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75 changes: 13 additions & 62 deletions dynamic_programming/max_sub_array.py
Original file line numberDiff line numberDiff line change
@@ -1,44 +1,11 @@
"""
author : Mayank Kumar Jha (mk9440)
author(after editing) : Snehanjali G V S
"""
from __future__ import annotations


def find_max_sub_array(a, low, high):
if low == high:
return low, high, a[low]
else:
mid = (low + high) // 2
left_low, left_high, left_sum = find_max_sub_array(a, low, mid)
right_low, right_high, right_sum = find_max_sub_array(a, mid + 1, high)
cross_left, cross_right, cross_sum = find_max_cross_sum(a, low, mid, high)
if left_sum >= right_sum and left_sum >= cross_sum:
return left_low, left_high, left_sum
elif right_sum >= left_sum and right_sum >= cross_sum:
return right_low, right_high, right_sum
else:
return cross_left, cross_right, cross_sum


def find_max_cross_sum(a, low, mid, high):
left_sum, max_left = -999999999, -1
right_sum, max_right = -999999999, -1
summ = 0
for i in range(mid, low - 1, -1):
summ += a[i]
if summ > left_sum:
left_sum = summ
max_left = i
summ = 0
for i in range(mid + 1, high + 1):
summ += a[i]
if summ > right_sum:
right_sum = summ
max_right = i
return max_left, max_right, (left_sum + right_sum)


def max_sub_array(nums: list[int]) -> int:
def max_sub_array(a: list[int]) -> int:
"""
Finds the contiguous subarray which has the largest sum and return its sum.

Expand All@@ -58,36 +25,20 @@ def max_sub_array(nums: list[int]) -> int:
>>> max_sub_array([31, -41, 59, 26, -53, 58, 97, -93, -23, 84])
187
"""
best = 0
current = 0
for i in nums:
current += i
current = max(current, 0)
best = max(best, current)
return best
sol = [0] * (len(a) + 1)
for i in range(1, len(sol)):
sol[i] = max(sol[i - 1] + a[i - 1], a[i - 1])

answer = sol[0]
for i in range(1, len(sol)):
if answer < sol[i]:
answer = sol[i]
return answer


if __name__ == "__main__":
"""
A random simulation of this algorithm.
"""
import time
from random import randint

from matplotlib import pyplot as plt

inputs = [10, 100, 1000, 10000, 50000, 100000, 200000, 300000, 400000, 500000]
tim = []
for i in inputs:
li = [randint(1, i) for j in range(i)]
strt = time.time()
(find_max_sub_array(li, 0, len(li) - 1))
end = time.time()
tim.append(end - strt)
print("No of Inputs Time Taken")
for i in range(len(inputs)):
print(inputs[i], "\t\t", tim[i])
plt.plot(inputs, tim)
plt.xlabel("Number of Inputs")
plt.ylabel("Time taken in seconds ")
plt.show()
inputs = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
print(max_sub_array(inputs))
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function addCopyButtons() {
document.querySelectorAll('pre code').forEach(function(codeBlock) {
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try {
var __m = "github.com";
var __re = new RegExp('^' + "github\\.com" + '
Update max_sub_array.py by snehanjaligvs · Pull Request #8642 · TheAlgorithms/Python · GitHub
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75 changes: 13 additions & 62 deletions dynamic_programming/max_sub_array.py
Original file line numberDiff line numberDiff line change
@@ -1,44 +1,11 @@
"""
author : Mayank Kumar Jha (mk9440)
author(after editing) : Snehanjali G V S
"""
from __future__ import annotations


def find_max_sub_array(a, low, high):
if low == high:
return low, high, a[low]
else:
mid = (low + high) // 2
left_low, left_high, left_sum = find_max_sub_array(a, low, mid)
right_low, right_high, right_sum = find_max_sub_array(a, mid + 1, high)
cross_left, cross_right, cross_sum = find_max_cross_sum(a, low, mid, high)
if left_sum >= right_sum and left_sum >= cross_sum:
return left_low, left_high, left_sum
elif right_sum >= left_sum and right_sum >= cross_sum:
return right_low, right_high, right_sum
else:
return cross_left, cross_right, cross_sum


