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2 changes: 0 additions & 2 deletions DIRECTORY.md
Original file line numberDiff line numberDiff line change
Expand Up@@ -577,9 +577,7 @@
* [Bailey Borwein Plouffe](maths/bailey_borwein_plouffe.py)
* [Base Neg2 Conversion](maths/base_neg2_conversion.py)
* [Basic Maths](maths/basic_maths.py)
* [Binary Exp Mod](maths/binary_exp_mod.py)
* [Binary Exponentiation](maths/binary_exponentiation.py)
* [Binary Exponentiation 2](maths/binary_exponentiation_2.py)
* [Binary Multiplication](maths/binary_multiplication.py)
* [Binomial Coefficient](maths/binomial_coefficient.py)
* [Binomial Distribution](maths/binomial_distribution.py)
Expand Down
28 changes: 0 additions & 28 deletions maths/binary_exp_mod.py

This file was deleted.

214 changes: 181 additions & 33 deletions maths/binary_exponentiation.py
Original file line numberDiff line numberDiff line change
@@ -1,48 +1,196 @@
"""Binary Exponentiation."""
"""
Binary Exponentiation

# Author : Junth Basnet
# Time Complexity : O(logn)
This is a method to find a^b in O(log b) time complexity and is one of the most commonly
used methods of exponentiation. The method is also useful for modular exponentiation,
when the solution to (a^b) % c is required.

To calculate a^b:
- If b is even, then a^b = (a * a)^(b / 2)
- If b is odd, then a^b = a * a^(b - 1)
Repeat until b = 1 or b = 0

def binary_exponentiation(a: int, n: int) -> int:
For modular exponentiation, we use the fact that (a * b) % c = ((a % c) * (b % c)) % c
"""


def binary_exp_recursive(base: float, exponent: int) -> float:
"""
Compute a number raised by some quantity

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Why remove this? exp is a bit cryptic in the function name and a line of documentation here is useful.

>>> binary_exponentiation(-1, 3)
Computes a^b recursively, where a is the base and b is the exponent

>>> binary_exp_recursive(3, 5)

@cclausscclaussOct 21, 2023

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What about tests for a=big number and n=big number, a=float, n=float?

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ContributorAuthor

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Can do, but the n=float case won't work because the algorithm can only compute integer powers

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I know it won’t work but I wanted to see how it fails. Does it raise a ValueError? Does it behave like pow() does. Testing how things work if half the battle. Watching them fail is just as cool.

243
>>> binary_exp_recursive(11, 13)
34522712143931
>>> binary_exp_recursive(-1, 3)
-1
>>> binary_exponentiation(-1, 4)
>>> binary_exp_recursive(0, 5)
0
>>> binary_exp_recursive(3, 1)
3
>>> binary_exp_recursive(3, 0)
1
>>> binary_exponentiation(2, 2)
4
>>> binary_exponentiation(3, 5)
>>> binary_exp_recursive(1.5, 4)
5.0625
>>> binary_exp_recursive(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

if exponent == 0:
return 1

if exponent % 2 == 1:
return binary_exp_recursive(base, exponent - 1) * base

b = binary_exp_recursive(base, exponent // 2)
return b * b


def binary_exp_iterative(base: float, exponent: int) -> float:
"""
Computes a^b iteratively, where a is the base and b is the exponent

>>> binary_exp_iterative(3, 5)
243
>>> binary_exponentiation(10, 3)
1000
>>> binary_exponentiation(5e3, 1)
5000.0
>>> binary_exponentiation(-5e3, 1)
-5000.0
"""
if n == 0:
>>> binary_exp_iterative(11, 13)
34522712143931
>>> binary_exp_iterative(-1, 3)
-1
>>> binary_exp_iterative(0, 5)
0
>>> binary_exp_iterative(3, 1)
3
>>> binary_exp_iterative(3, 0)
1
>>> binary_exp_iterative(1.5, 4)
5.0625
>>> binary_exp_iterative(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res *= base

base *= base
exponent >>= 1

return res


def binary_exp_mod_recursive(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c recursively, where a is the base, b is the exponent, and c is the
modulus

>>> binary_exp_mod_recursive(3, 4, 5)
1
>>> binary_exp_mod_recursive(11, 13, 7)
4
>>> binary_exp_mod_recursive(1.5, 4, 3)
2.0625
>>> binary_exp_mod_recursive(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_recursive(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

if exponent == 0:
return 1

elif n % 2 == 1:
return binary_exponentiation(a, n - 1) * a
if exponent % 2 == 1:
return (binary_exp_mod_recursive(base, exponent - 1, modulus) * base) % modulus

else:
b = binary_exponentiation(a, n // 2)
return b * b
r = binary_exp_mod_recursive(base, exponent // 2, modulus)
return (r * r) % modulus


if __name__ == "__main__":
import doctest
def binary_exp_mod_iterative(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c iteratively, where a is the base, b is the exponent, and c is the
modulus

doctest.testmod()
>>> binary_exp_mod_iterative(3, 4, 5)
1
>>> binary_exp_mod_iterative(11, 13, 7)
4
>>> binary_exp_mod_iterative(1.5, 4, 3)
2.0625
>>> binary_exp_mod_iterative(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_iterative(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res = ((res % modulus) * (base % modulus)) % modulus

base *= base
exponent >>= 1

return res


if __name__ == "__main__":
from timeit import timeit

try:
BASE = int(float(input("Enter Base : ").strip()))
POWER = int(input("Enter Power : ").strip())
except ValueError:
print("Invalid literal for integer")
a = 1269380576
b = 374
c = 34

