Mapped Types should distribute over union types

[Jessidhia]

Search Terms

Mapped Type Union

Suggestion

This might be a bug or an intentional consequence of the original design, but mapped types do not distribute over union types. The example below demonstrates what happens:

type Foo = { x: false; foo?: string }
type Bar = { x: true; foo: string }

type FooOrBar = Foo | Bar

type MappedFooOrBar = Pick<FooOrBar, keyof FooOrBar>

// the type of MappedFooOrBar will be { x: boolean; foo: string | undefined }
// note how foo is now required even with x = false
// and also how you're now allowed to set foo = undefined even with x = true

Use Cases

Higher order components that receive components whose props are union types.

This usually is not a problem but it is a problem if you are going to use Pick (or Omit) on their props. This is already a problem with react-redux's connect for example.

Examples

type Foo = { x: false; foo?: string }
type Bar = { x: true; foo: string }

type FooOrBar = Foo | Bar

// input is a union type so this should distribute
type MappedFooOrBar = Pick<FooOrBar, keyof FooOrBar>
// should be equivalent to a MappedFooOrBar that distributes over its input
type MappedFooBar = Pick<Foo, keyof FooOrBar> | Pick<Bar, keyof FooOrBar>

Checklist

My suggestion meets these guidelines:

• This wouldn't be a breaking change in existing TypeScript / JavaScript code
  • It probably is breaking but is a "good break" as far as I can tell.
• This wouldn't change the runtime behavior of existing JavaScript code
• This could be implemented without emitting different JS based on the types of the expressions
• This isn't a runtime feature (e.g. new expression-level syntax)

[eps1lon]

It looks like only Pick does not distribute over union types. Partial is working fine.

[jack-williams]

The difference seems natural if you look at the definitions of Partial and Pick, to me at least.

type Partial<T> = {
 [P in keyof T]?: T[P];
};

type Pick<T, K extends keyof T> = {
 [P in K]: T[P];
};

Specifically the constraint part which is essentially the input to the map.

// Partial: [P in keyof T], could be read as a function T => [P in keyof T]
// Pick: [P in K], could be read as a function K => [P in K]

Partial is a parametric function on objects T, so applying it uniformly to object types in a union makes sense. Pick is a function on keys; the notion there was ever union of object types has been lost.

[eps1lon]

Jack Williams (@jack-williams)

The difference seems natural if you look at the definitions of Partial and Pick, to me at least.

That's kind of my issue here: Should I actually have to look at the implementation and then infer different behavior? Or wouldn't it be nicer if they behave the same since they're both classified as mapped types?

Do you have an example where the current behavior of Pick for unions is useful?

Is this maybe more of an issue with keyof for unions? In a perfect world the keyof { kind: 1; error: string } | { kind: 2; payload: any } would be ('kind' | 'error') | ('kind' | 'payload'). Typescript would not flatten this union and keep the information that 'kind' is the discriminant. Maybe this touches to much internals which is why I would prefer the standard lib Pick to use conditionals to distribute over union types.

At least the title should be changed from "Mapped types" to "Mapped types that are a function of keys". Otherwise it is misleading that all mapped types do not distribute over unions.

[dragomirtitian]

Sebastian "Sebbie" Silbermann (@eps1lon)

The difference seems natural if you look at the definitions of Partial and Pick, to me at least.

That's kind of my issue here: Should I actually have to look at the implementation and then infer different behavior? Or wouldn't it be nicer if they behave the same since they're both classified as mapped types?

Distribution does not happen in all cases for conditional types either. If the type parameter is not used nakedly it will not distribute so you have to know a bit about the type to know if it distributes over unions.

I think we can easily create a distributive version of Pick with what the language currently offers. I don't think it is of as general a use as the original version, but it would look something like:

type UnionKeys<T> = T extends any ? keyof T : never
type DistributivePick<T, K extends UnionKeys<T>> = T extends any ? Pick<T, Extract<keyof T, K>> : never;

type Union = {
 kind: "A",
 payload: number
} | {
 kind: "B",
 payload: string
} | {
 kind: "C",
}

type JustKind = DistributivePick<Union, 'kind'> // Pick<{ kind: "A"; payload: number; }, "kind"> | Pick<{ kind: "B"; payload: string; }, "kind"> | Pick<{ kind: "C"; payload: string; }, "kind">
type JustPayload = DistributivePick<Union, 'payload'> // Pick<{ kind: "A"; payload: number; }, "payload"> | Pick<{ kind: "B"; payload: string; }, "payload"> | Pick<{ kind: "C"; }, never>

[eps1lon]

Titian Cernicova-Dragomir (@dragomirtitian) Thanks for code. The union keys trick is new to me.