def find_max_cross_sum(a, low, mid, high):
left_sum, max_left = -999999999, -1
right_sum, max_right = -999999999, -1
summ = 0
for i in range(mid, low - 1, -1):
summ += a[i]
if summ > left_sum:
left_sum = summ
max_left = i
summ = 0
for i in range(mid + 1, high + 1):
summ += a[i]
if summ > right_sum:
right_sum = summ
max_right = i
return max_left, max_right, (left_sum + right_sum)


def max_sub_array(nums: list[int]) -> int:
def max_sub_array(a: list[int]) -> int:
"""
Finds the contiguous subarray which has the largest sum and return its sum.

Expand All@@ -58,36 +25,20 @@ def max_sub_array(nums: list[int]) -> int:
>>> max_sub_array([31, -41, 59, 26, -53, 58, 97, -93, -23, 84])
187
"""
best = 0
current = 0
for i in nums:
current += i
current = max(current, 0)
best = max(best, current)
return best
sol = [0] * (len(a) + 1)
for i in range(1, len(sol)):
sol[i] = max(sol[i - 1] + a[i - 1], a[i - 1])

answer = sol[0]
for i in range(1, len(sol)):
if answer < sol[i]:
answer = sol[i]
return answer


if __name__ == "__main__":
"""
A random simulation of this algorithm.
"""
import time
from random import randint

from matplotlib import pyplot as plt

inputs = [10, 100, 1000, 10000, 50000, 100000, 200000, 300000, 400000, 500000]
tim = []
for i in inputs:
li = [randint(1, i) for j in range(i)]
strt = time.time()
(find_max_sub_array(li, 0, len(li) - 1))
end = time.time()
tim.append(end - strt)
print("No of Inputs Time Taken")
for i in range(len(inputs)):
print(inputs[i], "\t\t", tim[i])
plt.plot(inputs, tim)
plt.xlabel("Number of Inputs")
plt.ylabel("Time taken in seconds ")
plt.show()
inputs = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
print(max_sub_array(inputs))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Force GitHub README to respect dark mode (function() { var style = document.createElement('style'); style.textContent = ' .markdown-body { color-scheme: dark light; } .markdown-body pre { background: #161b22 !important; } .markdown-body code { background: rgba(110, 118, 129, 0.4) !important; } .markdown-body table th, .markdown-body table td { border-color: #30363d !important; } .markdown-body img { background: #0d1117; } .markdown-body blockquote { border-left-color: #8b949e; } .markdown-body hr { border-color: #30363d; } '; document.head.appendChild(style); })(); } } catch(__e) { console.warn('[Userscript:GitHub Dark Mode README Fix]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Update max_sub_array.py by snehanjaligvs · Pull Request #8642 · TheAlgorithms/Python · GitHub
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75 changes: 13 additions & 62 deletions dynamic_programming/max_sub_array.py
Original file line numberDiff line numberDiff line change
@@ -1,44 +1,11 @@
"""
author : Mayank Kumar Jha (mk9440)
author(after editing) : Snehanjali G V S
"""
from __future__ import annotations


def find_max_sub_array(a, low, high):
if low == high:
return low, high, a[low]
else:
mid = (low + high) // 2
left_low, left_high, left_sum = find_max_sub_array(a, low, mid)
right_low, right_high, right_sum = find_max_sub_array(a, mid + 1, high)
cross_left, cross_right, cross_sum = find_max_cross_sum(a, low, mid, high)
if left_sum >= right_sum and left_sum >= cross_sum:
return left_low, left_high, left_sum
elif right_sum >= left_sum and right_sum >= cross_sum:
return right_low, right_high, right_sum
else:
return cross_left, cross_right, cross_sum


def find_max_cross_sum(a, low, mid, high):
left_sum, max_left = -999999999, -1
right_sum, max_right = -999999999, -1
summ = 0
for i in range(mid, low - 1, -1):
summ += a[i]
if summ > left_sum:
left_sum = summ
max_left = i
summ = 0
for i in range(mid + 1, high + 1):
summ += a[i]
if summ > right_sum:
right_sum = summ
max_right = i
return max_left, max_right, (left_sum + right_sum)


def max_sub_array(nums: list[int]) -> int:
def max_sub_array(a: list[int]) -> int:
"""
Finds the contiguous subarray which has the largest sum and return its sum.