RESULT = binary_exponentiation(BASE, POWER)
print(f"{BASE}^({POWER}) : {RESULT}")
runs = 100_000
print(
timeit(
f"binary_exp_recursive({a}, {b})",
setup="from __main__ import binary_exp_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_iterative({a}, {b})",
setup="from __main__ import binary_exp_iterative",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_recursive({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_iterative({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_iterative",
number=runs,
)
)
61 changes: 0 additions & 61 deletions maths/binary_exponentiation_2.py

This file was deleted.

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var __re = new RegExp('^' + "github\\.com" + '
Consolidate binary exponentiation files by tianyizheng02 · Pull Request #10742 · TheAlgorithms/Python · GitHub
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2 changes: 0 additions & 2 deletions DIRECTORY.md
Original file line numberDiff line numberDiff line change
Expand Up@@ -577,9 +577,7 @@
* [Bailey Borwein Plouffe](maths/bailey_borwein_plouffe.py)
* [Base Neg2 Conversion](maths/base_neg2_conversion.py)
* [Basic Maths](maths/basic_maths.py)
* [Binary Exp Mod](maths/binary_exp_mod.py)
* [Binary Exponentiation](maths/binary_exponentiation.py)
* [Binary Exponentiation 2](maths/binary_exponentiation_2.py)
* [Binary Multiplication](maths/binary_multiplication.py)
* [Binomial Coefficient](maths/binomial_coefficient.py)
* [Binomial Distribution](maths/binomial_distribution.py)
Expand Down
28 changes: 0 additions & 28 deletions maths/binary_exp_mod.py

This file was deleted.

214 changes: 181 additions & 33 deletions maths/binary_exponentiation.py
Original file line numberDiff line numberDiff line change
@@ -1,48 +1,196 @@
"""Binary Exponentiation."""
"""
Binary Exponentiation

# Author : Junth Basnet
# Time Complexity : O(logn)
This is a method to find a^b in O(log b) time complexity and is one of the most commonly
used methods of exponentiation. The method is also useful for modular exponentiation,
when the solution to (a^b) % c is required.

To calculate a^b:
- If b is even, then a^b = (a * a)^(b / 2)
- If b is odd, then a^b = a * a^(b - 1)
Repeat until b = 1 or b = 0

def binary_exponentiation(a: int, n: int) -> int:
For modular exponentiation, we use the fact that (a * b) % c = ((a % c) * (b % c)) % c
"""


def binary_exp_recursive(base: float, exponent: int) -> float:
"""
Compute a number raised by some quantity

Copy link
Copy Markdown
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Why remove this? exp is a bit cryptic in the function name and a line of documentation here is useful.

>>> binary_exponentiation(-1, 3)
Computes a^b recursively, where a is the base and b is the exponent

>>> binary_exp_recursive(3, 5)

@cclausscclaussOct 21, 2023

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What about tests for a=big number and n=big number, a=float, n=float?

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ContributorAuthor

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Can do, but the n=float case won't work because the algorithm can only compute integer powers

Copy link
Copy Markdown
Member

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The reason will be displayed to describe this comment to others. Learn more.

I know it won’t work but I wanted to see how it fails. Does it raise a ValueError? Does it behave like pow() does. Testing how things work if half the battle. Watching them fail is just as cool.

243
>>> binary_exp_recursive(11, 13)
34522712143931
>>> binary_exp_recursive(-1, 3)
-1
>>> binary_exponentiation(-1, 4)
>>> binary_exp_recursive(0, 5)
0
>>> binary_exp_recursive(3, 1)
3
>>> binary_exp_recursive(3, 0)
1
>>> binary_exponentiation(2, 2)
4
>>> binary_exponentiation(3, 5)
>>> binary_exp_recursive(1.5, 4)
5.0625
>>> binary_exp_recursive(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

if exponent == 0:
return 1

if exponent % 2 == 1:
return binary_exp_recursive(base, exponent - 1) * base

b = binary_exp_recursive(base, exponent // 2)
return b * b


def binary_exp_iterative(base: float, exponent: int) -> float:
"""
Computes a^b iteratively, where a is the base and b is the exponent

>>> binary_exp_iterative(3, 5)
243
>>> binary_exponentiation(10, 3)
1000
>>> binary_exponentiation(5e3, 1)
5000.0
>>> binary_exponentiation(-5e3, 1)
-5000.0
"""
if n == 0:
>>> binary_exp_iterative(11, 13)
34522712143931
>>> binary_exp_iterative(-1, 3)
-1
>>> binary_exp_iterative(0, 5)
0
>>> binary_exp_iterative(3, 1)
3
>>> binary_exp_iterative(3, 0)
1
>>> binary_exp_iterative(1.5, 4)
5.0625
>>> binary_exp_iterative(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res *= base

base *= base
exponent >>= 1

return res


def binary_exp_mod_recursive(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c recursively, where a is the base, b is the exponent, and c is the
modulus