I don't think it is of as general a use as the original version

Do you have a use case were you require Pick to behave in its current way for union types?

[dragomirtitian]

Sebastian "Sebbie" Silbermann (@eps1lon) I am not 100% sure that i have used Pick with unions. I usually use Pick on non-union types.

The problem is that I do suspect changing it now would break some code somewhere. Also the distributive version is considerably more complex, it will slow down compilation and I think in most cases Pick is not used over unions so the people who want it can use custom type such as the one above.

Distributive omit below, for completeness :)

type Omit<T, K extends keyof T> = Pick<T, Exclude<keyof T, K>>
type DistributiveOmit<T, K extends UnionKeys<T>> = T extends any ? Omit<T, Extract<keyof T, K>> : never;

[eps1lon]

Well many libraries use Pick (see original Post: react higher-order components in particular). In those cases Pick should be agnostic to the type of the type.

I usually use Pick on non-union types.

Can you show me some examples where you use Pick? I'm biased towards react and we use Pick mostly in HOCs which is why the current behavior is so frustrating.

it will slow down compilation

Is there some accepted method to benchmark tsc compilation? I'm not familiar with all the intricacies of the language server. Can I just repeatedly run the cli or do I need to reset some things in between?

[jack-williams]

Sebastian "Sebbie" Silbermann (@eps1lon)

That's kind of my issue here: Should I actually have to look at the implementation and then infer different behavior? Or wouldn't it be nicer if they behave the same since they're both classified as mapped types?

Yes, I probably agree that the difference between homomorphic (Partial) and non-homomorphic (Pick) mapped types should be better documented. This does not mean the correct solution is to remove the differences.

Fundamentally I think they are mapping over different things and it doesn't really make sense to force them to behave the same. If you look at the implementation of Pick I'm not even sure how you would implement it as a mapped type that distributes over unions; the object type does not appear in the constraint type ([K in …]).

Do you have an example where the current behavior of Pick for unions is useful?

They are useful to me in so far as they work as I expect them to. This isn't a very satisfactory answer, but I've never felt the need for them to distribute.

In a perfect world the keyof { kind: 1; error: string } | { kind: 2; payload: any } would be ('kind' | 'error') | ('kind' | 'payload').

This will fundamentally break union types because they should be associative. If it doesn't break the correctness of the typechecker, I suspect it will at least cause a non-trivial perf hit.

The crux of the issue, IMO, is that distributing non-homomorphic mapped types over unions is incredibly shaky. They are functions that depend on keys, and the keys change if you view as a union or if you distribute.

As an example, consider the distributive implementation of Pick.

type JustPayload = DistributivePick<Union, 'payload'> // Pick<{ kind: "A"; payload: number; }, "payload"> | Pick<{ kind: "B"; payload: string; }, "payload"> | Pick<{ kind: "C"; }, never>

For JustPayload, distributing payload to the branch with kind "C" produces an empty object type {}, and consequently the overall type of JustPayload is essentially {}. I'm not sure this is what someone would want or expect.

[dragomirtitian]

Jack Williams (@jack-williams)

JustPayload can be useful with the apropriate type guards (an in type guard should narrow the {} away). But I do agree variations in behavior may be required on what you are trying to achieve.

[eps1lon]

For JustPayload, distributing payload to the branch with kind "C" produces an empty object type {}, and consequently the overall type of JustPayload is essentially {}.

What do you mean by that? I can still branch depending on the shape if I have a union like Foo | {}: https://www.typescriptlang.org/play/index.html#src=type%20Foo%20%3D%20%7B%20payload%3A%20string%20%7D%20%7C%20%7B%7D%0D%0A%0D%0Afunction%20getPayload(foo%3A%20Foo)%3A%20string%20%7C%20undefined%20%20%7B%0D%0A%20%20%20%20if%20(%22payload%22%20in%20foo)%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20foo.payload%3B%0D%0A%20%20%20%20%7D%0D%0A%20%20%20%20return%20undefined%3B%0D%0A%7D