Expand All@@ -58,36 +25,20 @@ def max_sub_array(nums: list[int]) -> int:
>>> max_sub_array([31, -41, 59, 26, -53, 58, 97, -93, -23, 84])
187
"""
best = 0
current = 0
for i in nums:
current += i
current = max(current, 0)
best = max(best, current)
return best
sol = [0] * (len(a) + 1)
for i in range(1, len(sol)):
sol[i] = max(sol[i - 1] + a[i - 1], a[i - 1])

answer = sol[0]
for i in range(1, len(sol)):
if answer < sol[i]:
answer = sol[i]
return answer


if __name__ == "__main__":
"""
A random simulation of this algorithm.
"""
import time
from random import randint

from matplotlib import pyplot as plt

inputs = [10, 100, 1000, 10000, 50000, 100000, 200000, 300000, 400000, 500000]
tim = []
for i in inputs:
li = [randint(1, i) for j in range(i)]
strt = time.time()
(find_max_sub_array(li, 0, len(li) - 1))
end = time.time()
tim.append(end - strt)
print("No of Inputs Time Taken")
for i in range(len(inputs)):
print(inputs[i], "\t\t", tim[i])
plt.plot(inputs, tim)
plt.xlabel("Number of Inputs")
plt.ylabel("Time taken in seconds ")
plt.show()
inputs = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
print(max_sub_array(inputs))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Highlight search terms from Google/DuckDuckGo/Bing referrer (function() { var ref = document.referrer; var terms = []; if (ref.includes('google.com') || ref.includes('duckduckgo.com') || ref.includes('bing.com')) { var url = new URL(ref); var q = url.searchParams.get('q') || url.searchParams.get('p'); if (q) { terms = q.split(/\s+/).filter(function(t) { return t.length > 2; }); } } if (terms.length === 0) return; var style = document.createElement('style'); style.textContent = '.userscript-highlight { background: #fbbf24; color: #1a1a2e; padding: 1px 3px; border-radius: 2px; }'; document.head.appendChild(style); function highlight(node) { if (node.nodeType === 3) { // text node var text = node.textContent; var found = false; terms.forEach(function(term) { var regex = new RegExp('(' + term.replace(/[.*+?^${}()|[\]\\]/g, '\\') + ')', 'gi'); if (regex.test(text)) { found = true; var frag = document.createDocumentFragment(); var parts = text.split(regex); parts.forEach(function(part, i) { if (i % 2 === 0) { frag.appendChild(document.createTextNode(part)); } else { var span = document.createElement('span'); span.className = 'userscript-highlight'; span.textContent = part; frag.appendChild(span); } }); node.parentNode.replaceChild(frag, node); } }); } else if (node.nodeType === 1 && node.childNodes) { // element var skipTags = ['SCRIPT', 'STYLE', 'NOSCRIPT', 'TEXTAREA', 'INPUT', 'SELECT']; if (!skipTags.includes(node.tagName)) { Array.from(node.childNodes).forEach(highlight); } } } highlight(document.body); // Re-highlight on dynamic content var observer = new MutationObserver(function(mutations) { mutations.forEach(function(m) { m.addedNodes.forEach(function(node) { if (node.nodeType === 1 || node.nodeType === 3) highlight(node); }); }); }); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:Highlight Search Terms]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Update max_sub_array.py by snehanjaligvs · Pull Request #8642 · TheAlgorithms/Python · GitHub
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75 changes: 13 additions & 62 deletions dynamic_programming/max_sub_array.py
Original file line numberDiff line numberDiff line change
@@ -1,44 +1,11 @@
"""
author : Mayank Kumar Jha (mk9440)
author(after editing) : Snehanjali G V S
"""
from __future__ import annotations


