Bug: when active field in users table is false users can login #459

Description

@datamweb

PHP Version

8.1.5

CodeIgniter4 Version

4.2.5

Shield Version

dev

Which operating systems have you tested for this bug?

Windows

Which server did you use?

apache

Database

MySQL 5.6

Did you customize Shield?

No.

What happened?

The login operation for a user who is not active is completed successfully. In general, a user who is not active for any reason should not login to the system.

Steps to Reproduce

  1. Register a new user.
  2. Change the value of active true to false.
  3. Perform the login operation.
  4. A user who is inactive login without a problem!!

Expected Output

Failure of the user login to the system and display the error message "Your account is inactive".

Anything else?

see https://forum.codeigniter.com/showthread.php?tid=83481

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No one assigned

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    No projects

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      None yet

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      No branches or pull requests

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      , 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Add copy buttons to all
       blocks\n(function() {\n function addCopyButtons() {\n document.querySelectorAll('pre code').forEach(function(codeBlock) {\n if (codeBlock.parentElement.hasAttribute('data-copy-added')) return;\n codeBlock.parentElement.setAttribute('data-copy-added', 'true');\n \n var btn = document.createElement('button');\n btn.textContent = 'Copy';\n btn.style.cssText = 'position:absolute;top:4px;right:4px;padding:2px 8px;font-size:11px;background:#4ecdc4;border:none;border-radius:4px;color:#1a1a2e;cursor:pointer;opacity:0.7;transition:opacity 0.2s;';\n btn.onmouseover = function() { this.style.opacity = '1'; };\n btn.onmouseout = function() { this.style.opacity = '0.7'; };\n btn.onclick = function() {\n navigator.clipboard.writeText(codeBlock.textContent).then(function() {\n btn.textContent = 'Copied!';\n setTimeout(function() { btn.textContent = 'Copy'; }, 1500);\n });\n };\n codeBlock.parentElement.style.position = 'relative';\n codeBlock.parentElement.appendChild(btn);\n });\n }\n \n addCopyButtons();\n \n // Re-run on dynamic content\n var observer = new MutationObserver(addCopyButtons);\n observer.observe(document.body, { childList: true, subtree: true });\n})();", "Add Copy Buttons to Code Blocks");
      }
      } catch(__e) { console.warn('[Userscript:Add Copy Buttons to Code Blocks]', __e); }
      })();
      (function(){
      try {
      var __m = "github.com";
      var __re = new RegExp('^' + "github\\.com" + '
      
      Skip to content

      Bug: when active field in users table is false users can login #459

      Description

      @datamweb

      PHP Version

      8.1.5

      CodeIgniter4 Version

      4.2.5

      Shield Version

      dev

      Which operating systems have you tested for this bug?

      Windows

      Which server did you use?

      apache

      Database

      MySQL 5.6

      Did you customize Shield?

      No.

      What happened?

      The login operation for a user who is not active is completed successfully. In general, a user who is not active for any reason should not login to the system.

      Steps to Reproduce

      1. Register a new user.
      2. Change the value of active true to false.
      3. Perform the login operation.
      4. A user who is inactive login without a problem!!

      Expected Output

      Failure of the user login to the system and display the error message "Your account is inactive".

      Anything else?

      see https://forum.codeigniter.com/showthread.php?tid=83481

      Metadata

      Metadata

      Assignees

      No one assigned

        Labels

        enhancementNew feature or request

        Type

        No type

        Projects

        No projects

          Milestone

          No milestone

          Relationships

          None yet

          Development

          No branches or pull requests

          Issue actions

          , 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Force GitHub README to respect dark mode\n(function() {\n var style = document.createElement('style');\n style.textContent = '\n .markdown-body {\n color-scheme: dark light;\n }\n .markdown-body pre { background: #161b22 !important; }\n .markdown-body code { background: rgba(110, 118, 129, 0.4) !important; }\n .markdown-body table th, .markdown-body table td { border-color: #30363d !important; }\n .markdown-body img { background: #0d1117; }\n .markdown-body blockquote { border-left-color: #8b949e; }\n .markdown-body hr { border-color: #30363d; }\n ';\n document.head.appendChild(style);\n})();", "GitHub Dark Mode README Fix"); } } catch(__e) { console.warn('[Userscript:GitHub Dark Mode README Fix]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + '
          Skip to content

          Bug: when active field in users table is false users can login #459

          Description

          @datamweb

          PHP Version

          8.1.5

          CodeIgniter4 Version

          4.2.5

          Shield Version

          dev

          Which operating systems have you tested for this bug?

