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5 changes: 5 additions & 0 deletions .vscode/settings.json
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,5 @@
{
"githubPullRequests.ignoredPullRequestBranches": [
"master"
]
}
142 changes: 142 additions & 0 deletions maths/simultaneous_linear_equation_solver.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,142 @@
"""
https://en.wikipedia.org/wiki/Augmented_matrix

This algorithm solves simultaneous linear equations of the form
λa + λb + λc + λd + ... = γ as [λ, λ, λ, λ, ..., γ]
Where λ & γ are individual coefficients, the no. of equations = no. of coefficients - 1

Note in order to work there must exist 1 equation where all instances of λ and γ != 0
"""


def simplify(current_set: list[list]) -> list[list]:
"""
>>> simplify([[1, 2, 3], [4, 5, 6]])
[[1.0, 2.0, 3.0], [0.0, 0.75, 1.5]]
>>> simplify([[5, 2, 5], [5, 1, 10]])
[[1.0, 0.4, 1.0], [0.0, 0.2, -1.0]]
"""
# Divide each row by magnitude of first term --> creates 'unit' matrix
duplicate_set = current_set.copy()
for row_index, row in enumerate(duplicate_set):
magnitude = row[0]
for column_index, column in enumerate(row):
if magnitude == 0:
current_set[row_index][column_index] = column
continue
current_set[row_index][column_index] = column / magnitude
# Subtract to cancel term
first_row = current_set[0]
final_set = [first_row]
current_set = current_set[1::]
for row in current_set:
temp_row = []
# If first term is 0, it is already in form we want, so we preserve it
if row[0] == 0:
final_set.append(row)
continue
for column_index in range(len(row)):
temp_row.append(first_row[column_index] - row[column_index])
final_set.append(temp_row)
# Create next recursion iteration set
if len(final_set[0]) != 3:
current_first_row = final_set[0]
current_first_column = []
next_iteration = []
for row in final_set[1::]:
current_first_column.append(row[0])
next_iteration.append(row[1::])
resultant = simplify(next_iteration)
for i in range(len(resultant)):
resultant[i].insert(0, current_first_column[i])
resultant.insert(0, current_first_row)
final_set = resultant
return final_set


def solve_simultaneous(equations: list[list]) -> list:
"""
>>> solve_simultaneous([[1, 2, 3],[4, 5, 6]])
[-1.0, 2.0]
>>> solve_simultaneous([[0, -3, 1, 7],[3, 2, -1, 11],[5, 1, -2, 12]])
[6.4, 1.2, 10.6]
>>> solve_simultaneous([])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],[1, 2]])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],["a", 7, 8]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires lists of integers
>>> solve_simultaneous([[0, 2, 3],[4, 0, 6]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires at least 1 full equation
"""
if len(equations) == 0:
raise IndexError("solve_simultaneous() requires n lists of length n+1")
_length = len(equations) + 1
if any(len(item) != _length for item in equations):
raise IndexError("solve_simultaneous() requires n lists of length n+1")
for row in equations:
if any(not isinstance(column, (int, float)) for column in row):
raise ValueError("solve_simultaneous() requires lists of integers")
if len(equations) == 1:
return [equations[0][-1] / equations[0][0]]
data_set = equations.copy()
if any(0 in row for row in data_set):
temp_data = data_set.copy()
full_row = []
for row_index, row in enumerate(temp_data):
if 0 not in row:
full_row = data_set.pop(row_index)
break
if not full_row:
raise ValueError("solve_simultaneous() requires at least 1 full equation")
data_set.insert(0, full_row)
useable_form = data_set.copy()
simplified = simplify(useable_form)
simplified = simplified[::-1]
solutions: list = []
for row in simplified:
current_solution = row[-1]
if not solutions:
if row[-2] == 0:
solutions.append(0)
continue
solutions.append(current_solution / row[-2])
continue
temp_row = row.copy()[: len(row) - 1 :]
while temp_row[0] == 0:
temp_row.pop(0)
if len(temp_row) == 0:
solutions.append(0)
continue
temp_row = temp_row[1::]
temp_row = temp_row[::-1]
for column_index, column in enumerate(temp_row):
current_solution -= column * solutions[column_index]
solutions.append(current_solution)
final = []
for item in solutions:
final.append(float(round(item, 5)))
return final[::-1]


if __name__ == "__main__":
import doctest

doctest.testmod()
eq = [
[2, 1, 1, 1, 1, 4],
[1, 2, 1, 1, 1, 5],
[1, 1, 2, 1, 1, 6],
[1, 1, 1, 2, 1, 7],
[1, 1, 1, 1, 2, 8],
]
print(solve_simultaneous(eq))
print(solve_simultaneous([[4, 2]]))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Add copy buttons to all
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function addCopyButtons() {
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navigator.clipboard.writeText(codeBlock.textContent).then(function() {
btn.textContent = 'Copied!';
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});
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observer.observe(document.body, { childList: true, subtree: true });
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})();
(function(){
try {
var __m = "github.com";
var __re = new RegExp('^' + "github\\.com" + '
Create a Simultaneous Equation Solver Algorithm by chriso345 · Pull Request #8773 · TheAlgorithms/Python · GitHub
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5 changes: 5 additions & 0 deletions .vscode/settings.json
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,5 @@
{
"githubPullRequests.ignoredPullRequestBranches": [
"master"
]
}
142 changes: 142 additions & 0 deletions maths/simultaneous_linear_equation_solver.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,142 @@
"""
https://en.wikipedia.org/wiki/Augmented_matrix

