rename and add doctest

[realDuYuanChao]

@cclauss

[cclauss]

This file is out of sync with master. There are already doctests on this file:
https://github.com/TheAlgorithms/Python/blob/master/maths/find_max.py#L6

[realDuYuanChao]

@cclauss Please review again!

[cclauss]

Please write a https://docs.python.org/3/library/timeit.html that proves that the new implementation is faster than the current implementation. My bet is that the function call and slice overhead means that it is not.

[realDuYuanChao]

Please write a https://docs.python.org/3/library/timeit.html that proves that the new implementation is faster than the current implementation. My bet is that the function call and slice overhead means that it is not.

Did you mean below code implementation is slower ?

max_num=nums[0]
foriinrange(1, len(nums)):
ifnums[i] >max_num:
max_num=nums[i]

[cclauss]

Not sure but that is my suspicion but a timeit test can tell us for sure.

[realDuYuanChao]

After I tested using

deffind_max(nums):
max_num=nums[0]
foriinrange(1, len(nums)):
ifnums[i] >max_num:
max_num=nums[i]
returnmax_numprint(timeit.timeit("find_max([2, 4, 9, 7, 19, 94, 5])", setup="from __main__ import find_max", number=10000))
time: 0.022231400000000002

deffind_max(nums):
max=nums[0]
forxinnums:
ifx>max:
max=xreturnmaxprint(timeit.timeit("find_max([2, 4, 9, 7, 19, 94, 5])", setup="from __main__ import find_max", number=10000))
time: 0.007430200000000005

From the result, You are right. Thanks

[cclauss]

This is awesome work. I think we should fill this file with as many different implementations of find_max() as we can think of with timeit tests for each one in an effort to find that fastest pure Python implementation.

How does print(timeit.timeit("max([2, 4, 9, 7, 19, 94, 5])", number=10000)) perform using the Python builtin?

[realDuYuanChao]

print(timeit.timeit("max([2, 4, 9, 7, 19, 94, 5])", number=10000))

0.004652999999999997 , Very fast

[cclauss]

Let's use the same tests data as find_max.py uses.

[realDuYuanChao]

Updated. Please review again

[cclauss]

Awesome work! Thanks for your persistence.