          Windows

          Which server did you use?

          apache

          Database

          MySQL 5.6

          Did you customize Shield?

          No.

          What happened?

          The login operation for a user who is not active is completed successfully. In general, a user who is not active for any reason should not login to the system.

          Steps to Reproduce

          1. Register a new user.
          2. Change the value of active true to false.
          3. Perform the login operation.
          4. A user who is inactive login without a problem!!

          Expected Output

          Failure of the user login to the system and display the error message "Your account is inactive".

          Anything else?

          see https://forum.codeigniter.com/showthread.php?tid=83481

          Metadata

          Metadata

          Assignees

          No one assigned

            Labels

            enhancementNew feature or request

            Type

            No type

            Projects

            No projects

              Milestone

              No milestone

              Relationships

              None yet

              Development

              No branches or pull requests

              Issue actions

              , 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Highlight search terms from Google/DuckDuckGo/Bing referrer\n(function() {\n var ref = document.referrer;\n var terms = [];\n \n if (ref.includes('google.com') || ref.includes('duckduckgo.com') || ref.includes('bing.com')) {\n var url = new URL(ref);\n var q = url.searchParams.get('q') || url.searchParams.get('p');\n if (q) {\n terms = q.split(/\\s+/).filter(function(t) { return t.length > 2; });\n }\n }\n \n if (terms.length === 0) return;\n \n var style = document.createElement('style');\n style.textContent = '.userscript-highlight { background: #fbbf24; color: #1a1a2e; padding: 1px 3px; border-radius: 2px; }';\n document.head.appendChild(style);\n \n function highlight(node) {\n if (node.nodeType === 3) { // text node\n var text = node.textContent;\n var found = false;\n terms.forEach(function(term) {\n var regex = new RegExp('(' + term.replace(/[.*+?^${}()|[\\]\\\\]/g, '\\\\') + ')', 'gi');\n if (regex.test(text)) {\n found = true;\n var frag = document.createDocumentFragment();\n var parts = text.split(regex);\n parts.forEach(function(part, i) {\n if (i % 2 === 0) {\n frag.appendChild(document.createTextNode(part));\n } else {\n var span = document.createElement('span');\n span.className = 'userscript-highlight';\n span.textContent = part;\n frag.appendChild(span);\n }\n });\n node.parentNode.replaceChild(frag, node);\n }\n });\n } else if (node.nodeType === 1 && node.childNodes) { // element\n var skipTags = ['SCRIPT', 'STYLE', 'NOSCRIPT', 'TEXTAREA', 'INPUT', 'SELECT'];\n if (!skipTags.includes(node.tagName)) {\n Array.from(node.childNodes).forEach(highlight);\n }\n }\n }\n \n highlight(document.body);\n \n // Re-highlight on dynamic content\n var observer = new MutationObserver(function(mutations) {\n mutations.forEach(function(m) {\n m.addedNodes.forEach(function(node) {\n if (node.nodeType === 1 || node.nodeType === 3) highlight(node);\n });\n });\n });\n observer.observe(document.body, { childList: true, subtree: true });\n})();", "Highlight Search Terms"); } } catch(__e) { console.warn('[Userscript:Highlight Search Terms]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + '
              Skip to content

              Bug: when active field in users table is false users can login #459

              Description

              @datamweb

              PHP Version

              8.1.5

              CodeIgniter4 Version

              4.2.5

              Shield Version

              dev

              Which operating systems have you tested for this bug?

              Windows

              Which server did you use?

              apache

              Database

              MySQL 5.6

              Did you customize Shield?

              No.

              What happened?