This algorithm solves simultaneous linear equations of the form
λa + λb + λc + λd + ... = γ as [λ, λ, λ, λ, ..., γ]
Where λ & γ are individual coefficients, the no. of equations = no. of coefficients - 1

Note in order to work there must exist 1 equation where all instances of λ and γ != 0
"""


def simplify(current_set: list[list]) -> list[list]:
"""
>>> simplify([[1, 2, 3], [4, 5, 6]])
[[1.0, 2.0, 3.0], [0.0, 0.75, 1.5]]
>>> simplify([[5, 2, 5], [5, 1, 10]])
[[1.0, 0.4, 1.0], [0.0, 0.2, -1.0]]
"""
# Divide each row by magnitude of first term --> creates 'unit' matrix
duplicate_set = current_set.copy()
for row_index, row in enumerate(duplicate_set):
magnitude = row[0]
for column_index, column in enumerate(row):
if magnitude == 0:
current_set[row_index][column_index] = column
continue
current_set[row_index][column_index] = column / magnitude
# Subtract to cancel term
first_row = current_set[0]
final_set = [first_row]
current_set = current_set[1::]
for row in current_set:
temp_row = []
# If first term is 0, it is already in form we want, so we preserve it
if row[0] == 0:
final_set.append(row)
continue
for column_index in range(len(row)):
temp_row.append(first_row[column_index] - row[column_index])
final_set.append(temp_row)
# Create next recursion iteration set
if len(final_set[0]) != 3:
current_first_row = final_set[0]
current_first_column = []
next_iteration = []
for row in final_set[1::]:
current_first_column.append(row[0])
next_iteration.append(row[1::])
resultant = simplify(next_iteration)
for i in range(len(resultant)):
resultant[i].insert(0, current_first_column[i])
resultant.insert(0, current_first_row)
final_set = resultant
return final_set


def solve_simultaneous(equations: list[list]) -> list:
"""
>>> solve_simultaneous([[1, 2, 3],[4, 5, 6]])
[-1.0, 2.0]
>>> solve_simultaneous([[0, -3, 1, 7],[3, 2, -1, 11],[5, 1, -2, 12]])
[6.4, 1.2, 10.6]
>>> solve_simultaneous([])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],[1, 2]])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],["a", 7, 8]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires lists of integers
>>> solve_simultaneous([[0, 2, 3],[4, 0, 6]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires at least 1 full equation
"""
if len(equations) == 0:
raise IndexError("solve_simultaneous() requires n lists of length n+1")
_length = len(equations) + 1
if any(len(item) != _length for item in equations):
raise IndexError("solve_simultaneous() requires n lists of length n+1")
for row in equations:
if any(not isinstance(column, (int, float)) for column in row):
raise ValueError("solve_simultaneous() requires lists of integers")
if len(equations) == 1:
return [equations[0][-1] / equations[0][0]]
data_set = equations.copy()
if any(0 in row for row in data_set):
temp_data = data_set.copy()
full_row = []
for row_index, row in enumerate(temp_data):
if 0 not in row:
full_row = data_set.pop(row_index)
break
if not full_row:
raise ValueError("solve_simultaneous() requires at least 1 full equation")
data_set.insert(0, full_row)
useable_form = data_set.copy()
simplified = simplify(useable_form)
simplified = simplified[::-1]
solutions: list = []
for row in simplified:
current_solution = row[-1]
if not solutions:
if row[-2] == 0:
solutions.append(0)
continue
solutions.append(current_solution / row[-2])
continue
temp_row = row.copy()[: len(row) - 1 :]
while temp_row[0] == 0:
temp_row.pop(0)
if len(temp_row) == 0:
solutions.append(0)
continue
temp_row = temp_row[1::]
temp_row = temp_row[::-1]
for column_index, column in enumerate(temp_row):
current_solution -= column * solutions[column_index]
solutions.append(current_solution)
final = []
for item in solutions:
final.append(float(round(item, 5)))
return final[::-1]