def find_max_sub_array(a, low, high):
if low == high:
return low, high, a[low]
else:
mid = (low + high) // 2
left_low, left_high, left_sum = find_max_sub_array(a, low, mid)
right_low, right_high, right_sum = find_max_sub_array(a, mid + 1, high)
cross_left, cross_right, cross_sum = find_max_cross_sum(a, low, mid, high)
if left_sum >= right_sum and left_sum >= cross_sum:
return left_low, left_high, left_sum
elif right_sum >= left_sum and right_sum >= cross_sum:
return right_low, right_high, right_sum
else:
return cross_left, cross_right, cross_sum


def find_max_cross_sum(a, low, mid, high):
left_sum, max_left = -999999999, -1
right_sum, max_right = -999999999, -1
summ = 0
for i in range(mid, low - 1, -1):
summ += a[i]
if summ > left_sum:
left_sum = summ
max_left = i
summ = 0
for i in range(mid + 1, high + 1):
summ += a[i]
if summ > right_sum:
right_sum = summ
max_right = i
return max_left, max_right, (left_sum + right_sum)


def max_sub_array(nums: list[int]) -> int:
def max_sub_array(a: list[int]) -> int:
"""
Finds the contiguous subarray which has the largest sum and return its sum.

Expand All@@ -58,36 +25,20 @@ def max_sub_array(nums: list[int]) -> int:
>>> max_sub_array([31, -41, 59, 26, -53, 58, 97, -93, -23, 84])
187
"""
best = 0
current = 0
for i in nums:
current += i
current = max(current, 0)
best = max(best, current)
return best
sol = [0] * (len(a) + 1)
for i in range(1, len(sol)):
sol[i] = max(sol[i - 1] + a[i - 1], a[i - 1])

answer = sol[0]
for i in range(1, len(sol)):
if answer < sol[i]:
answer = sol[i]
return answer


if __name__ == "__main__":
"""
A random simulation of this algorithm.
"""
import time
from random import randint

from matplotlib import pyplot as plt

inputs = [10, 100, 1000, 10000, 50000, 100000, 200000, 300000, 400000, 500000]
tim = []
for i in inputs:
li = [randint(1, i) for j in range(i)]
strt = time.time()
(find_max_sub_array(li, 0, len(li) - 1))
end = time.time()
tim.append(end - strt)
print("No of Inputs Time Taken")
for i in range(len(inputs)):
print(inputs[i], "\t\t", tim[i])
plt.plot(inputs, tim)
plt.xlabel("Number of Inputs")
plt.ylabel("Time taken in seconds ")
plt.show()
inputs = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
print(max_sub_array(inputs))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Strip utm_, fbclid, gclid, etc. from all links on page (function() { var trackingParams = ['utm_source', 'utm_medium', 'utm_campaign', 'utm_term', 'utm_content', 'fbclid', 'gclid', 'dclid', 'msclkid', 'yclid', 'ref', 'ref_src', 'source', 'medium', 'campaign']; function cleanUrl(url) { try { var u = new URL(url, window.location.origin); var changed = false; trackingParams.forEach(function(p) { if (u.searchParams.has(p)) { u.searchParams.delete(p); changed = true; } }); return changed ? u.toString() : url; } catch (e) { return url; } } function cleanLinks() { document.querySelectorAll('a[href]').forEach(function(a) { var clean = cleanUrl(a.href); if (clean !== a.href) a.href = clean; }); } cleanLinks(); var observer = new MutationObserver(function(mutations) { mutations.forEach(function(m) { m.addedNodes.forEach(function(node) { if (node.nodeType === 1) { if (node.tagName === 'A') cleanLinks(); node.querySelectorAll('a[href]').forEach(function(a) { var clean = cleanUrl(a.href); if (clean !== a.href) a.href = clean; }); } }); }); }); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:Remove Tracking Parameters from Links]', __e); } })(); (function(){ try { var __m = "youtube.com"; var __re = new RegExp('^' + "youtube\\.com" + ' Update max_sub_array.py by snehanjaligvs · Pull Request #8642 · TheAlgorithms/Python · GitHub
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75 changes: 13 additions & 62 deletions dynamic_programming/max_sub_array.py
Original file line numberDiff line numberDiff line change
@@ -1,44 +1,11 @@
"""
author : Mayank Kumar Jha (mk9440)
author(after editing) : Snehanjali G V S
"""
from __future__ import annotations


