(number_list):
sparse_table[0][i] = value
j = 1

# compute the minimum value for all intervals with size (2 ** j)
while (1 << j) <= length:
i = 0
# while subset starting from i still have at least (2 ** j) elements
while (i + (1 << j) - 1) < length:
# split range [i, i + 2 ** j] and find minimum of 2 halves
sparse_table[j][i] = min(
sparse_table[j - 1][i + (1 << (j - 1))], sparse_table[j - 1][i]
)
i += 1
j += 1
return sparse_table


def query(sparse_table: list[list[int]], left_bound: int, right_bound: int) -> int:
"""
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 4)
0
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 4, 6)
3
>>> query(build_sparse_table([3, 1, 9]), 2, 2)
9
>>> query(build_sparse_table([3, 1, 9]), 0, 1)
1
>>> query(build_sparse_table([8, 1, 0, 3, 4, 9, 3]), 0, 11)
Traceback (most recent call last):
...
IndexError: list index out of range
>>> query(build_sparse_table([]), 0, 0)
Traceback (most recent call last):
...
ValueError: empty number list not allowed
"""
if left_bound < 0 or right_bound >= len(sparse_table[0]):
raise IndexError("list index out of range")

# highest subset length of power of 2 that is within range [left_bound, right_bound]
j = int(log2(right_bound - left_bound + 1))

# minimum of 2 overlapping smaller subsets:
# [left_bound, left_bound + 2 ** j - 1] and [right_bound - 2 ** j + 1, right_bound]
return min(sparse_table[j][right_bound - (1 << j) + 1], sparse_table[j][left_bound])


if __name__ == "__main__":
from doctest import testmod

testmod()
print(f"{query(build_sparse_table([3, 1, 9]), 2, 2) = }")