if __name__ == "__main__":
import doctest

doctest.testmod()
eq = [
[2, 1, 1, 1, 1, 4],
[1, 2, 1, 1, 1, 5],
[1, 1, 2, 1, 1, 6],
[1, 1, 1, 2, 1, 7],
[1, 1, 1, 1, 2, 8],
]
print(solve_simultaneous(eq))
print(solve_simultaneous([[4, 2]]))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Force GitHub README to respect dark mode (function() { var style = document.createElement('style'); style.textContent = ' .markdown-body { color-scheme: dark light; } .markdown-body pre { background: #161b22 !important; } .markdown-body code { background: rgba(110, 118, 129, 0.4) !important; } .markdown-body table th, .markdown-body table td { border-color: #30363d !important; } .markdown-body img { background: #0d1117; } .markdown-body blockquote { border-left-color: #8b949e; } .markdown-body hr { border-color: #30363d; } '; document.head.appendChild(style); })(); } } catch(__e) { console.warn('[Userscript:GitHub Dark Mode README Fix]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Create a Simultaneous Equation Solver Algorithm by chriso345 · Pull Request #8773 · TheAlgorithms/Python · GitHub
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5 changes: 5 additions & 0 deletions .vscode/settings.json
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,5 @@
{
"githubPullRequests.ignoredPullRequestBranches": [
"master"
]
}
142 changes: 142 additions & 0 deletions maths/simultaneous_linear_equation_solver.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,142 @@
"""
https://en.wikipedia.org/wiki/Augmented_matrix

This algorithm solves simultaneous linear equations of the form
λa + λb + λc + λd + ... = γ as [λ, λ, λ, λ, ..., γ]
Where λ & γ are individual coefficients, the no. of equations = no. of coefficients - 1

Note in order to work there must exist 1 equation where all instances of λ and γ != 0
"""


def simplify(current_set: list[list]) -> list[list]:
"""
>>> simplify([[1, 2, 3], [4, 5, 6]])
[[1.0, 2.0, 3.0], [0.0, 0.75, 1.5]]
>>> simplify([[5, 2, 5], [5, 1, 10]])
[[1.0, 0.4, 1.0], [0.0, 0.2, -1.0]]
"""
# Divide each row by magnitude of first term --> creates 'unit' matrix
duplicate_set = current_set.copy()
for row_index, row in enumerate(duplicate_set):
magnitude = row[0]
for column_index, column in enumerate(row):
if magnitude == 0:
current_set[row_index][column_index] = column
continue
current_set[row_index][column_index] = column / magnitude
# Subtract to cancel term
first_row = current_set[0]
final_set = [first_row]
current_set = current_set[1::]
for row in current_set:
temp_row = []
# If first term is 0, it is already in form we want, so we preserve it
if row[0] == 0:
final_set.append(row)
continue
for column_index in range(len(row)):
temp_row.append(first_row[column_index] - row[column_index])
final_set.append(temp_row)
# Create next recursion iteration set
if len(final_set[0]) != 3:
current_first_row = final_set[0]
current_first_column = []
next_iteration = []
for row in final_set[1::]:
current_first_column.append(row[0])
next_iteration.append(row[1::])
resultant = simplify(next_iteration)
for i in range(len(resultant)):
resultant[i].insert(0, current_first_column[i])
resultant.insert(0, current_first_row)
final_set = resultant
return final_set


def solve_simultaneous(equations: list[list]) -> list:
"""
>>> solve_simultaneous([[1, 2, 3],[4, 5, 6]])
[-1.0, 2.0]
>>> solve_simultaneous([[0, -3, 1, 7],[3, 2, -1, 11],[5, 1, -2, 12]])
[6.4, 1.2, 10.6]
>>> solve_simultaneous([])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],[1, 2]])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],["a", 7, 8]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires lists of integers
>>> solve_simultaneous([[0, 2, 3],[4, 0, 6]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires at least 1 full equation
"""
if len(equations) == 0:
raise IndexError("solve_simultaneous() requires n lists of length n+1")
_length = len(equations) + 1
if any(len(item) != _length for item in equations):
raise IndexError("solve_simultaneous() requires n lists of length n+1")
for row in equations:
if any(not isinstance(column, (int, float)) for column in row):
raise ValueError("solve_simultaneous() requires lists of integers")
if len(equations) == 1:
return [equations[0][-1] / equations[0][0]]
data_set = equations.copy()
if any(0 in row for row in data_set):
temp_data = data_set.copy()
full_row = []
for row_index, row in enumerate(temp_data):
if 0 not in row:
full_row = data_set.pop(row_index)
break
if not full_row:
raise ValueError("solve_simultaneous() requires at least 1 full equation")
data_set.insert(0, full_row)
useable_form = data_set.copy()
simplified = simplify(useable_form)
simplified = simplified[::-1]
solutions: list = []
for row in simplified:
current_solution = row[-1]
if not solutions:
if row[-2] == 0:
solutions.append(0)
continue
solutions.append(current_solution / row[-2])
continue
temp_row = row.copy()[: len(row) - 1 :]
while temp_row[0] == 0:
temp_row.pop(0)
if len(temp_row) == 0:
solutions.append(0)
continue
temp_row = temp_row[1::]
temp_row = temp_row[::-1]
for column_index, column in enumerate(temp_row):
current_solution -= column * solutions[column_index]
solutions.append(current_solution)
final = []
for item in solutions:
final.append(float(round(item, 5)))
return final[::-1]