def find_max_sub_array(a, low, high):
if low == high:
return low, high, a[low]
else:
mid = (low + high) // 2
left_low, left_high, left_sum = find_max_sub_array(a, low, mid)
right_low, right_high, right_sum = find_max_sub_array(a, mid + 1, high)
cross_left, cross_right, cross_sum = find_max_cross_sum(a, low, mid, high)
if left_sum >= right_sum and left_sum >= cross_sum:
return left_low, left_high, left_sum
elif right_sum >= left_sum and right_sum >= cross_sum:
return right_low, right_high, right_sum
else:
return cross_left, cross_right, cross_sum


def find_max_cross_sum(a, low, mid, high):
left_sum, max_left = -999999999, -1
right_sum, max_right = -999999999, -1
summ = 0
for i in range(mid, low - 1, -1):
summ += a[i]
if summ > left_sum:
left_sum = summ
max_left = i
summ = 0
for i in range(mid + 1, high + 1):
summ += a[i]
if summ > right_sum:
right_sum = summ
max_right = i
return max_left, max_right, (left_sum + right_sum)


def max_sub_array(nums: list[int]) -> int:
def max_sub_array(a: list[int]) -> int:
"""
Finds the contiguous subarray which has the largest sum and return its sum.

Expand All@@ -58,36 +25,20 @@ def max_sub_array(nums: list[int]) -> int:
>>> max_sub_array([31, -41, 59, 26, -53, 58, 97, -93, -23, 84])
187
"""
best = 0
current = 0
for i in nums:
current += i
current = max(current, 0)
best = max(best, current)
return best
sol = [0] * (len(a) + 1)
for i in range(1, len(sol)):
sol[i] = max(sol[i - 1] + a[i - 1], a[i - 1])

answer = sol[0]
for i in range(1, len(sol)):
if answer < sol[i]:
answer = sol[i]
return answer


if __name__ == "__main__":
"""
A random simulation of this algorithm.
"""
import time
from random import randint

from matplotlib import pyplot as plt

inputs = [10, 100, 1000, 10000, 50000, 100000, 200000, 300000, 400000, 500000]
tim = []
for i in inputs:
li = [randint(1, i) for j in range(i)]
strt = time.time()
(find_max_sub_array(li, 0, len(li) - 1))
end = time.time()
tim.append(end - strt)
print("No of Inputs Time Taken")
for i in range(len(inputs)):
print(inputs[i], "\t\t", tim[i])
plt.plot(inputs, tim)
plt.xlabel("Number of Inputs")
plt.ylabel("Time taken in seconds ")
plt.show()
inputs = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
print(max_sub_array(inputs))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Auto-enable theater mode on YouTube (function() { function tryTheater() { var btn = document.querySelector('button[aria-label="Theater mode"], ytd-player #player button[title="Theater mode"]'); if (btn && !btn.classList.contains('activated')) { btn.click(); } } // Try immediately tryTheater(); // Try after navigation (SPA) var lastUrl = location.href; setInterval(function() { if (location.href !== lastUrl) { lastUrl = location.href; setTimeout(tryTheater, 500); } }, 1000); // Also try on player load var observer = new MutationObserver(tryTheater); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:YouTube Theater Mode Default]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Update max_sub_array.py by snehanjaligvs · Pull Request #8642 · TheAlgorithms/Python · GitHub
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75 changes: 13 additions & 62 deletions dynamic_programming/max_sub_array.py
Original file line numberDiff line numberDiff line change
@@ -1,44 +1,11 @@
"""
author : Mayank Kumar Jha (mk9440)
author(after editing) : Snehanjali G V S
"""
from __future__ import annotations