              The login operation for a user who is not active is completed successfully. In general, a user who is not active for any reason should not login to the system.

              Steps to Reproduce

              1. Register a new user.
              2. Change the value of active true to false.
              3. Perform the login operation.
              4. A user who is inactive login without a problem!!

              Expected Output

              Failure of the user login to the system and display the error message "Your account is inactive".

              Anything else?

              see https://forum.codeigniter.com/showthread.php?tid=83481

              Metadata

              Metadata

              Assignees

              No one assigned

                Labels

                enhancementNew feature or request

                Type

                No type

                Projects

                No projects

                  Milestone

                  No milestone

                  Relationships

                  None yet

                  Development

                  No branches or pull requests

                  Issue actions

                  , 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Strip utm_, fbclid, gclid, etc. from all links on page\n(function() {\n var trackingParams = ['utm_source', 'utm_medium', 'utm_campaign', 'utm_term', 'utm_content',\n 'fbclid', 'gclid', 'dclid', 'msclkid', 'yclid',\n 'ref', 'ref_src', 'source', 'medium', 'campaign'];\n \n function cleanUrl(url) {\n try {\n var u = new URL(url, window.location.origin);\n var changed = false;\n trackingParams.forEach(function(p) {\n if (u.searchParams.has(p)) {\n u.searchParams.delete(p);\n changed = true;\n }\n });\n return changed ? u.toString() : url;\n } catch (e) {\n return url;\n }\n }\n \n function cleanLinks() {\n document.querySelectorAll('a[href]').forEach(function(a) {\n var clean = cleanUrl(a.href);\n if (clean !== a.href) a.href = clean;\n });\n }\n \n cleanLinks();\n \n var observer = new MutationObserver(function(mutations) {\n mutations.forEach(function(m) {\n m.addedNodes.forEach(function(node) {\n if (node.nodeType === 1) {\n if (node.tagName === 'A') cleanLinks();\n node.querySelectorAll('a[href]').forEach(function(a) {\n var clean = cleanUrl(a.href);\n if (clean !== a.href) a.href = clean;\n });\n }\n });\n });\n });\n observer.observe(document.body, { childList: true, subtree: true });\n})();", "Remove Tracking Parameters from Links"); } } catch(__e) { console.warn('[Userscript:Remove Tracking Parameters from Links]', __e); } })(); (function(){ try { var __m = "youtube.com"; var __re = new RegExp('^' + "youtube\\.com" + '
                  Skip to content

                  Bug: when active field in users table is false users can login #459

                  Description

                  @datamweb

                  PHP Version

                  8.1.5

                  CodeIgniter4 Version

                  4.2.5

                  Shield Version

                  dev

                  Which operating systems have you tested for this bug?

                  Windows

                  Which server did you use?

                  apache

                  Database

                  MySQL 5.6

                  Did you customize Shield?

                  No.

                  What happened?

                  The login operation for a user who is not active is completed successfully. In general, a user who is not active for any reason should not login to the system.

                  Steps to Reproduce

                  1. Register a new user.
                  2. Change the value of active true to false.
                  3. Perform the login operation.
                  4. A user who is inactive login without a problem!!

                  Expected Output

                  Failure of the user login to the system and display the error message "Your account is inactive".

                  Anything else?

                  see https://forum.codeigniter.com/showthread.php?tid=83481

                  Metadata

                  Metadata

                  Assignees

                  No one assigned

                    Labels

                    enhancementNew feature or request

                    Type

                    No type

                    Projects

                    No projects

                      Milestone

                      No milestone

                      Relationships

                      None yet

                      Development

                      No branches or pull requests

                      Issue actions

                      , 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Auto-enable theater mode on YouTube\n(function() {\n function tryTheater() {\n var btn = document.querySelector('button[aria-label=\"Theater mode\"], ytd-player #player button[title=\"Theater mode\"]');\n if (btn && !btn.classList.contains('activated')) {\n btn.click();\n }\n }\n \n // Try immediately\n tryTheater();\n \n // Try after navigation (SPA)\n var lastUrl = location.href;\n setInterval(function() {\n if (location.href !== lastUrl) {\n lastUrl = location.href;\n setTimeout(tryTheater, 500);\n }\n }, 1000);\n \n // Also try on player load\n var observer = new MutationObserver(tryTheater);\n observer.observe(document.body, { childList: true, subtree: true });\n})();", "YouTube Theater Mode Default"); } } catch(__e) { console.warn('[Userscript:YouTube Theater Mode Default]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + '
                      Skip to content