if __name__ == "__main__":
import doctest

doctest.testmod()
eq = [
[2, 1, 1, 1, 1, 4],
[1, 2, 1, 1, 1, 5],
[1, 1, 2, 1, 1, 6],
[1, 1, 1, 2, 1, 7],
[1, 1, 1, 1, 2, 8],
]
print(solve_simultaneous(eq))
print(solve_simultaneous([[4, 2]]))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Highlight search terms from Google/DuckDuckGo/Bing referrer (function() { var ref = document.referrer; var terms = []; if (ref.includes('google.com') || ref.includes('duckduckgo.com') || ref.includes('bing.com')) { var url = new URL(ref); var q = url.searchParams.get('q') || url.searchParams.get('p'); if (q) { terms = q.split(/\s+/).filter(function(t) { return t.length > 2; }); } } if (terms.length === 0) return; var style = document.createElement('style'); style.textContent = '.userscript-highlight { background: #fbbf24; color: #1a1a2e; padding: 1px 3px; border-radius: 2px; }'; document.head.appendChild(style); function highlight(node) { if (node.nodeType === 3) { // text node var text = node.textContent; var found = false; terms.forEach(function(term) { var regex = new RegExp('(' + term.replace(/[.*+?^${}()|[\]\\]/g, '\\') + ')', 'gi'); if (regex.test(text)) { found = true; var frag = document.createDocumentFragment(); var parts = text.split(regex); parts.forEach(function(part, i) { if (i % 2 === 0) { frag.appendChild(document.createTextNode(part)); } else { var span = document.createElement('span'); span.className = 'userscript-highlight'; span.textContent = part; frag.appendChild(span); } }); node.parentNode.replaceChild(frag, node); } }); } else if (node.nodeType === 1 && node.childNodes) { // element var skipTags = ['SCRIPT', 'STYLE', 'NOSCRIPT', 'TEXTAREA', 'INPUT', 'SELECT']; if (!skipTags.includes(node.tagName)) { Array.from(node.childNodes).forEach(highlight); } } } highlight(document.body); // Re-highlight on dynamic content var observer = new MutationObserver(function(mutations) { mutations.forEach(function(m) { m.addedNodes.forEach(function(node) { if (node.nodeType === 1 || node.nodeType === 3) highlight(node); }); }); }); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:Highlight Search Terms]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Create a Simultaneous Equation Solver Algorithm by chriso345 · Pull Request #8773 · TheAlgorithms/Python · GitHub
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5 changes: 5 additions & 0 deletions .vscode/settings.json
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,5 @@
{
"githubPullRequests.ignoredPullRequestBranches": [
"master"
]
}
142 changes: 142 additions & 0 deletions maths/simultaneous_linear_equation_solver.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,142 @@
"""
https://en.wikipedia.org/wiki/Augmented_matrix

This algorithm solves simultaneous linear equations of the form
λa + λb + λc + λd + ... = γ as [λ, λ, λ, λ, ..., γ]
Where λ & γ are individual coefficients, the no. of equations = no. of coefficients - 1

Note in order to work there must exist 1 equation where all instances of λ and γ != 0
"""


def simplify(current_set: list[list]) -> list[list]:
"""
>>> simplify([[1, 2, 3], [4, 5, 6]])
[[1.0, 2.0, 3.0], [0.0, 0.75, 1.5]]
>>> simplify([[5, 2, 5], [5, 1, 10]])
[[1.0, 0.4, 1.0], [0.0, 0.2, -1.0]]
"""
# Divide each row by magnitude of first term --> creates 'unit' matrix
duplicate_set = current_set.copy()
for row_index, row in enumerate(duplicate_set):
magnitude = row[0]
for column_index, column in enumerate(row):
if magnitude == 0:
current_set[row_index][column_index] = column
continue
current_set[row_index][column_index] = column / magnitude
# Subtract to cancel term
first_row = current_set[0]
final_set = [first_row]
current_set = current_set[1::]
for row in current_set:
temp_row = []
# If first term is 0, it is already in form we want, so we preserve it
if row[0] == 0:
final_set.append(row)
continue
for column_index in range(len(row)):
temp_row.append(first_row[column_index] - row[column_index])
final_set.append(temp_row)
# Create next recursion iteration set
if len(final_set[0]) != 3:
current_first_row = final_set[0]
current_first_column = []
next_iteration = []
for row in final_set[1::]:
current_first_column.append(row[0])
next_iteration.append(row[1::])
resultant = simplify(next_iteration)
for i in range(len(resultant)):
resultant[i].insert(0, current_first_column[i])
resultant.insert(0, current_first_row)
final_set = resultant
return final_set