>>> binary_exp_mod_recursive(3, 4, 5)
1
>>> binary_exp_mod_recursive(11, 13, 7)
4
>>> binary_exp_mod_recursive(1.5, 4, 3)
2.0625
>>> binary_exp_mod_recursive(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_recursive(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

if exponent == 0:
return 1

elif n % 2 == 1:
return binary_exponentiation(a, n - 1) * a
if exponent % 2 == 1:
return (binary_exp_mod_recursive(base, exponent - 1, modulus) * base) % modulus

else:
b = binary_exponentiation(a, n // 2)
return b * b
r = binary_exp_mod_recursive(base, exponent // 2, modulus)
return (r * r) % modulus


if __name__ == "__main__":
import doctest
def binary_exp_mod_iterative(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c iteratively, where a is the base, b is the exponent, and c is the
modulus

doctest.testmod()
>>> binary_exp_mod_iterative(3, 4, 5)
1
>>> binary_exp_mod_iterative(11, 13, 7)
4
>>> binary_exp_mod_iterative(1.5, 4, 3)
2.0625
>>> binary_exp_mod_iterative(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_iterative(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res = ((res % modulus) * (base % modulus)) % modulus

base *= base
exponent >>= 1

return res


if __name__ == "__main__":
from timeit import timeit

try:
BASE = int(float(input("Enter Base : ").strip()))
POWER = int(input("Enter Power : ").strip())
except ValueError:
print("Invalid literal for integer")
a = 1269380576
b = 374
c = 34

RESULT = binary_exponentiation(BASE, POWER)
print(f"{BASE}^({POWER}) : {RESULT}")
runs = 100_000
print(
timeit(
f"binary_exp_recursive({a}, {b})",
setup="from __main__ import binary_exp_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_iterative({a}, {b})",
setup="from __main__ import binary_exp_iterative",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_recursive({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_iterative({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_iterative",
number=runs,
)
)
61 changes: 0 additions & 61 deletions maths/binary_exponentiation_2.py

This file was deleted.

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2 changes: 0 additions & 2 deletions DIRECTORY.md
Original file line numberDiff line numberDiff line change
Expand Up@@ -577,9 +577,7 @@
* [Bailey Borwein Plouffe](maths/bailey_borwein_plouffe.py)
* [Base Neg2 Conversion](maths/base_neg2_conversion.py)
* [Basic Maths](maths/basic_maths.py)
* [Binary Exp Mod](maths/binary_exp_mod.py)
* [Binary Exponentiation](maths/binary_exponentiation.py)
* [Binary Exponentiation 2](maths/binary_exponentiation_2.py)
* [Binary Multiplication](maths/binary_multiplication.py)
* [Binomial Coefficient](maths/binomial_coefficient.py)
* [Binomial Distribution](maths/binomial_distribution.py)
Expand Down
28 changes: 0 additions & 28 deletions maths/binary_exp_mod.py

This file was deleted.

214 changes: 181 additions & 33 deletions maths/binary_exponentiation.py
Original file line numberDiff line numberDiff line change
@@ -1,48 +1,196 @@
"""Binary Exponentiation."""
"""
Binary Exponentiation

# Author : Junth Basnet
# Time Complexity : O(logn)
This is a method to find a^b in O(log b) time complexity and is one of the most commonly
used methods of exponentiation. The method is also useful for modular exponentiation,
when the solution to (a^b) % c is required.

To calculate a^b:
- If b is even, then a^b = (a * a)^(b / 2)
- If b is odd, then a^b = a * a^(b - 1)
Repeat until b = 1 or b = 0

def binary_exponentiation(a: int, n: int) -> int:
For modular exponentiation, we use the fact that (a * b) % c = ((a % c) * (b % c)) % c
"""


def binary_exp_recursive(base: float, exponent: int) -> float:
"""
Compute a number raised by some quantity

Copy link
Copy Markdown
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Why remove this? exp is a bit cryptic in the function name and a line of documentation here is useful.

>>> binary_exponentiation(-1, 3)
Computes a^b recursively, where a is the base and b is the exponent

>>> binary_exp_recursive(3, 5)

@cclausscclaussOct 21, 2023

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What about tests for a=big number and n=big number, a=float, n=float?

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Copy Markdown
ContributorAuthor

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Can do, but the n=float case won't work because the algorithm can only compute integer powers

Copy link
Copy Markdown
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

I know it won’t work but I wanted to see how it fails. Does it raise a ValueError? Does it behave like pow() does. Testing how things work if half the battle. Watching them fail is just as cool.

