Correction for problem: Find no of trailing zeroes.

[shailbenq]

Hi I checked the solution provided for number problem to find no of trailing zeroes in a factorial of a number. Your solution does not consider the case where number is larger than 25. If its larger than 25, the number of trailing zeroes will be number/5 + 1. In your case 26! will have 5 trailing zeroes but actually it should be 6. This is also true for multiples of 25 ,125,625, So below is one of the approach to solve this issue. Thanks :)

 public class FactorialNoOfTrailingZeroes {
 public static int findTrailingZeroes(int number) {
 int res=0;
 int i = 1;
 while(number >= Math.pow(5, i)){
 res += number/Math.pow(5, i);
 i++;
 }
 return res;
 }

 public static void main(String[] args) {
 System.out.println(findTrailingZeroes(60));
 }
}

[techpanja]

thanks for the comment.. i will update it.