def solve_simultaneous(equations: list[list]) -> list:
"""
>>> solve_simultaneous([[1, 2, 3],[4, 5, 6]])
[-1.0, 2.0]
>>> solve_simultaneous([[0, -3, 1, 7],[3, 2, -1, 11],[5, 1, -2, 12]])
[6.4, 1.2, 10.6]
>>> solve_simultaneous([])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],[1, 2]])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],["a", 7, 8]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires lists of integers
>>> solve_simultaneous([[0, 2, 3],[4, 0, 6]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires at least 1 full equation
"""
if len(equations) == 0:
raise IndexError("solve_simultaneous() requires n lists of length n+1")
_length = len(equations) + 1
if any(len(item) != _length for item in equations):
raise IndexError("solve_simultaneous() requires n lists of length n+1")
for row in equations:
if any(not isinstance(column, (int, float)) for column in row):
raise ValueError("solve_simultaneous() requires lists of integers")
if len(equations) == 1:
return [equations[0][-1] / equations[0][0]]
data_set = equations.copy()
if any(0 in row for row in data_set):
temp_data = data_set.copy()
full_row = []
for row_index, row in enumerate(temp_data):
if 0 not in row:
full_row = data_set.pop(row_index)
break
if not full_row:
raise ValueError("solve_simultaneous() requires at least 1 full equation")
data_set.insert(0, full_row)
useable_form = data_set.copy()
simplified = simplify(useable_form)
simplified = simplified[::-1]
solutions: list = []
for row in simplified:
current_solution = row[-1]
if not solutions:
if row[-2] == 0:
solutions.append(0)
continue
solutions.append(current_solution / row[-2])
continue
temp_row = row.copy()[: len(row) - 1 :]
while temp_row[0] == 0:
temp_row.pop(0)
if len(temp_row) == 0:
solutions.append(0)
continue
temp_row = temp_row[1::]
temp_row = temp_row[::-1]
for column_index, column in enumerate(temp_row):
current_solution -= column * solutions[column_index]
solutions.append(current_solution)
final = []
for item in solutions:
final.append(float(round(item, 5)))
return final[::-1]


if __name__ == "__main__":
import doctest

doctest.testmod()
eq = [
[2, 1, 1, 1, 1, 4],
[1, 2, 1, 1, 1, 5],
[1, 1, 2, 1, 1, 6],
[1, 1, 1, 2, 1, 7],
[1, 1, 1, 1, 2, 8],
]
print(solve_simultaneous(eq))
print(solve_simultaneous([[4, 2]]))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Strip utm_, fbclid, gclid, etc. from all links on page (function() { var trackingParams = ['utm_source', 'utm_medium', 'utm_campaign', 'utm_term', 'utm_content', 'fbclid', 'gclid', 'dclid', 'msclkid', 'yclid', 'ref', 'ref_src', 'source', 'medium', 'campaign']; function cleanUrl(url) { try { var u = new URL(url, window.location.origin); var changed = false; trackingParams.forEach(function(p) { if (u.searchParams.has(p)) { u.searchParams.delete(p); changed = true; } }); return changed ? u.toString() : url; } catch (e) { return url; } } function cleanLinks() { document.querySelectorAll('a[href]').forEach(function(a) { var clean = cleanUrl(a.href); if (clean !== a.href) a.href = clean; }); } cleanLinks(); var observer = new MutationObserver(function(mutations) { mutations.forEach(function(m) { m.addedNodes.forEach(function(node) { if (node.nodeType === 1) { if (node.tagName === 'A') cleanLinks(); node.querySelectorAll('a[href]').forEach(function(a) { var clean = cleanUrl(a.href); if (clean !== a.href) a.href = clean; }); } }); }); }); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:Remove Tracking Parameters from Links]', __e); } })(); (function(){ try { var __m = "youtube.com"; var __re = new RegExp('^' + "youtube\\.com" + ' Create a Simultaneous Equation Solver Algorithm by chriso345 · Pull Request #8773 · TheAlgorithms/Python · GitHub
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5 changes: 5 additions & 0 deletions .vscode/settings.json
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,5 @@
{
"githubPullRequests.ignoredPullRequestBranches": [
"master"
]
}
142 changes: 142 additions & 0 deletions maths/simultaneous_linear_equation_solver.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,142 @@
"""
https://en.wikipedia.org/wiki/Augmented_matrix

This algorithm solves simultaneous linear equations of the form
λa + λb + λc + λd + ... = γ as [λ, λ, λ, λ, ..., γ]
Where λ & γ are individual coefficients, the no. of equations = no. of coefficients - 1