def find_max_sub_array(a, low, high):
if low == high:
return low, high, a[low]
else:
mid = (low + high) // 2
left_low, left_high, left_sum = find_max_sub_array(a, low, mid)
right_low, right_high, right_sum = find_max_sub_array(a, mid + 1, high)
cross_left, cross_right, cross_sum = find_max_cross_sum(a, low, mid, high)
if left_sum >= right_sum and left_sum >= cross_sum:
return left_low, left_high, left_sum
elif right_sum >= left_sum and right_sum >= cross_sum:
return right_low, right_high, right_sum
else:
return cross_left, cross_right, cross_sum


def find_max_cross_sum(a, low, mid, high):
left_sum, max_left = -999999999, -1
right_sum, max_right = -999999999, -1
summ = 0
for i in range(mid, low - 1, -1):
summ += a[i]
if summ > left_sum:
left_sum = summ
max_left = i
summ = 0
for i in range(mid + 1, high + 1):
summ += a[i]
if summ > right_sum:
right_sum = summ
max_right = i
return max_left, max_right, (left_sum + right_sum)


def max_sub_array(nums: list[int]) -> int:
def max_sub_array(a: list[int]) -> int:
"""
Finds the contiguous subarray which has the largest sum and return its sum.

Expand All@@ -58,36 +25,20 @@ def max_sub_array(nums: list[int]) -> int:
>>> max_sub_array([31, -41, 59, 26, -53, 58, 97, -93, -23, 84])
187
"""
best = 0
current = 0
for i in nums:
current += i
current = max(current, 0)
best = max(best, current)
return best
sol = [0] * (len(a) + 1)
for i in range(1, len(sol)):
sol[i] = max(sol[i - 1] + a[i - 1], a[i - 1])

answer = sol[0]
for i in range(1, len(sol)):
if answer < sol[i]:
answer = sol[i]
return answer


if __name__ == "__main__":
"""
A random simulation of this algorithm.
"""
import time
from random import randint

from matplotlib import pyplot as plt

inputs = [10, 100, 1000, 10000, 50000, 100000, 200000, 300000, 400000, 500000]
tim = []
for i in inputs:
li = [randint(1, i) for j in range(i)]
strt = time.time()
(find_max_sub_array(li, 0, len(li) - 1))
end = time.time()
tim.append(end - strt)
print("No of Inputs Time Taken")
for i in range(len(inputs)):
print(inputs[i], "\t\t", tim[i])
plt.plot(inputs, tim)
plt.xlabel("Number of Inputs")
plt.ylabel("Time taken in seconds ")
plt.show()
inputs = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
print(max_sub_array(inputs))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Remove or un-stick sticky/fixed headers that block content (function() { function unstick() { document.querySelectorAll('header, nav, [role="banner"], .header, .navbar, .sticky, .fixed-top, [style*="position: fixed"], [style*="position:sticky"]').forEach(function(el) { if (el.style.position === 'fixed' || el.style.position === 'sticky' || getComputedStyle(el).position === 'fixed' || getComputedStyle(el).position === 'sticky') { el.style.position = 'static'; el.style.top = 'auto'; el.style.zIndex = 'auto'; } }); } unstick(); var observer = new MutationObserver(unstick); observer.observe(document.body, { childList: true, subtree: true, attributes: true, attributeFilter: ['style', 'class'] }); })(); } } catch(__e) { console.warn('[Userscript:Kill Sticky Headers]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Update max_sub_array.py by snehanjaligvs · Pull Request #8642 · TheAlgorithms/Python · GitHub
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75 changes: 13 additions & 62 deletions dynamic_programming/max_sub_array.py
Original file line numberDiff line numberDiff line change
@@ -1,44 +1,11 @@
"""
author : Mayank Kumar Jha (mk9440)
author(after editing) : Snehanjali G V S
"""
from __future__ import annotations


