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Infer union from conditional definition in if statement #6233

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@JukkaL

Maybe if a variable is initialized both in if and else blocks, the resulting type should be the union of the types of the initializers (only when using --allow-redefinitions):

iffoo():
x=0# Type of x is 'int' hereelse:
x=''# No error here# Type of x is 'str' herereveal_type(x) # Union[int, str]

Currently the second assignment generates an error, and the type of x is int everywhere.

This is a generalization of #6232 and related to #1174 (but not a direct follow-up issue).

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