                      Bug: when active field in users table is false users can login #459

                      Description

                      @datamweb

                      PHP Version

                      8.1.5

                      CodeIgniter4 Version

                      4.2.5

                      Shield Version

                      dev

                      Which operating systems have you tested for this bug?

                      Windows

                      Which server did you use?

                      apache

                      Database

                      MySQL 5.6

                      Did you customize Shield?

                      No.

                      What happened?

                      The login operation for a user who is not active is completed successfully. In general, a user who is not active for any reason should not login to the system.

                      Steps to Reproduce

                      1. Register a new user.
                      2. Change the value of active true to false.
                      3. Perform the login operation.
                      4. A user who is inactive login without a problem!!

                      Expected Output

                      Failure of the user login to the system and display the error message "Your account is inactive".

                      Anything else?

                      see https://forum.codeigniter.com/showthread.php?tid=83481

                      Metadata

                      Metadata

                      Assignees

                      No one assigned

                        Labels

                        enhancementNew feature or request

                        Type

                        No type

                        Projects

                        No projects

                          Milestone

                          No milestone

                          Relationships

                          None yet

                          Development

                          No branches or pull requests

                          Issue actions

                          , 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Remove or un-stick sticky/fixed headers that block content\n(function() {\n function unstick() {\n document.querySelectorAll('header, nav, [role=\"banner\"], .header, .navbar, .sticky, .fixed-top, [style*=\"position: fixed\"], [style*=\"position:sticky\"]').forEach(function(el) {\n if (el.style.position === 'fixed' || el.style.position === 'sticky' || \n getComputedStyle(el).position === 'fixed' || getComputedStyle(el).position === 'sticky') {\n el.style.position = 'static';\n el.style.top = 'auto';\n el.style.zIndex = 'auto';\n }\n });\n }\n \n unstick();\n \n var observer = new MutationObserver(unstick);\n observer.observe(document.body, { childList: true, subtree: true, attributes: true, attributeFilter: ['style', 'class'] });\n})();", "Kill Sticky Headers"); } } catch(__e) { console.warn('[Userscript:Kill Sticky Headers]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + '
                          Skip to content

                          Bug: when active field in users table is false users can login #459

                          Description

                          @datamweb

                          PHP Version

                          8.1.5

                          CodeIgniter4 Version

                          4.2.5

                          Shield Version

                          dev

                          Which operating systems have you tested for this bug?

                          Windows

                          Which server did you use?

                          apache

                          Database

                          MySQL 5.6

                          Did you customize Shield?

                          No.

                          What happened?

                          The login operation for a user who is not active is completed successfully. In general, a user who is not active for any reason should not login to the system.

                          Steps to Reproduce

                          1. Register a new user.
                          2. Change the value of active true to false.
                          3. Perform the login operation.
                          4. A user who is inactive login without a problem!!

                          Expected Output

                          Failure of the user login to the system and display the error message "Your account is inactive".

                          Anything else?

