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Fix incorrect results in BitAnd GroupsAccumulator - #6957
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Fix accumulator
BitAnd GroupsAccumulatoralambforce-pushed
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Jul 13, 2023
| GROUP BY tag | ||
| ORDER BY tag | ||
| ---- | ||
| 1 8 11 13 14 11 12 6 11 A |
ContributorAuthor
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before this PR, this test fails like
External error: query result mismatch:
[SQL] SELECT
bit_and(c1),
bit_and(c2),
bit_and(c3),
bit_or(c1),
bit_or(c2),
bit_or(c3),
bit_xor(c1),
bit_xor(c2),
bit_xor(c3),
tag
FROM bit_aggregate_functions
GROUP BY tag
ORDER BY tag
[Diff] (-expected|+actual)
- 1 8 11 13 14 11 12 6 11 A
- 33 11 NULL 33 11 NULL 33 11 NULL B
+ 0 0 0 13 14 11 12 6 11 A
+ 0 0 NULL 33 11 NULL 33 11 NULL B
at tests/sqllogictests/test_files/aggregate.slt:1546
| DataType::Int8 => { | ||
| instantiate_primitive_accumulator!(self, Int8Type, |x, y| x | ||
| .bitand_assign(y)) | ||
| instantiate_accumulator!(self, -1, Int8Type, |x, y| x.bitand_assign(y)) |
ContributorAuthor
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the fix is passing in MAX / -1 here to get a bitpattern of all 1 initially
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The fix looks good. It's better to leave a comment like above in the code.
| let values = values[0].as_primitive::<T>(); | ||
| // update values | ||
| self.values.resize(total_num_groups, T::default_value()); |
ContributorAuthor
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previously this always started at zero, now it starts at the specified value.
I think I can now reduce the code in min/max accumulator as well
alamb
marked this pull request as ready for review
July 13, 2023 16:06
viirya
approved these changes
Jul 13, 2023
alamb
commented
Jul 13, 2023
ContributorAuthor
🤔 seems clippy failure is unrelated. I will fix that |
alamb
commented
Jul 13, 2023
ContributorAuthor
Clippy fixes in #6959 |
alamb
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Jul 13, 2023
ContributorAuthor
This was referenced Jul 13, 2023
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Which issue does this PR close?
Resolves#6955, a bug introduced in #6904
Rationale for this change
The answer is incorrect because the starting value is always 0 and thus
0 &anything else will also be zero which is not rightWhat changes are included in this PR?
bit_andAre these changes tested?
Yes
Are there any user-facing changes?