Note in order to work there must exist 1 equation where all instances of λ and γ != 0
"""


def simplify(current_set: list[list]) -> list[list]:
"""
>>> simplify([[1, 2, 3], [4, 5, 6]])
[[1.0, 2.0, 3.0], [0.0, 0.75, 1.5]]
>>> simplify([[5, 2, 5], [5, 1, 10]])
[[1.0, 0.4, 1.0], [0.0, 0.2, -1.0]]
"""
# Divide each row by magnitude of first term --> creates 'unit' matrix
duplicate_set = current_set.copy()
for row_index, row in enumerate(duplicate_set):
magnitude = row[0]
for column_index, column in enumerate(row):
if magnitude == 0:
current_set[row_index][column_index] = column
continue
current_set[row_index][column_index] = column / magnitude
# Subtract to cancel term
first_row = current_set[0]
final_set = [first_row]
current_set = current_set[1::]
for row in current_set:
temp_row = []
# If first term is 0, it is already in form we want, so we preserve it
if row[0] == 0:
final_set.append(row)
continue
for column_index in range(len(row)):
temp_row.append(first_row[column_index] - row[column_index])
final_set.append(temp_row)
# Create next recursion iteration set
if len(final_set[0]) != 3:
current_first_row = final_set[0]
current_first_column = []
next_iteration = []
for row in final_set[1::]:
current_first_column.append(row[0])
next_iteration.append(row[1::])
resultant = simplify(next_iteration)
for i in range(len(resultant)):
resultant[i].insert(0, current_first_column[i])
resultant.insert(0, current_first_row)
final_set = resultant
return final_set


def solve_simultaneous(equations: list[list]) -> list:
"""
>>> solve_simultaneous([[1, 2, 3],[4, 5, 6]])
[-1.0, 2.0]
>>> solve_simultaneous([[0, -3, 1, 7],[3, 2, -1, 11],[5, 1, -2, 12]])
[6.4, 1.2, 10.6]
>>> solve_simultaneous([])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],[1, 2]])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],["a", 7, 8]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires lists of integers
>>> solve_simultaneous([[0, 2, 3],[4, 0, 6]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires at least 1 full equation
"""
if len(equations) == 0:
raise IndexError("solve_simultaneous() requires n lists of length n+1")
_length = len(equations) + 1
if any(len(item) != _length for item in equations):
raise IndexError("solve_simultaneous() requires n lists of length n+1")
for row in equations:
if any(not isinstance(column, (int, float)) for column in row):
raise ValueError("solve_simultaneous() requires lists of integers")
if len(equations) == 1:
return [equations[0][-1] / equations[0][0]]
data_set = equations.copy()
if any(0 in row for row in data_set):
temp_data = data_set.copy()
full_row = []
for row_index, row in enumerate(temp_data):
if 0 not in row:
full_row = data_set.pop(row_index)
break
if not full_row:
raise ValueError("solve_simultaneous() requires at least 1 full equation")
data_set.insert(0, full_row)
useable_form = data_set.copy()
simplified = simplify(useable_form)
simplified = simplified[::-1]
solutions: list = []
for row in simplified:
current_solution = row[-1]
if not solutions:
if row[-2] == 0:
solutions.append(0)
continue
solutions.append(current_solution / row[-2])
continue
temp_row = row.copy()[: len(row) - 1 :]
while temp_row[0] == 0:
temp_row.pop(0)
if len(temp_row) == 0:
solutions.append(0)
continue
temp_row = temp_row[1::]
temp_row = temp_row[::-1]
for column_index, column in enumerate(temp_row):
current_solution -= column * solutions[column_index]
solutions.append(current_solution)
final = []
for item in solutions:
final.append(float(round(item, 5)))
return final[::-1]


if __name__ == "__main__":
import doctest

doctest.testmod()
eq = [
[2, 1, 1, 1, 1, 4],
[1, 2, 1, 1, 1, 5],
[1, 1, 2, 1, 1, 6],
[1, 1, 1, 2, 1, 7],
[1, 1, 1, 1, 2, 8],
]
print(solve_simultaneous(eq))
print(solve_simultaneous([[4, 2]]))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Auto-enable theater mode on YouTube (function() { function tryTheater() { var btn = document.querySelector('button[aria-label="Theater mode"], ytd-player #player button[title="Theater mode"]'); if (btn && !btn.classList.contains('activated')) { btn.click(); } } // Try immediately tryTheater(); // Try after navigation (SPA) var lastUrl = location.href; setInterval(function() { if (location.href !== lastUrl) { lastUrl = location.href; setTimeout(tryTheater, 500); } }, 1000); // Also try on player load var observer = new MutationObserver(tryTheater); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:YouTube Theater Mode Default]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Create a Simultaneous Equation Solver Algorithm by chriso345 · Pull Request #8773 · TheAlgorithms/Python · GitHub
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5 changes: 5 additions & 0 deletions .vscode/settings.json
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,5 @@
{
"githubPullRequests.ignoredPullRequestBranches": [
"master"
]
}
142 changes: 142 additions & 0 deletions maths/simultaneous_linear_equation_solver.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,142 @@
"""
https://en.wikipedia.org/wiki/Augmented_matrix

This algorithm solves simultaneous linear equations of the form
λa + λb + λc + λd + ... = γ as [λ, λ, λ, λ, ..., γ]
Where λ & γ are individual coefficients, the no. of equations = no. of coefficients - 1

