@mhoemmen
I was looking at this and it seems to me this is wrong?
Scalar scale = init.scaling_factor;
Scalar ssq = init.scaled_sum_of_squares;
for (extents<>::size_type i = 0; i < x.extent(0); ++i) {
if (abs(x(i)) != 0.0) {
const auto absxi = abs(x(i));
const auto quotient = scale / absxi;
if (scale < absxi) {
ssq = Scalar(1.0) + ssq * quotient * quotient;
scale = absxi;
}
else {
ssq = ssq + quotient * quotient;
}
}
}
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why does scale change along the way?
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also, shouldn't scale / absxi; instead be absxi/scale? Looking at the spec, section 16.9.2.7:
Constraints: For all i in the domain of v, and for f and ssq of type T, the expression ssq = ssq + (abs(x[i]) / f)*(abs(x[i]) / f) is well formed.
It says abs(x[i])/f should be well-formed, but not f/abs(x[i]).
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also, if things are correct, in theory one should have that:
scaling_factor * scaling_factor * scaled_sum_of_squares = sum of squares of abs(x[i]) plus init.scaling_factor *
init.scaling_factor * init.scaled_sum_of_squares.
see dlassq. But that does not work for the impl above.
So i tried something on my end:
{
using std::abs;
using std::max;
T scale = init.scaling_factor;
for (std::size_t i = 0; i < x.extent(0); ++i) {
scale = max(scale, abs(x(i)));
}
T ssq = (init.scaling_factor*init.scaling_factor*init.scaled_sum_of_squares)/(scale*scale);
T s= {};
for (std::size_t i = 0; i < x.extent(0); ++i) {
const auto absxi = abs(x(i));
const auto quotient = absxi/scale;
ssq = ssq + quotient * quotient;
s += absxi*absxi;
}
std::experimental::linalg::sum_of_squares_result<T> result;
result.scaled_sum_of_squares = ssq;
result.scaling_factor = scale;
// verify that things are consistent according to definition
const auto lhs = scale*scale*ssq;
const auto rhs = s+init.scaling_factor*init.scaling_factor*init.scaled_sum_of_squares;
std::cout << lhs << " " << rhs << '\n';
EXPECT_NEAR(lhs, rhs, 1e-9);
}
and this works, in the sense that it satisfies:
scaling_factor * scaling_factor * scaled_sum_of_squares = sum of squares of abs(x[i]) plus init.scaling_factor *
init.scaling_factor * init.scaled_sum_of_squares.
@mhoemmen
I was looking at this and it seems to me this is wrong?
why does scale change along the way?
also, shouldn't
scale / absxi;instead beabsxi/scale? Looking at the spec, section 16.9.2.7:It says
abs(x[i])/fshould be well-formed, but notf/abs(x[i]).also, if things are correct, in theory one should have that:
scaling_factor * scaling_factor * scaled_sum_of_squares = sum of squares of abs(x[i]) plus init.scaling_factor * init.scaling_factor * init.scaled_sum_of_squares.see dlassq. But that does not work for the impl above.
So i tried something on my end:
{ using std::abs; using std::max; T scale = init.scaling_factor; for (std::size_t i = 0; i < x.extent(0); ++i) { scale = max(scale, abs(x(i))); } T ssq = (init.scaling_factor*init.scaling_factor*init.scaled_sum_of_squares)/(scale*scale); T s= {}; for (std::size_t i = 0; i < x.extent(0); ++i) { const auto absxi = abs(x(i)); const auto quotient = absxi/scale; ssq = ssq + quotient * quotient; s += absxi*absxi; } std::experimental::linalg::sum_of_squares_result<T> result; result.scaled_sum_of_squares = ssq; result.scaling_factor = scale; // verify that things are consistent according to definition const auto lhs = scale*scale*ssq; const auto rhs = s+init.scaling_factor*init.scaling_factor*init.scaled_sum_of_squares; std::cout << lhs << " " << rhs << '\n'; EXPECT_NEAR(lhs, rhs, 1e-9); }and this works, in the sense that it satisfies: