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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,18 @@ | ||
| { | ||
| "introduction": { | ||
| "authors": [ | ||
| "MatthijsBlom" | ||
| ] | ||
| }, | ||
| "approaches": [ | ||
| { | ||
| "uuid": "7dd85d5b-12bd-48a6-97fe-8eb7dd87af72", | ||
| "slug": "filter-for-multiples", | ||
| "title": "Filter for multiples", | ||
| "blurb": "Use the built-in filter function to select the numbers that are multiples, then sum these.", | ||
| "authors": [ | ||
| "MatthijsBlom" | ||
| ] | ||
| } | ||
| ] | ||
| } |
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,253 @@ | ||
| # `filter` for multiples | ||
| ```python | ||
| def sum_of_multiples(limit, factors): | ||
| return sum(filter( | ||
| lambda n: any(n % f == 0 for f in factors if f != 0), | ||
| range(limit) | ||
| )) | ||
| ``` | ||
| Probably the most straightforward way of solving this problem is to | ||
| 1. look at every individual integer between `0` and `limit`, | ||
| 2. check that it is a multiple of any of the given `factors`, and | ||
| 3. add it to the sum when it is. | ||
| ## Notable language features used in this solution | ||
| ### Built-in function: `sum` | ||
| Adding all the numbers in a collection together is a very common operation. | ||
| Therefore, Python provides the built-in function [`sum`][builtin-sum]. | ||
| `sum` takes one argument, and requires that it be **iterable**. | ||
| A value is iterable whenever it makes sense to use it in a `for` loop like this: | ||
| ```python | ||
| for element in iterable_value: # 👈 | ||
| ... | ||
| ``` | ||
| The `list` is the most commonly used iterable data structure. | ||
| Many other containers are also iterable, such as `set`s, `tuple`s, `range`s, and even `dict`s and `str`ings. | ||
| Still other examples include iterators and generators, which are discussed below. | ||
| When given a collection of numbers, `sum` will look at the elements one by one and add them up. | ||
| The result is a single number. | ||
| ```python | ||
| numbers = range(1, 100 + 1) # 1, 2, …, 100 | ||
| sum(numbers) # ⟹ 5050 | ||
| ``` | ||
| Had the highlighted solution not used `sum`, it might have looked like this: | ||
| ```python | ||
| def sum_of_multiples(limit, factors): | ||
| multiples = filter( | ||
| lambda n: any(n % f == 0 for f in factors if f != 0), | ||
| range(limit)) | ||
| total = 0 | ||
| for multiple in multiples: | ||
| total += multiple | ||
| return total | ||
| ``` | ||
| ### Built-in function: `filter` | ||
| Selecting elements of a collection for having a certain property is also a very common operation. | ||
| Therefore, Python provides the built-in function [`filter`][builtin-filter]. | ||
| `filter` takes two arguments. | ||
| The first is a **predicate**. | ||
| The second is the iterable the elements of which should be filtered. | ||
| A predicate is a function that takes one argument (of any particular type) and returns a `bool`. | ||
| Such functions are commonly used to encode properties of values. | ||
| An example is `str.isupper`, which takes a `str` and returns `True` whenever it is uppercase: | ||
| ```python | ||
| str.isupper("AAAAH! 😱") # ⟹ True | ||
| str.isupper("Eh? 😕") # ⟹ False | ||
| str.isupper("⬆️💼") # ⟹ False | ||
| ``` | ||
| Thus, the function `str.isupper` represents the property of _being an uppercase string_. | ||
| Contrary to what you might expect, `filter` does not return a data structure like the one given as the iterable argument: | ||
| ```python | ||
| filter(str.isupper, ["THUNDERBOLTS", "and", "LIGHTNING"]) | ||
| # ⟹ <filter object at 0x000002F46B107BE0> | ||
| ``` | ||
| Instead, it returns an **iterator**. | ||
| An iterator is an object whose sole purpose is to guide iteration through some data structure. | ||
| In particular, `filter` makes sure that elements that do not satisfy the predicate are skipped: | ||
| ```python | ||
| for word in filter(str.isupper, ["THUNDERBOLTS", "and", "LIGHTNING"]): | ||
| print(word) | ||
| # prints: | ||
| # THUNDERBOLTS | ||
| # LIGHTNING | ||
| ``` | ||
| An iterator is a bit like a cursor that can move only to the right. | ||
| The main differences between containers (such as `list`s) and iterators are | ||
| - Containers can, depending on their contents, take up a lot of space in memory, but iterators are typically very small regardless of how many elements they 'contain'. | ||
| - Containers can be iterated over multiple times, but iterators can be used only once. | ||
| To illustrate the latter difference: | ||
| ```python | ||
| def is_even(n): | ||
| return n % 2 == 0 | ||
| numbers = range(20) # 0, 1, …, 19 | ||
| even_numbers = filter(is_even, numbers) # 0, 2, …, 18 | ||
| sum(numbers) # ⟹ 190 | ||
| sum(numbers) # ⟹ 190 | ||
| sum(even_numbers) # ⟹ 90 | ||
| sum(even_numbers) # ⟹ 0 | ||
| ``` | ||
| Here, `sum` iterates over both `numbers` and `even_numbers` twice. | ||
| In the case of `numbers` everything is fine. | ||
| Even after looping through the whole of `numbers`, all its elements are still there, and so `sum` can ask to see them again without problem. | ||
| The situation with `even_numbers` is less simple. | ||
