Optional chaining type narrowing of void

[sharno]

TypeScript Version: 3.7.2

Search Terms:
Type narrowing void
Optional Chaining void

Code

type A = { b: string };

// example of how I try to use it:
async (p: Promise<A>) => {
 const a = await p.catch(console.error);
 a?.b; // error Property 'b' does not exist on type 'void | A'.
};

// simplified examples:
(a: A | void) => {
 a?.b; // error Property 'b' does not exist on type 'void | A'.
 a ? a.b : undefined // works
};

(a: A | undefined) => {
 a?.b; // works
};

(a: A | null) => {
 a?.b; // works
};

Expected behavior:
No errors when using optional chaining with a T | void if T contains the fields specified. I guess void could be represented as a value as undefined considering that a function that returns undefined returns type void.

Not sure if this is feasible

Actual behavior:
compilation error

Playground Link: https://www.typescriptlang.org/play/index.html?ssl=10&ssc=22&pln=10&pc=13#code/C4TwDgpgBAglC8UDeUBGAuKBnYAnAlgHYDmUAvgNwBQVAhliIQMZQAUYmACrgPYC2+LBAA8MAHwBKBGORUoUJj0I4otBKoDutfMChgAdE1rAmAC1aLlPADYR9EXL1wTq82gH59qapRqtamHAAPlAAbjz4ACZS8DJIcqqe3glq7qpeUJgAroSREABmRBCRVL5U-oFQITl5hYTFMXEpST7U5QGwVVCEWdbWjbJuLaXUQA

[nmain]

undefined and void are not synonymous. void represents that the return of a function could be anything and should not be used for anything, and so has consequences like https://github.com/microsoft/TypeScript/wiki/FAQ#why-are-functions-returning-non-void-assignable-to-function-returning-void

So your request can be broken with something like this:

let a: () => void;

let b = () => ({ a: 5 })

a = b;

let c = true;

let d = c ? a() : { a: "5" };

d; // void | { a: string }
console.log(typeof d?.a); // "number"

[sharno]

Nicholai Main (@nmain) Makes sense, thanks for the clarification

[sharno]

Actually another question if according to #26262, void shouldn't allow checking for truthiness
Why is it allowed here when it's a discriminated union with another type?

(a: A | void) => {
 a ? a.b : undefined // works
};

Do you think I should file another bug for this?

[nmain]

Good question. I'm guessing that was intentional, but it does seem inconsistent; T | void can be tested for truthiness, but not safe-navigated. 🤷‍♂

[RyanCavanaugh]

Testing void for truthiness is a one-off rule. There's no legitimate reason to write (a: A | void) => so whatever behavior that produces is immaterial

[sharno]

Ryan Cavanaugh (@RyanCavanaugh)
There's a legitimate reason I have in my code to write something like this:

async (p: Promise<A>) => {
 const a = await p.catch(console.error);
 // do stuff with a
};

Apparently a will have type A | void. Passing any function that returns void to catch will yield the same type which might cause unwanted behaviors if checked for truthiness and the function returns something other than undefined.

I know this issue doesn't track this and it's good to close it. But what do you think about such a use case?

[Cellule]

There are also a lot of confusion between void and undefined in general.
For instance in react-apollo the result of a mutation was typed with void | {data: Data}.

const response = mutation();
if (response) {
 // This is fine because if(void|{data: Data}) removed void from union
 const data = response.data
}
// This is not fine because ?. won't remove void thus giving error that "data" doesn't exist on void
const data = response?.data;

While I agree that void and undefined are different, in practice there are used interchangeably.

If you stick to the argument that void | A is not legitimate to do, why are we allowed to write it?
Either void is special and can't be union'ed with another type or it behaves like undefined and should be removed from the union when using ?.

[RyanCavanaugh]

The category of "things which you should not do because they are ultimately incoherent" is unbounded; it's similarly useless to write 0 * ((x + a + b) * 1 + 3) but not a categorical error. void has a meaning and | has a meaning; if you misapprehend those meanings and combine them you'll get weird results.

Banning of certain combinations of type operators and type operands has been discussed extensively before; in a language with structural generics it's ultimately a fool's errand because you can't prevent generic instantiations that end up creating "illegal" types.

[Cellule]

You make a very good point why void | A should not be blocked and I totally agree with you there.
My main question is why was it determined that if (void | A) will produce A in the if block and can we apply the same logic for ?.?

[RyanCavanaugh]

We're actually thinking that the if block shouldn't narrow, since some other truthy value might inhabit response. If mutation is guaranteed to return undefined when it doesn't produce the prescribed value, then it should be written as such rather than using void

[RyanCavanaugh]

Oh, and that console.error and its friends should have their return types changed from void to undefined since that behavior is specified

[Cellule]

The biggest problem with making such a change is all the libraries incorrectly using void instead of undefined would become broken. Upgrading is not always easy or possible in the short time for various reasons.
We'd be stuck having to do something like

type ReplaceVoid<T> = T extends void ? Exclude<T, void> | undefined : T;
function removeVoid<T>(a: T): ReplaceVoid<T> {
 return a as any;
}

type A = void | { data: any };
function foo(a: A) {
 // for if block
 const _a = removeVoid(a);
 if (_a) {
 _a.data
 }
 // using && operator
 _a && _a.data;
 // using optional chaining
 removeVoid(a)?.data;
}

Maybe there is an easier way to convert void to undefined, but we'd definitely need it if Typescript is going in that direction.