def find_max_sub_array(a, low, high):
if low == high:
return low, high, a[low]
else:
mid = (low + high) // 2
left_low, left_high, left_sum = find_max_sub_array(a, low, mid)
right_low, right_high, right_sum = find_max_sub_array(a, mid + 1, high)
cross_left, cross_right, cross_sum = find_max_cross_sum(a, low, mid, high)
if left_sum >= right_sum and left_sum >= cross_sum:
return left_low, left_high, left_sum
elif right_sum >= left_sum and right_sum >= cross_sum:
return right_low, right_high, right_sum
else:
return cross_left, cross_right, cross_sum


def find_max_cross_sum(a, low, mid, high):
left_sum, max_left = -999999999, -1
right_sum, max_right = -999999999, -1
summ = 0
for i in range(mid, low - 1, -1):
summ += a[i]
if summ > left_sum:
left_sum = summ
max_left = i
summ = 0
for i in range(mid + 1, high + 1):
summ += a[i]
if summ > right_sum:
right_sum = summ
max_right = i
return max_left, max_right, (left_sum + right_sum)


def max_sub_array(nums: list[int]) -> int:
def max_sub_array(a: list[int]) -> int:
"""
Finds the contiguous subarray which has the largest sum and return its sum.

Expand All@@ -58,36 +25,20 @@ def max_sub_array(nums: list[int]) -> int:
>>> max_sub_array([31, -41, 59, 26, -53, 58, 97, -93, -23, 84])
187
"""
best = 0
current = 0
for i in nums:
current += i
current = max(current, 0)
best = max(best, current)
return best
sol = [0] * (len(a) + 1)
for i in range(1, len(sol)):
sol[i] = max(sol[i - 1] + a[i - 1], a[i - 1])

answer = sol[0]
for i in range(1, len(sol)):
if answer < sol[i]:
answer = sol[i]
return answer


if __name__ == "__main__":
"""
A random simulation of this algorithm.
"""
import time
from random import randint

from matplotlib import pyplot as plt

inputs = [10, 100, 1000, 10000, 50000, 100000, 200000, 300000, 400000, 500000]
tim = []
for i in inputs:
li = [randint(1, i) for j in range(i)]
strt = time.time()
(find_max_sub_array(li, 0, len(li) - 1))
end = time.time()
tim.append(end - strt)
print("No of Inputs Time Taken")
for i in range(len(inputs)):
print(inputs[i], "\t\t", tim[i])
plt.plot(inputs, tim)
plt.xlabel("Number of Inputs")
plt.ylabel("Time taken in seconds ")
plt.show()
inputs = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
print(max_sub_array(inputs))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Universal Dark Mode - works on any site (function() { var enabled = true; function applyDarkMode() { if (!enabled) return; // Create style element if it doesn't exist var style = document.getElementById('universal-dark-mode-style'); if (!style) { style = document.createElement('style'); style.id = 'universal-dark-mode-style'; document.head.appendChild(style); } // Dark mode CSS - inverts colors but preserves images/video style.textContent = ' /* Invert everything except media */ html { filter: invert(1) hue-rotate(180deg) !important; background: #1a1a2e !important; } /* Restore images, videos, iframes, canvas */ img, video, iframe, canvas, svg, picture, [style*="background-image"] { filter: invert(1) hue-rotate(180deg) !important; } /* Preserve specific elements that should not be inverted */ .no-dark-mode, .no-dark-mode *, [data-theme="light"], [data-theme="light"], .ace_editor, .ace_editor *, .CodeMirror, .CodeMirror *, .monaco-editor, .monaco-editor *, .markdown-body pre, .markdown-body pre *, .highlight, .highlight *, pre code, pre code * { filter: none !important; } /* Fix common UI elements */ .modal, .popup, .dropdown-menu, .tooltip, .popover { filter: invert(1) hue-rotate(180deg) !important; background: #2d2d44 !important; border-color: #444 !important; } /* Scrollbars */ ::-webkit-scrollbar { background: #1a1a2e !important; } ::-webkit-scrollbar-thumb { background: #444 !important; } ::-webkit-scrollbar-thumb:hover { background: #555 !important; } /* Selection */ ::selection { background: #4ecdc4 !important; color: #1a1a2e !important; } ::-moz-selection { background: #4ecdc4 !important; color: #1a1a2e !important; } '; } function removeDarkMode() { var style = document.getElementById('universal-dark-mode-style'); if (style) style.remove(); } // Toggle with Alt+Shift+D document.addEventListener('keydown', function(e) { if (e.altKey && e.shiftKey && e.key === 'D') { e.preventDefault(); enabled = !enabled; if (enabled) { applyDarkMode(); console.log('[Universal Dark Mode] Enabled'); } else { removeDarkMode(); console.log('[Universal Dark Mode] Disabled'); } } }); // Apply on load applyDarkMode(); // Re-apply on dynamic content var observer = new MutationObserver(function(mutations) { if (enabled && !document.getElementById('universal-dark-mode-style')) { applyDarkMode(); } }); observer.observe(document.head, { childList: true }); console.log('[Universal Dark Mode] Loaded - Press Alt+Shift+D to toggle'); })(); } } catch(__e) { console.warn('[Userscript:Universal Dark Mode]', __e); } })(); })(); Update max_sub_array.py by snehanjaligvs · Pull Request #8642 · TheAlgorithms/Python · GitHub
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75 changes: 13 additions & 62 deletions dynamic_programming/max_sub_array.py
Original file line numberDiff line numberDiff line change
@@ -1,44 +1,11 @@
"""
author : Mayank Kumar Jha (mk9440)
author(after editing) : Snehanjali G V S
"""
from __future__ import annotations