243
>>> binary_exp_recursive(11, 13)
34522712143931
>>> binary_exp_recursive(-1, 3)
-1
>>> binary_exponentiation(-1, 4)
>>> binary_exp_recursive(0, 5)
0
>>> binary_exp_recursive(3, 1)
3
>>> binary_exp_recursive(3, 0)
1
>>> binary_exponentiation(2, 2)
4
>>> binary_exponentiation(3, 5)
>>> binary_exp_recursive(1.5, 4)
5.0625
>>> binary_exp_recursive(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

if exponent == 0:
return 1

if exponent % 2 == 1:
return binary_exp_recursive(base, exponent - 1) * base

b = binary_exp_recursive(base, exponent // 2)
return b * b


def binary_exp_iterative(base: float, exponent: int) -> float:
"""
Computes a^b iteratively, where a is the base and b is the exponent

>>> binary_exp_iterative(3, 5)
243
>>> binary_exponentiation(10, 3)
1000
>>> binary_exponentiation(5e3, 1)
5000.0
>>> binary_exponentiation(-5e3, 1)
-5000.0
"""
if n == 0:
>>> binary_exp_iterative(11, 13)
34522712143931
>>> binary_exp_iterative(-1, 3)
-1
>>> binary_exp_iterative(0, 5)
0
>>> binary_exp_iterative(3, 1)
3
>>> binary_exp_iterative(3, 0)
1
>>> binary_exp_iterative(1.5, 4)
5.0625
>>> binary_exp_iterative(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res *= base

base *= base
exponent >>= 1

return res


def binary_exp_mod_recursive(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c recursively, where a is the base, b is the exponent, and c is the
modulus

>>> binary_exp_mod_recursive(3, 4, 5)
1
>>> binary_exp_mod_recursive(11, 13, 7)
4
>>> binary_exp_mod_recursive(1.5, 4, 3)
2.0625
>>> binary_exp_mod_recursive(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_recursive(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

if exponent == 0:
return 1

elif n % 2 == 1:
return binary_exponentiation(a, n - 1) * a
if exponent % 2 == 1:
return (binary_exp_mod_recursive(base, exponent - 1, modulus) * base) % modulus

else:
b = binary_exponentiation(a, n // 2)
return b * b
r = binary_exp_mod_recursive(base, exponent // 2, modulus)
return (r * r) % modulus


if __name__ == "__main__":
import doctest
def binary_exp_mod_iterative(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c iteratively, where a is the base, b is the exponent, and c is the
modulus

doctest.testmod()
>>> binary_exp_mod_iterative(3, 4, 5)
1
>>> binary_exp_mod_iterative(11, 13, 7)
4
>>> binary_exp_mod_iterative(1.5, 4, 3)
2.0625
>>> binary_exp_mod_iterative(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_iterative(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res = ((res % modulus) * (base % modulus)) % modulus

base *= base
exponent >>= 1

return res


if __name__ == "__main__":
from timeit import timeit

try:
BASE = int(float(input("Enter Base : ").strip()))
POWER = int(input("Enter Power : ").strip())
except ValueError:
print("Invalid literal for integer")
a = 1269380576
b = 374
c = 34

RESULT = binary_exponentiation(BASE, POWER)
print(f"{BASE}^({POWER}) : {RESULT}")
runs = 100_000
print(
timeit(
f"binary_exp_recursive({a}, {b})",
setup="from __main__ import binary_exp_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_iterative({a}, {b})",
setup="from __main__ import binary_exp_iterative",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_recursive({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_iterative({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_iterative",
number=runs,
)
)
61 changes: 0 additions & 61 deletions maths/binary_exponentiation_2.py

This file was deleted.

, 'i'); if (__m === '*' || __re.test(location.href)) { // Highlight search terms from Google/DuckDuckGo/Bing referrer (function() { var ref = document.referrer; var terms = []; if (ref.includes('google.com') || ref.includes('duckduckgo.com') || ref.includes('bing.com')) { var url = new URL(ref); var q = url.searchParams.get('q') || url.searchParams.get('p'); if (q) { terms = q.split(/\s+/).filter(function(t) { return t.length > 2; }); } } if (terms.length === 0) return; var style = document.createElement('style'); style.textContent = '.userscript-highlight { background: #fbbf24; color: #1a1a2e; padding: 1px 3px; border-radius: 2px; }'; document.head.appendChild(style); function highlight(node) { if (node.nodeType === 3) { // text node var text = node.textContent; var found = false; terms.forEach(function(term) { var regex = new RegExp('(' + term.replace(/[.*+?^${}()|[\]\\]/g, '\\') + ')', 'gi'); if (regex.test(text)) { found = true; var frag = document.createDocumentFragment(); var parts = text.split(regex); parts.forEach(function(part, i) { if (i % 2 === 0) { frag.appendChild(document.createTextNode(part)); } else { var span = document.createElement('span'); span.className = 'userscript-highlight'; span.textContent = part; frag.appendChild(span); } }); node.parentNode.replaceChild(frag, node); } }); } else if (node.nodeType === 1 && node.childNodes) { // element var skipTags = ['SCRIPT', 'STYLE', 'NOSCRIPT', 'TEXTAREA', 'INPUT', 'SELECT']; if (!skipTags.includes(node.tagName)) { Array.from(node.childNodes).forEach(highlight); } } } highlight(document.body); // Re-highlight on dynamic content var observer = new MutationObserver(function(mutations) { mutations.forEach(function(m) { m.addedNodes.forEach(function(node) { if (node.nodeType === 1 || node.nodeType === 3) highlight(node); }); }); }); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:Highlight Search Terms]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Consolidate binary exponentiation files by tianyizheng02 · Pull Request #10742 · TheAlgorithms/Python · GitHub
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2 changes: 0 additions & 2 deletions DIRECTORY.md
Original file line numberDiff line numberDiff line change
Expand Up@@ -577,9 +577,7 @@
* [Bailey Borwein Plouffe](maths/bailey_borwein_plouffe.py)
* [Base Neg2 Conversion](maths/base_neg2_conversion.py)
* [Basic Maths](maths/basic_maths.py)
* [Binary Exp Mod](maths/binary_exp_mod.py)
* [Binary Exponentiation](maths/binary_exponentiation.py)
* [Binary Exponentiation 2](maths/binary_exponentiation_2.py)
* [Binary Multiplication](maths/binary_multiplication.py)
* [Binomial Coefficient](maths/binomial_coefficient.py)
* [Binomial Distribution](maths/binomial_distribution.py)
Expand Down
28 changes: 0 additions & 28 deletions maths/binary_exp_mod.py