Note in order to work there must exist 1 equation where all instances of λ and γ != 0
"""


def simplify(current_set: list[list]) -> list[list]:
"""
>>> simplify([[1, 2, 3], [4, 5, 6]])
[[1.0, 2.0, 3.0], [0.0, 0.75, 1.5]]
>>> simplify([[5, 2, 5], [5, 1, 10]])
[[1.0, 0.4, 1.0], [0.0, 0.2, -1.0]]
"""
# Divide each row by magnitude of first term --> creates 'unit' matrix
duplicate_set = current_set.copy()
for row_index, row in enumerate(duplicate_set):
magnitude = row[0]
for column_index, column in enumerate(row):
if magnitude == 0:
current_set[row_index][column_index] = column
continue
current_set[row_index][column_index] = column / magnitude
# Subtract to cancel term
first_row = current_set[0]
final_set = [first_row]
current_set = current_set[1::]
for row in current_set:
temp_row = []
# If first term is 0, it is already in form we want, so we preserve it
if row[0] == 0:
final_set.append(row)
continue
for column_index in range(len(row)):
temp_row.append(first_row[column_index] - row[column_index])
final_set.append(temp_row)
# Create next recursion iteration set
if len(final_set[0]) != 3:
current_first_row = final_set[0]
current_first_column = []
next_iteration = []
for row in final_set[1::]:
current_first_column.append(row[0])
next_iteration.append(row[1::])
resultant = simplify(next_iteration)
for i in range(len(resultant)):
resultant[i].insert(0, current_first_column[i])
resultant.insert(0, current_first_row)
final_set = resultant
return final_set


def solve_simultaneous(equations: list[list]) -> list:
"""
>>> solve_simultaneous([[1, 2, 3],[4, 5, 6]])
[-1.0, 2.0]
>>> solve_simultaneous([[0, -3, 1, 7],[3, 2, -1, 11],[5, 1, -2, 12]])
[6.4, 1.2, 10.6]
>>> solve_simultaneous([])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],[1, 2]])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],["a", 7, 8]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires lists of integers
>>> solve_simultaneous([[0, 2, 3],[4, 0, 6]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires at least 1 full equation
"""
if len(equations) == 0:
raise IndexError("solve_simultaneous() requires n lists of length n+1")
_length = len(equations) + 1
if any(len(item) != _length for item in equations):
raise IndexError("solve_simultaneous() requires n lists of length n+1")
for row in equations:
if any(not isinstance(column, (int, float)) for column in row):
raise ValueError("solve_simultaneous() requires lists of integers")
if len(equations) == 1:
return [equations[0][-1] / equations[0][0]]
data_set = equations.copy()
if any(0 in row for row in data_set):
temp_data = data_set.copy()
full_row = []
for row_index, row in enumerate(temp_data):
if 0 not in row:
full_row = data_set.pop(row_index)
break
if not full_row:
raise ValueError("solve_simultaneous() requires at least 1 full equation")
data_set.insert(0, full_row)
useable_form = data_set.copy()
simplified = simplify(useable_form)
simplified = simplified[::-1]
solutions: list = []
for row in simplified:
current_solution = row[-1]
if not solutions:
if row[-2] == 0:
solutions.append(0)
continue
solutions.append(current_solution / row[-2])
continue
temp_row = row.copy()[: len(row) - 1 :]
while temp_row[0] == 0:
temp_row.pop(0)
if len(temp_row) == 0:
solutions.append(0)
continue
temp_row = temp_row[1::]
temp_row = temp_row[::-1]
for column_index, column in enumerate(temp_row):
current_solution -= column * solutions[column_index]
solutions.append(current_solution)
final = []
for item in solutions:
final.append(float(round(item, 5)))
return final[::-1]


if __name__ == "__main__":
import doctest

doctest.testmod()
eq = [
[2, 1, 1, 1, 1, 4],
[1, 2, 1, 1, 1, 5],
[1, 1, 2, 1, 1, 6],
[1, 1, 1, 2, 1, 7],
[1, 1, 1, 1, 2, 8],
]
print(solve_simultaneous(eq))
print(solve_simultaneous([[4, 2]]))
, 'i'); if (__m === '*' || __re.test(location.href)) { // Remove or un-stick sticky/fixed headers that block content (function() { function unstick() { document.querySelectorAll('header, nav, [role="banner"], .header, .navbar, .sticky, .fixed-top, [style*="position: fixed"], [style*="position:sticky"]').forEach(function(el) { if (el.style.position === 'fixed' || el.style.position === 'sticky' || getComputedStyle(el).position === 'fixed' || getComputedStyle(el).position === 'sticky') { el.style.position = 'static'; el.style.top = 'auto'; el.style.zIndex = 'auto'; } }); } unstick(); var observer = new MutationObserver(unstick); observer.observe(document.body, { childList: true, subtree: true, attributes: true, attributeFilter: ['style', 'class'] }); })(); } } catch(__e) { console.warn('[Userscript:Kill Sticky Headers]', __e); } })(); })(); Create a Simultaneous Equation Solver Algorithm by chriso345 · Pull Request #8773 · TheAlgorithms/Python · GitHub
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5 changes: 5 additions & 0 deletions .vscode/settings.json
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,5 @@
{
"githubPullRequests.ignoredPullRequestBranches": [
"master"
]
}
142 changes: 142 additions & 0 deletions maths/simultaneous_linear_equation_solver.py
Original file line numberDiff line numberDiff line change
@@ -0,0 +1,142 @@
"""
https://en.wikipedia.org/wiki/Augmented_matrix