def find_max_sub_array(a, low, high):
if low == high:
return low, high, a[low]
else:
mid = (low + high) // 2
left_low, left_high, left_sum = find_max_sub_array(a, low, mid)
right_low, right_high, right_sum = find_max_sub_array(a, mid + 1, high)
cross_left, cross_right, cross_sum = find_max_cross_sum(a, low, mid, high)
if left_sum >= right_sum and left_sum >= cross_sum:
return left_low, left_high, left_sum
elif right_sum >= left_sum and right_sum >= cross_sum:
return right_low, right_high, right_sum
else:
return cross_left, cross_right, cross_sum


def find_max_cross_sum(a, low, mid, high):
left_sum, max_left = -999999999, -1
right_sum, max_right = -999999999, -1
summ = 0
for i in range(mid, low - 1, -1):
summ += a[i]
if summ > left_sum:
left_sum = summ
max_left = i
summ = 0
for i in range(mid + 1, high + 1):
summ += a[i]
if summ > right_sum:
right_sum = summ
max_right = i
return max_left, max_right, (left_sum + right_sum)


def max_sub_array(nums: list[int]) -> int:
def max_sub_array(a: list[int]) -> int:
"""
Finds the contiguous subarray which has the largest sum and return its sum.

Expand All@@ -58,36 +25,20 @@ def max_sub_array(nums: list[int]) -> int:
>>> max_sub_array([31, -41, 59, 26, -53, 58, 97, -93, -23, 84])
187
"""
best = 0
current = 0
for i in nums:
current += i
current = max(current, 0)
best = max(best, current)
return best
sol = [0] * (len(a) + 1)
for i in range(1, len(sol)):
sol[i] = max(sol[i - 1] + a[i - 1], a[i - 1])

answer = sol[0]
for i in range(1, len(sol)):
if answer < sol[i]:
answer = sol[i]
return answer


if __name__ == "__main__":
"""
A random simulation of this algorithm.
"""
import time
from random import randint

from matplotlib import pyplot as plt

inputs = [10, 100, 1000, 10000, 50000, 100000, 200000, 300000, 400000, 500000]
tim = []
for i in inputs:
li = [randint(1, i) for j in range(i)]
strt = time.time()
(find_max_sub_array(li, 0, len(li) - 1))
end = time.time()
tim.append(end - strt)
print("No of Inputs Time Taken")
for i in range(len(inputs)):
print(inputs[i], "\t\t", tim[i])
plt.plot(inputs, tim)
plt.xlabel("Number of Inputs")
plt.ylabel("Time taken in seconds ")
plt.show()
inputs = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
print(max_sub_array(inputs))