callable protocols cannot infer the type of their own `self`

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Bug Report

Methods on protocols with a __call__ method cannot infer the type of self
as callable in other methods.

To Reproduce

https://mypy-play.net/?mypy=latest&python=3.11&flags=strict&gist=7234281168a0762dd9a81b1f10d8a96a

from typing import Callable, ParamSpec, Protocol, TypeVar

Params = ParamSpec("Params")
Result = TypeVar("Result", covariant=True)

class FancyMethod(Protocol):

    def __call__(self, arg1: int, arg2: str) -> list[float]:
        """
        Calling me results in a very specific signature.
        """

    def returnMe(self: Callable[Params, Result]) -> Callable[Params, Result]:
        ...

def externalGet(self: Callable[Params, Result]) -> Callable[Params, Result]:
    return self

Expected Behavior

I would expect that this would be inferred in returnMe the same way that it would be in externalGet.

Actual Behavior

main.py:13: error: The erased type of self "def (*Params.args, **Params.kwargs) -> Result`-2" is not a supertype of its class "__main__.FancyMethod"  [misc]