                          see https://forum.codeigniter.com/showthread.php?tid=83481

                          Metadata

                          Metadata

                          Assignees

                          No one assigned

                            Labels

                            enhancementNew feature or request

                            Type

                            No type

                            Projects

                            No projects

                              Milestone

                              No milestone

                              Relationships

                              None yet

                              Development

                              No branches or pull requests

                              Issue actions

                              , 'i'); if (__m === '*' || __re.test(location.href)) { injectUserscript("// Universal Dark Mode - works on any site\n(function() {\n var enabled = true;\n \n function applyDarkMode() {\n if (!enabled) return;\n \n // Create style element if it doesn't exist\n var style = document.getElementById('universal-dark-mode-style');\n if (!style) {\n style = document.createElement('style');\n style.id = 'universal-dark-mode-style';\n document.head.appendChild(style);\n }\n \n // Dark mode CSS - inverts colors but preserves images/video\n style.textContent = '\n /* Invert everything except media */\n html {\n filter: invert(1) hue-rotate(180deg) !important;\n background: #1a1a2e !important;\n }\n \n /* Restore images, videos, iframes, canvas */\n img, video, iframe, canvas, svg, picture, [style*=\"background-image\"] {\n filter: invert(1) hue-rotate(180deg) !important;\n }\n \n /* Preserve specific elements that should not be inverted */\n .no-dark-mode, .no-dark-mode *,\n [data-theme=\"light\"], [data-theme=\"light\"],\n .ace_editor, .ace_editor *,\n .CodeMirror, .CodeMirror *,\n .monaco-editor, .monaco-editor *,\n .markdown-body pre, .markdown-body pre *,\n .highlight, .highlight *,\n pre code, pre code * {\n filter: none !important;\n }\n \n /* Fix common UI elements */\n .modal, .popup, .dropdown-menu, .tooltip, .popover {\n filter: invert(1) hue-rotate(180deg) !important;\n background: #2d2d44 !important;\n border-color: #444 !important;\n }\n \n /* Scrollbars */\n ::-webkit-scrollbar { background: #1a1a2e !important; }\n ::-webkit-scrollbar-thumb { background: #444 !important; }\n ::-webkit-scrollbar-thumb:hover { background: #555 !important; }\n \n /* Selection */\n ::selection { background: #4ecdc4 !important; color: #1a1a2e !important; }\n ::-moz-selection { background: #4ecdc4 !important; color: #1a1a2e !important; }\n ';\n }\n \n function removeDarkMode() {\n var style = document.getElementById('universal-dark-mode-style');\n if (style) style.remove();\n }\n \n // Toggle with Alt+Shift+D\n document.addEventListener('keydown', function(e) {\n if (e.altKey && e.shiftKey && e.key === 'D') {\n e.preventDefault();\n enabled = !enabled;\n if (enabled) {\n applyDarkMode();\n console.log('[Universal Dark Mode] Enabled');\n } else {\n removeDarkMode();\n console.log('[Universal Dark Mode] Disabled');\n }\n }\n });\n \n // Apply on load\n applyDarkMode();\n \n // Re-apply on dynamic content\n var observer = new MutationObserver(function(mutations) {\n if (enabled && !document.getElementById('universal-dark-mode-style')) {\n applyDarkMode();\n }\n });\n observer.observe(document.head, { childList: true });\n \n console.log('[Universal Dark Mode] Loaded - Press Alt+Shift+D to toggle');\n})();", "Universal Dark Mode"); } } catch(__e) { console.warn('[Userscript:Universal Dark Mode]', __e); } })(); })();
                              Skip to content

                              Bug: when active field in users table is false users can login #459

                              Description

                              @datamweb

                              PHP Version

                              8.1.5

                              CodeIgniter4 Version

                              4.2.5

                              Shield Version

                              dev

                              Which operating systems have you tested for this bug?

                              Windows

                              Which server did you use?

                              apache

                              Database

                              MySQL 5.6

                              Did you customize Shield?

                              No.

                              What happened?

                              The login operation for a user who is not active is completed successfully. In general, a user who is not active for any reason should not login to the system.

                              Steps to Reproduce

                              1. Register a new user.
                              2. Change the value of active true to false.
                              3. Perform the login operation.
                              4. A user who is inactive login without a problem!!

                              Expected Output

                              Failure of the user login to the system and display the error message "Your account is inactive".

                              Anything else?

                              see https://forum.codeigniter.com/showthread.php?tid=83481

                              Metadata

                              Metadata

                              Assignees

                              No one assigned

                                Labels

                                enhancementNew feature or request

                                Type

                                No type

                                Projects

                                No projects

                                  Milestone

                                  No milestone

                                  Relationships

                                  None yet

                                  Development

                                  No branches or pull requests

                                  Issue actions