This file was deleted.

214 changes: 181 additions & 33 deletions maths/binary_exponentiation.py
Original file line numberDiff line numberDiff line change
@@ -1,48 +1,196 @@
"""Binary Exponentiation."""
"""
Binary Exponentiation

# Author : Junth Basnet
# Time Complexity : O(logn)
This is a method to find a^b in O(log b) time complexity and is one of the most commonly
used methods of exponentiation. The method is also useful for modular exponentiation,
when the solution to (a^b) % c is required.

To calculate a^b:
- If b is even, then a^b = (a * a)^(b / 2)
- If b is odd, then a^b = a * a^(b - 1)
Repeat until b = 1 or b = 0

def binary_exponentiation(a: int, n: int) -> int:
For modular exponentiation, we use the fact that (a * b) % c = ((a % c) * (b % c)) % c
"""


def binary_exp_recursive(base: float, exponent: int) -> float:
"""
Compute a number raised by some quantity

Copy link
Copy Markdown
Member

Choose a reason for hiding this comment

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Why remove this? exp is a bit cryptic in the function name and a line of documentation here is useful.

>>> binary_exponentiation(-1, 3)
Computes a^b recursively, where a is the base and b is the exponent

>>> binary_exp_recursive(3, 5)

@cclausscclaussOct 21, 2023

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What about tests for a=big number and n=big number, a=float, n=float?

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ContributorAuthor

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Can do, but the n=float case won't work because the algorithm can only compute integer powers

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I know it won’t work but I wanted to see how it fails. Does it raise a ValueError? Does it behave like pow() does. Testing how things work if half the battle. Watching them fail is just as cool.

243
>>> binary_exp_recursive(11, 13)
34522712143931
>>> binary_exp_recursive(-1, 3)
-1
>>> binary_exponentiation(-1, 4)
>>> binary_exp_recursive(0, 5)
0
>>> binary_exp_recursive(3, 1)
3
>>> binary_exp_recursive(3, 0)
1
>>> binary_exponentiation(2, 2)
4
>>> binary_exponentiation(3, 5)
>>> binary_exp_recursive(1.5, 4)
5.0625
>>> binary_exp_recursive(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

if exponent == 0:
return 1

if exponent % 2 == 1:
return binary_exp_recursive(base, exponent - 1) * base

b = binary_exp_recursive(base, exponent // 2)
return b * b


def binary_exp_iterative(base: float, exponent: int) -> float:
"""
Computes a^b iteratively, where a is the base and b is the exponent

>>> binary_exp_iterative(3, 5)
243
>>> binary_exponentiation(10, 3)
1000
>>> binary_exponentiation(5e3, 1)
5000.0
>>> binary_exponentiation(-5e3, 1)
-5000.0
"""
if n == 0:
>>> binary_exp_iterative(11, 13)
34522712143931
>>> binary_exp_iterative(-1, 3)
-1
>>> binary_exp_iterative(0, 5)
0
>>> binary_exp_iterative(3, 1)
3
>>> binary_exp_iterative(3, 0)
1
>>> binary_exp_iterative(1.5, 4)
5.0625
>>> binary_exp_iterative(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res *= base

base *= base
exponent >>= 1

return res


def binary_exp_mod_recursive(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c recursively, where a is the base, b is the exponent, and c is the
modulus

>>> binary_exp_mod_recursive(3, 4, 5)
1
>>> binary_exp_mod_recursive(11, 13, 7)
4
>>> binary_exp_mod_recursive(1.5, 4, 3)
2.0625
>>> binary_exp_mod_recursive(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_recursive(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

if exponent == 0:
return 1

elif n % 2 == 1:
return binary_exponentiation(a, n - 1) * a
if exponent % 2 == 1:
return (binary_exp_mod_recursive(base, exponent - 1, modulus) * base) % modulus

else:
b = binary_exponentiation(a, n // 2)
return b * b
r = binary_exp_mod_recursive(base, exponent // 2, modulus)
return (r * r) % modulus


if __name__ == "__main__":
import doctest
def binary_exp_mod_iterative(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c iteratively, where a is the base, b is the exponent, and c is the
modulus

doctest.testmod()
>>> binary_exp_mod_iterative(3, 4, 5)
1
>>> binary_exp_mod_iterative(11, 13, 7)
4
>>> binary_exp_mod_iterative(1.5, 4, 3)
2.0625
>>> binary_exp_mod_iterative(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_iterative(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res = ((res % modulus) * (base % modulus)) % modulus

base *= base
exponent >>= 1

return res


if __name__ == "__main__":
from timeit import timeit

try:
BASE = int(float(input("Enter Base : ").strip()))
POWER = int(input("Enter Power : ").strip())
except ValueError:
print("Invalid literal for integer")
a = 1269380576
b = 374
c = 34

