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challenges #18

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20 changes: 15 additions & 5 deletions for_challenges.py
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Original file line numberDiff line numberDiff line change
Expand Up@@ -2,7 +2,8 @@
# Необходимо вывести имена всех учеников из списка с новой строки

names = ['Оля', 'Петя', 'Вася', 'Маша']
# ???
for name in names:
print(name)


# Задание 2
Expand All@@ -11,8 +12,10 @@
# Оля: 3
# Петя: 4


names = ['Оля', 'Петя', 'Вася', 'Маша']
# ???
for name in names:
print(name, len(names))


# Задание 3
Expand All@@ -25,7 +28,11 @@
'Маша': False,
}
names = ['Оля', 'Петя', 'Вася', 'Маша']
# ???
for name in names:
if is_male[name]:
print(f'{name} мужской род')
else:
print(f'{name} женский род')

@n05tr0m0n05tr0m0Dec 10, 2022

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Можно одной строкой в данном случае:

print(name, 'мужской пол') ifis_male[name] elseprint(name, 'женский пол')



# Задание 4
Expand All@@ -40,7 +47,9 @@
['Вася', 'Маша', 'Саша', 'Женя'],
['Оля', 'Петя', 'Гриша'],
]
# ???
print(f'Всего {len(groups)} группы.')
for number, group in enumerate(groups, 1):
print(f'В группе {number}:{len(group)} ученика')


# Задание 5
Expand All@@ -54,4 +63,5 @@
['Оля', 'Петя', 'Гриша'],
['Вася', 'Маша', 'Саша', 'Женя'],
]
# ???
for number, name in enumerate(groups, 1):
print(f"В группе {number}:{', '.join(name)}")
46 changes: 41 additions & 5 deletions for_dict_challenges.py
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Original file line numberDiff line numberDiff line change
Expand Up@@ -4,6 +4,8 @@
# Вася: 1
# Маша: 2
# Петя: 2
from collections import Counter


students = [
{'first_name': 'Вася'},
Expand All@@ -12,7 +14,14 @@
{'first_name': 'Маша'},
{'first_name': 'Петя'},
]
# ???
def count_name(students):
students_names = Counter([student['first_name'] for student in students])
return students_names


students_names = count_name(students)
for name, repeats in students_names.items():
print(f'{name}: {repeats}')

@n05tr0m0n05tr0m0Dec 10, 2022

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Решение без Counter для ознакомления:

count_students= {}
forstudentinstudents:
ifstudent['first_name'] notincount_students.keys():
count_students[student['first_name']] =1else:
count_students[student['first_name']] +=1print(count_students)
forname, countincount_students.items():
print(f"{name}: {count}")



# Задание 2
Expand All@@ -26,7 +35,17 @@
{'first_name': 'Маша'},
{'first_name': 'Оля'},
]
# ???
def name_max_value(students):
name_max_value = Counter(names).most_common(1)
return name_max_value[0][0]


names = count_name(students)
most_common_name = name_max_value(names)
print(f'Самое частое имя в классе: {most_common_name}')

@n05tr0m0n05tr0m0Dec 10, 2022

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Решение без Counter, для ознакомления:

students_list= [student['first_name'] forstudentinstudents]
print("Самое частое имя среди учеников:", max(set(students_list), key=students_list.count))





# Задание 3
Expand All@@ -51,7 +70,10 @@
{'first_name': 'Саша'},
],
]
# ???
for i, school_class in enumerate(school_students):
names = count_name(school_class)
most_common_name = name_max_value(names)
print(f'Самое частое имя в классе {i+1}: {most_common_name}')

@n05tr0m0n05tr0m0Dec 10, 2022

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Переиспользование уже написанных функций хороший подход.
Публикую решение без использования Counter для ознакомления:

fornum, studentsinenumerate(school_students, start=1):
students_list= [student['first_name'] forstudentinstudents]
print(f"Самое частое имя в классе {num}: {max(set(students_list), key=students_list.count)}")

Почитай, попробуй разобраться как это работает, если не получится, напиши мне.



# Задание 4
Expand All@@ -63,7 +85,7 @@
school = [
{'class': '2a', 'students': [{'first_name': 'Маша'}, {'first_name': 'Оля'}]},
{'class': '2б', 'students': [{'first_name': 'Олег'}, {'first_name': 'Миша'}]},
{'class': '2б', 'students': [{'first_name': 'Даша'}, {'first_name': 'Олег'}, {'first_name': 'Маша'}]},
{'class': '2в', 'students': [{'first_name': 'Даша'}, {'first_name': 'Олег'}, {'first_name': 'Маша'}]},
]
is_male = {
'Олег': True,
Expand All@@ -72,7 +94,21 @@
'Миша': True,
'Даша': False,
}
# ???
def students_gender(students):
gender = {'Male': 0, 'Female': 0}
for student in students:
name = student['first_name']
if is_male[name]:
gender['Male'] += 1
else:
gender['Female'] += 1
return gender


for school_class in school:
gender = students_gender(school_class['students'])
class_name = school_class['class']
print(f"Класс {class_name}: девочки {gender['Female']}, мальчики {gender['Male']}")

@n05tr0m0n05tr0m0Dec 10, 2022

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Ещё два способа решения для этой задачи для ознакомления:

forclass_inschool:
count_boys=0count_girls=0forstudentinclass_['students']:
ifis_male[student['first_name']]:
count_boys+=1else:
count_girls+=1print(f"Класс {class_['class']}: девочки {count_girls}, мальчики {count_boys}")
print("альтернативный способ") # альтернативный способforclass_inschool:
female= [name['first_name'] fornameinclass_['students'] ifnotis_male[name['first_name']]]
male= [name['first_name'] fornameinclass_['students'] ifis_male[name['first_name']]]
print(f"Класс {class_['class']}: девочки {len(female)}, мальчики {len(male)}")

@n05tr0m0n05tr0m0Dec 10, 2022

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Когда разберёшь, выполни 5-е задание



# Задание 5
Expand Down
22 changes: 15 additions & 7 deletions string_challenges.py
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Original file line numberDiff line numberDiff line change
@@ -1,28 +1,36 @@
# Вывести последнюю букву в слове
word = 'Архангельск'
# ???
word = 'Архангельск'
print(word[-1])


# Вывести количество букв "а" в слове
word = 'Архангельск'
# ???
print(word.find('а'))


# Вывести количество гласных букв в слове
word = 'Архангельск'
# ???
glas = set('аиеёоуыэюя')
word_set = set(word.lower())
print(f'{len(word_set.intersection(glas))} гласных слове')


# Вывести количество слов в предложении
sentence = 'Мы приехали в гости'
# ???

sentence = sentence.split(' ')
print(len(sentence))

# Вывести первую букву каждого слова на отдельной строке
sentence = 'Мы приехали в гости'
# ???
words = sentence.split(' ')
for word in words:
print(word[0])



# Вывести усреднённую длину слова в предложении
sentence = 'Мы приехали в гости'
# ???
words = sentence.split(' ')
avrg = sum(len(word) for word in words)/(len(words))
print(avrg)