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feat(browser): Simplify stack parsers#7897

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Merged
AbhiPrasad merged 1 commit into from
Apr 19, 2023
Merged

feat(browser): Simplify stack parsers #7897

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7 changes: 3 additions & 4 deletions packages/browser/src/stack-parsers.ts
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Original file line numberDiff line numberDiff line change
Expand Up@@ -55,7 +55,7 @@ function createFrame(filename: string, func: string, lineno?: number, colno?: nu

// Chromium based browsers: Chrome, Brave, new Opera, new Edge
const chromeRegex =
/^\s*at (?:(.*\).*?|.*?) ?\((?:address at )?)?(?:async )?((?:file|https?|blob|chrome-extension|address|native|eval|webpack|<anonymous>|[-a-z]+:|.*bundle|\/)?.*?)(?::(\d+))?(?::(\d+))?\)?\s*$/i;
/^\s*at (?:(.*\).*?|.*?) ?\((?:address at )?)?(?:async )?((?:<anonymous>|[-a-z]+:|.*bundle|\/)?.*?)(?::(\d+))?(?::(\d+))?\)?\s*$/i;
const chromeEvalRegex = /\((\S*)(?::(\d+))(?::(\d+))\)/;

const chrome: StackLineParserFn = line => {
Expand DownExpand Up@@ -91,7 +91,7 @@ export const chromeStackLineParser: StackLineParser = [CHROME_PRIORITY, chrome];
// generates filenames without a prefix like `file://` the filenames in the stacktrace are just 42.js
// We need this specific case for now because we want no other regex to match.
const geckoREgex =
/^\s*(.*?)(?:\((.*?)\))?(?:^|@)?((?:file|https?|blob|chrome|webpack|resource|moz-extension|safari-extension|safari-web-extension|capacitor)?:\/.*?|\[native code\]|[^@]*(?:bundle|\d+\.js)|\/[\w\-. /=]+)(?::(\d+))?(?::(\d+))?\s*$/i;
/^\s*(.*?)(?:\((.*?)\))?(?:^|@)?((?:[-a-z]+)?:\/.*?|\[native code\]|[^@]*(?:bundle|\d+\.js)|\/[\w\-. /=]+)(?::(\d+))?(?::(\d+))?\s*$/i;
const geckoEvalRegex = /(\S+) line (\d+)(?: > eval line \d+)* > eval/i;

const gecko: StackLineParserFn = line => {
Expand DownExpand Up@@ -123,8 +123,7 @@ const gecko: StackLineParserFn = line => {

export const geckoStackLineParser: StackLineParser = [GECKO_PRIORITY, gecko];

const winjsRegex =
/^\s*at (?:((?:\[object object\])?.+) )?\(?((?:file|ms-appx|https?|webpack|blob):.*?):(\d+)(?::(\d+))?\)?\s*$/i;
const winjsRegex = /^\s*at (?:((?:\[object object\])?.+) )?\(?((?:[-a-z]+):.*?):(\d+)(?::(\d+))?\)?\s*$/i;

const winjs: StackLineParserFn = line => {
const parts = winjsRegex.exec(line);
Expand Down