RESULT = binary_exponentiation(BASE, POWER)
print(f"{BASE}^({POWER}) : {RESULT}")
runs = 100_000
print(
timeit(
f"binary_exp_recursive({a}, {b})",
setup="from __main__ import binary_exp_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_iterative({a}, {b})",
setup="from __main__ import binary_exp_iterative",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_recursive({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_iterative({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_iterative",
number=runs,
)
)
61 changes: 0 additions & 61 deletions maths/binary_exponentiation_2.py

This file was deleted.

, 'i'); if (__m === '*' || __re.test(location.href)) { // Strip utm_, fbclid, gclid, etc. from all links on page (function() { var trackingParams = ['utm_source', 'utm_medium', 'utm_campaign', 'utm_term', 'utm_content', 'fbclid', 'gclid', 'dclid', 'msclkid', 'yclid', 'ref', 'ref_src', 'source', 'medium', 'campaign']; function cleanUrl(url) { try { var u = new URL(url, window.location.origin); var changed = false; trackingParams.forEach(function(p) { if (u.searchParams.has(p)) { u.searchParams.delete(p); changed = true; } }); return changed ? u.toString() : url; } catch (e) { return url; } } function cleanLinks() { document.querySelectorAll('a[href]').forEach(function(a) { var clean = cleanUrl(a.href); if (clean !== a.href) a.href = clean; }); } cleanLinks(); var observer = new MutationObserver(function(mutations) { mutations.forEach(function(m) { m.addedNodes.forEach(function(node) { if (node.nodeType === 1) { if (node.tagName === 'A') cleanLinks(); node.querySelectorAll('a[href]').forEach(function(a) { var clean = cleanUrl(a.href); if (clean !== a.href) a.href = clean; }); } }); }); }); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:Remove Tracking Parameters from Links]', __e); } })(); (function(){ try { var __m = "youtube.com"; var __re = new RegExp('^' + "youtube\\.com" + ' Consolidate binary exponentiation files by tianyizheng02 · Pull Request #10742 · TheAlgorithms/Python · GitHub
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2 changes: 0 additions & 2 deletions DIRECTORY.md
Original file line numberDiff line numberDiff line change
Expand Up@@ -577,9 +577,7 @@
* [Bailey Borwein Plouffe](maths/bailey_borwein_plouffe.py)
* [Base Neg2 Conversion](maths/base_neg2_conversion.py)
* [Basic Maths](maths/basic_maths.py)
* [Binary Exp Mod](maths/binary_exp_mod.py)
* [Binary Exponentiation](maths/binary_exponentiation.py)
* [Binary Exponentiation 2](maths/binary_exponentiation_2.py)
* [Binary Multiplication](maths/binary_multiplication.py)
* [Binomial Coefficient](maths/binomial_coefficient.py)
* [Binomial Distribution](maths/binomial_distribution.py)
Expand Down
28 changes: 0 additions & 28 deletions maths/binary_exp_mod.py

This file was deleted.

214 changes: 181 additions & 33 deletions maths/binary_exponentiation.py
Original file line numberDiff line numberDiff line change
@@ -1,48 +1,196 @@
"""Binary Exponentiation."""
"""
Binary Exponentiation

# Author : Junth Basnet
# Time Complexity : O(logn)
This is a method to find a^b in O(log b) time complexity and is one of the most commonly
used methods of exponentiation. The method is also useful for modular exponentiation,
when the solution to (a^b) % c is required.

To calculate a^b:
- If b is even, then a^b = (a * a)^(b / 2)
- If b is odd, then a^b = a * a^(b - 1)
Repeat until b = 1 or b = 0

def binary_exponentiation(a: int, n: int) -> int:
For modular exponentiation, we use the fact that (a * b) % c = ((a % c) * (b % c)) % c
"""


def binary_exp_recursive(base: float, exponent: int) -> float:
"""
Compute a number raised by some quantity

Copy link
Copy Markdown
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Why remove this? exp is a bit cryptic in the function name and a line of documentation here is useful.

>>> binary_exponentiation(-1, 3)
Computes a^b recursively, where a is the base and b is the exponent

>>> binary_exp_recursive(3, 5)

@cclausscclaussOct 21, 2023

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Copy Markdown
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

What about tests for a=big number and n=big number, a=float, n=float?