This algorithm solves simultaneous linear equations of the form
λa + λb + λc + λd + ... = γ as [λ, λ, λ, λ, ..., γ]
Where λ & γ are individual coefficients, the no. of equations = no. of coefficients - 1

Note in order to work there must exist 1 equation where all instances of λ and γ != 0
"""


def simplify(current_set: list[list]) -> list[list]:
"""
>>> simplify([[1, 2, 3], [4, 5, 6]])
[[1.0, 2.0, 3.0], [0.0, 0.75, 1.5]]
>>> simplify([[5, 2, 5], [5, 1, 10]])
[[1.0, 0.4, 1.0], [0.0, 0.2, -1.0]]
"""
# Divide each row by magnitude of first term --> creates 'unit' matrix
duplicate_set = current_set.copy()
for row_index, row in enumerate(duplicate_set):
magnitude = row[0]
for column_index, column in enumerate(row):
if magnitude == 0:
current_set[row_index][column_index] = column
continue
current_set[row_index][column_index] = column / magnitude
# Subtract to cancel term
first_row = current_set[0]
final_set = [first_row]
current_set = current_set[1::]
for row in current_set:
temp_row = []
# If first term is 0, it is already in form we want, so we preserve it
if row[0] == 0:
final_set.append(row)
continue
for column_index in range(len(row)):
temp_row.append(first_row[column_index] - row[column_index])
final_set.append(temp_row)
# Create next recursion iteration set
if len(final_set[0]) != 3:
current_first_row = final_set[0]
current_first_column = []
next_iteration = []
for row in final_set[1::]:
current_first_column.append(row[0])
next_iteration.append(row[1::])
resultant = simplify(next_iteration)
for i in range(len(resultant)):
resultant[i].insert(0, current_first_column[i])
resultant.insert(0, current_first_row)
final_set = resultant
return final_set


def solve_simultaneous(equations: list[list]) -> list:
"""
>>> solve_simultaneous([[1, 2, 3],[4, 5, 6]])
[-1.0, 2.0]
>>> solve_simultaneous([[0, -3, 1, 7],[3, 2, -1, 11],[5, 1, -2, 12]])
[6.4, 1.2, 10.6]
>>> solve_simultaneous([])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],[1, 2]])
Traceback (most recent call last):
...
IndexError: solve_simultaneous() requires n lists of length n+1
>>> solve_simultaneous([[1, 2, 3],["a", 7, 8]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires lists of integers
>>> solve_simultaneous([[0, 2, 3],[4, 0, 6]])
Traceback (most recent call last):
...
ValueError: solve_simultaneous() requires at least 1 full equation
"""
if len(equations) == 0:
raise IndexError("solve_simultaneous() requires n lists of length n+1")
_length = len(equations) + 1
if any(len(item) != _length for item in equations):
raise IndexError("solve_simultaneous() requires n lists of length n+1")
for row in equations:
if any(not isinstance(column, (int, float)) for column in row):
raise ValueError("solve_simultaneous() requires lists of integers")
if len(equations) == 1:
return [equations[0][-1] / equations[0][0]]
data_set = equations.copy()
if any(0 in row for row in data_set):
temp_data = data_set.copy()
full_row = []
for row_index, row in enumerate(temp_data):
if 0 not in row:
full_row = data_set.pop(row_index)
break
if not full_row:
raise ValueError("solve_simultaneous() requires at least 1 full equation")
data_set.insert(0, full_row)
useable_form = data_set.copy()
simplified = simplify(useable_form)
simplified = simplified[::-1]
solutions: list = []
for row in simplified:
current_solution = row[-1]
if not solutions:
if row[-2] == 0:
solutions.append(0)
continue
solutions.append(current_solution / row[-2])
continue
temp_row = row.copy()[: len(row) - 1 :]
while temp_row[0] == 0:
temp_row.pop(0)
if len(temp_row) == 0:
solutions.append(0)
continue
temp_row = temp_row[1::]
temp_row = temp_row[::-1]
for column_index, column in enumerate(temp_row):
current_solution -= column * solutions[column_index]
solutions.append(current_solution)
final = []
for item in solutions:
final.append(float(round(item, 5)))
return final[::-1]


if __name__ == "__main__":
import doctest

doctest.testmod()
eq = [
[2, 1, 1, 1, 1, 4],
[1, 2, 1, 1, 1, 5],
[1, 1, 2, 1, 1, 6],
[1, 1, 1, 2, 1, 7],
[1, 1, 1, 1, 2, 8],
]
print(solve_simultaneous(eq))
print(solve_simultaneous([[4, 2]]))