| To use the _cursor_ analogy: after going through all of `even_number`'s 'elements' – actually elements of `numbers` – the cursor has moved all the way to the right. | ||
| It cannot move backwards, so if you wish to iterate over all even numbers again then you need a new cursor. | ||
| We say that the `even_numbers` iterator is _exhausted_. When `sum` asks for its elements again, `even_numbers` comes up empty and so `sum` returns `0`. | ||
| Had the highlighted solution not used `filter`, it might have looked like this: | ||
| ```python | ||
| def sum_of_multiples(limit, factors): | ||
| def is_multiple(n): | ||
| return any(n % f == 0 for f in factors if f != 0) | ||
| multiples = [candidate for candidate in range(limit) if is_multiple(candidate)] | ||
| return sum(multiples) | ||
| ``` | ||
| This variant stores all the multiples in a `list` before summing them. | ||
| Such a list can become very big. | ||
| For example, if `limit = 1_000_000_000` and `factors = [1]` then `multiples` will take up 8 gigabytes of memory! | ||
| It is to avoid unnecessarily creating such large intermediate data structures that iterators are often used. | ||
| ### A function expression: `lambda` | ||
| Typically, when using higher-order functions like `filter` and `map`, the function to pass as an argument does not yet exist and needs to be defined first. | ||
| The standard way of defining functions is through the `def` statement: | ||
| ```python | ||
| def name(parameters): | ||
| statements | ||
| ``` | ||
| Downsides of this construct include | ||
| - the syntax can be a bit bulky | ||
| - it requires coming up with a fresh name | ||
| These qualities can be quite bothersome when you just need a simple function of no particular significance for single use only. | ||
| In situations like this you might like to use a **lambda expression** instead. | ||
| A lambda expression is a specific kind of expression that evaluates to a function. | ||
| It looks like this: | ||
| ```python | ||
| lambda parameters: expression # general form | ||
| lambda a, b, x: a * x + b # specific example | ||
| ``` | ||
| This latter lambda expression evaluates to a function that takes three arguments (`a`, `b`, `x`) and returns the value `a * x + b`. | ||
| Except for not having a name, it is equivalent to the function defined by | ||
| ```python | ||
| def some_name(a, b, x): | ||
| return a * x + b | ||
| ``` | ||
| A lambda expression need not necessarily be passed as an argument. | ||
| It can also be applied to arguments immediately, or assigned to a variable: | ||
BethanyG marked this conversation as resolved.
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| ```python | ||
| lambda a, b, x: a * x + b | ||
| # ⟹ <function <lambda> at 0x000001F36A274CC0> | ||
| (lambda a, b, x: a * x + b)(2, 3, 5) | ||
| # ⟹ 13 | ||
| some_function = lambda a, b, x: a * x + b | ||
| some_function(2, 3, 5) | ||
| # ⟹ 13 | ||
| list(filter( | ||
| lambda s: len(s) <= 3, | ||
| ["aaaa", "b", "ccccc", "dd", "eee"] | ||
| )) | ||
| # ⟹ ['b', 'dd', 'eee'] | ||
| ``` | ||
| ~~~~exercism/note | ||
| Immediately applying a lambda expression is possible, but generally pointless: | ||
| ```python | ||
| # Instead of | ||
| (lambda a, b, x: a * x + b)(2, 3, y) | ||
| # you might as well write | ||
| 2 * y + 3 | ||
| ``` | ||
| ~~~~ | ||
MatthijsBlom marked this conversation as resolved.
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| ~~~~exercism/caution | ||
| Assigning a lambda expressions to variables is unidiomatic. | ||
| When you want to give a lambda expression a name, use `def` instead. | ||
| ~~~~ | ||
| Only functions that can be defined using a single (`return`) statement can be written as a lambda expression. | ||
| If you need multiple statements, you have no choice but to use `def`. | ||
| Had the highlighted solution not used `lambda`, it might have looked like this: | ||
| ```python | ||
| def sum_of_multiples(limit, factors): | ||
| def is_multiple(n): | ||
| return any(n % f == 0 for f in factors if f != 0) | ||
| return sum(filter(is_multiple, range(limit))) | ||
| ``` | ||
| ### Built-in function: `any` | ||
| ... | ||
| ### A generator expression | ||
| ... | ||
| ## Reflections on this approach | ||
| An important advantage of this approach is that it is very easy to understand. | ||
| However, it suffers from potentially performing a lot of unnecessary work, for example when all `factors` are large, or when there are no `factors` at all. | ||
| <!-- TODO elaborate --> | ||
| [builtin-sum]: https://docs.python.org/3/library/functions.html#sum "Built-in Functions: sum" | ||
| [builtin-filter]: https://docs.python.org/3/library/functions.html#filter "Built-in Functions: filter" | ||
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,5 @@ | ||
| def sum_of_multiples(limit, factors): | ||
| return sum(filter( | ||
| lambda n: any(n % f == 0 for f in factors if f != 0), | ||
| range(limit) | ||
| )) |
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I really like this explanation. Both from a cursor for typing ... and a cursor from a DB. Both can only be gone through once, and you can't back up. 😄