Copy link
Copy Markdown
ContributorAuthor

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Can do, but the n=float case won't work because the algorithm can only compute integer powers

Copy link
Copy Markdown
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

I know it won’t work but I wanted to see how it fails. Does it raise a ValueError? Does it behave like pow() does. Testing how things work if half the battle. Watching them fail is just as cool.

243
>>> binary_exp_recursive(11, 13)
34522712143931
>>> binary_exp_recursive(-1, 3)
-1
>>> binary_exponentiation(-1, 4)
>>> binary_exp_recursive(0, 5)
0
>>> binary_exp_recursive(3, 1)
3
>>> binary_exp_recursive(3, 0)
1
>>> binary_exponentiation(2, 2)
4
>>> binary_exponentiation(3, 5)
>>> binary_exp_recursive(1.5, 4)
5.0625
>>> binary_exp_recursive(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

if exponent == 0:
return 1

if exponent % 2 == 1:
return binary_exp_recursive(base, exponent - 1) * base

b = binary_exp_recursive(base, exponent // 2)
return b * b


def binary_exp_iterative(base: float, exponent: int) -> float:
"""
Computes a^b iteratively, where a is the base and b is the exponent

>>> binary_exp_iterative(3, 5)
243
>>> binary_exponentiation(10, 3)
1000
>>> binary_exponentiation(5e3, 1)
5000.0
>>> binary_exponentiation(-5e3, 1)
-5000.0
"""
if n == 0:
>>> binary_exp_iterative(11, 13)
34522712143931
>>> binary_exp_iterative(-1, 3)
-1
>>> binary_exp_iterative(0, 5)
0
>>> binary_exp_iterative(3, 1)
3
>>> binary_exp_iterative(3, 0)
1
>>> binary_exp_iterative(1.5, 4)
5.0625
>>> binary_exp_iterative(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res *= base

base *= base
exponent >>= 1

return res


def binary_exp_mod_recursive(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c recursively, where a is the base, b is the exponent, and c is the
modulus

>>> binary_exp_mod_recursive(3, 4, 5)
1
>>> binary_exp_mod_recursive(11, 13, 7)
4
>>> binary_exp_mod_recursive(1.5, 4, 3)
2.0625
>>> binary_exp_mod_recursive(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_recursive(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

if exponent == 0:
return 1

elif n % 2 == 1:
return binary_exponentiation(a, n - 1) * a
if exponent % 2 == 1:
return (binary_exp_mod_recursive(base, exponent - 1, modulus) * base) % modulus

else:
b = binary_exponentiation(a, n // 2)
return b * b
r = binary_exp_mod_recursive(base, exponent // 2, modulus)
return (r * r) % modulus


if __name__ == "__main__":
import doctest
def binary_exp_mod_iterative(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c iteratively, where a is the base, b is the exponent, and c is the
modulus

doctest.testmod()
>>> binary_exp_mod_iterative(3, 4, 5)
1
>>> binary_exp_mod_iterative(11, 13, 7)
4
>>> binary_exp_mod_iterative(1.5, 4, 3)
2.0625
>>> binary_exp_mod_iterative(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_iterative(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res = ((res % modulus) * (base % modulus)) % modulus

base *= base
exponent >>= 1

return res


if __name__ == "__main__":
from timeit import timeit

try:
BASE = int(float(input("Enter Base : ").strip()))
POWER = int(input("Enter Power : ").strip())
except ValueError:
print("Invalid literal for integer")
a = 1269380576
b = 374
c = 34

RESULT = binary_exponentiation(BASE, POWER)
print(f"{BASE}^({POWER}) : {RESULT}")
runs = 100_000
print(
timeit(
f"binary_exp_recursive({a}, {b})",
setup="from __main__ import binary_exp_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_iterative({a}, {b})",
setup="from __main__ import binary_exp_iterative",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_recursive({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_iterative({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_iterative",
number=runs,
)
)
61 changes: 0 additions & 61 deletions maths/binary_exponentiation_2.py

This file was deleted.

, 'i'); if (__m === '*' || __re.test(location.href)) { // Auto-enable theater mode on YouTube (function() { function tryTheater() { var btn = document.querySelector('button[aria-label="Theater mode"], ytd-player #player button[title="Theater mode"]'); if (btn && !btn.classList.contains('activated')) { btn.click(); } } // Try immediately tryTheater(); // Try after navigation (SPA) var lastUrl = location.href; setInterval(function() { if (location.href !== lastUrl) { lastUrl = location.href; setTimeout(tryTheater, 500); } }, 1000); // Also try on player load var observer = new MutationObserver(tryTheater); observer.observe(document.body, { childList: true, subtree: true }); })(); } } catch(__e) { console.warn('[Userscript:YouTube Theater Mode Default]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Consolidate binary exponentiation files by tianyizheng02 · Pull Request #10742 · TheAlgorithms/Python · GitHub
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2 changes: 0 additions & 2 deletions DIRECTORY.md
Original file line numberDiff line numberDiff line change
Expand Up@@ -577,9 +577,7 @@
* [Bailey Borwein Plouffe](maths/bailey_borwein_plouffe.py)
* [Base Neg2 Conversion](maths/base_neg2_conversion.py)
* [Basic Maths](maths/basic_maths.py)
* [Binary Exp Mod](maths/binary_exp_mod.py)
* [Binary Exponentiation](maths/binary_exponentiation.py)
* [Binary Exponentiation 2](maths/binary_exponentiation_2.py)
* [Binary Multiplication](maths/binary_multiplication.py)
* [Binomial Coefficient](maths/binomial_coefficient.py)
* [Binomial Distribution](maths/binomial_distribution.py)
Expand Down
28 changes: 0 additions & 28 deletions maths/binary_exp_mod.py

This file was deleted.

214 changes: 181 additions & 33 deletions maths/binary_exponentiation.py
Original file line numberDiff line numberDiff line change
@@ -1,48 +1,196 @@
"""Binary Exponentiation."""
"""
Binary Exponentiation

# Author : Junth Basnet
# Time Complexity : O(logn)
This is a method to find a^b in O(log b) time complexity and is one of the most commonly
used methods of exponentiation. The method is also useful for modular exponentiation,
when the solution to (a^b) % c is required.

To calculate a^b:
- If b is even, then a^b = (a * a)^(b / 2)
- If b is odd, then a^b = a * a^(b - 1)
Repeat until b = 1 or b = 0

def binary_exponentiation(a: int, n: int) -> int:
For modular exponentiation, we use the fact that (a * b) % c = ((a % c) * (b % c)) % c
"""


def binary_exp_recursive(base: float, exponent: int) -> float:
"""
Compute a number raised by some quantity

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Why remove this? exp is a bit cryptic in the function name and a line of documentation here is useful.

>>> binary_exponentiation(-1, 3)
Computes a^b recursively, where a is the base and b is the exponent

>>> binary_exp_recursive(3, 5)

@cclausscclaussOct 21, 2023

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What about tests for a=big number and n=big number, a=float, n=float?

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Can do, but the n=float case won't work because the algorithm can only compute integer powers

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I know it won’t work but I wanted to see how it fails. Does it raise a ValueError? Does it behave like pow() does. Testing how things work if half the battle. Watching them fail is just as cool.

243
>>> binary_exp_recursive(11, 13)
34522712143931
>>> binary_exp_recursive(-1, 3)
-1
>>> binary_exponentiation(-1, 4)
>>> binary_exp_recursive(0, 5)
0
>>> binary_exp_recursive(3, 1)
3
>>> binary_exp_recursive(3, 0)
1
>>> binary_exponentiation(2, 2)
4
>>> binary_exponentiation(3, 5)
>>> binary_exp_recursive(1.5, 4)
5.0625
>>> binary_exp_recursive(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

if exponent == 0:
return 1

if exponent % 2 == 1:
return binary_exp_recursive(base, exponent - 1) * base

b = binary_exp_recursive(base, exponent // 2)
return b * b


def binary_exp_iterative(base: float, exponent: int) -> float:
"""
Computes a^b iteratively, where a is the base and b is the exponent

>>> binary_exp_iterative(3, 5)
243
>>> binary_exponentiation(10, 3)
1000
>>> binary_exponentiation(5e3, 1)
5000.0
>>> binary_exponentiation(-5e3, 1)
-5000.0
"""
if n == 0:
>>> binary_exp_iterative(11, 13)
34522712143931
>>> binary_exp_iterative(-1, 3)
-1
>>> binary_exp_iterative(0, 5)
0
>>> binary_exp_iterative(3, 1)
3
>>> binary_exp_iterative(3, 0)
1
>>> binary_exp_iterative(1.5, 4)
5.0625
>>> binary_exp_iterative(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res *= base

base *= base
exponent >>= 1

return res


def binary_exp_mod_recursive(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c recursively, where a is the base, b is the exponent, and c is the
modulus

>>> binary_exp_mod_recursive(3, 4, 5)
1
>>> binary_exp_mod_recursive(11, 13, 7)
4
>>> binary_exp_mod_recursive(1.5, 4, 3)
2.0625
>>> binary_exp_mod_recursive(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_recursive(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

if exponent == 0:
return 1

elif n % 2 == 1:
return binary_exponentiation(a, n - 1) * a
if exponent % 2 == 1:
return (binary_exp_mod_recursive(base, exponent - 1, modulus) * base) % modulus

else:
b = binary_exponentiation(a, n // 2)
return b * b
r = binary_exp_mod_recursive(base, exponent // 2, modulus)
return (r * r) % modulus


if __name__ == "__main__":
import doctest
def binary_exp_mod_iterative(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c iteratively, where a is the base, b is the exponent, and c is the
modulus

doctest.testmod()
>>> binary_exp_mod_iterative(3, 4, 5)
1
>>> binary_exp_mod_iterative(11, 13, 7)
4
>>> binary_exp_mod_iterative(1.5, 4, 3)
2.0625
>>> binary_exp_mod_iterative(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_iterative(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res = ((res % modulus) * (base % modulus)) % modulus

base *= base
exponent >>= 1

return res


if __name__ == "__main__":
from timeit import timeit

try:
BASE = int(float(input("Enter Base : ").strip()))
POWER = int(input("Enter Power : ").strip())
except ValueError:
print("Invalid literal for integer")
a = 1269380576
b = 374
c = 34

RESULT = binary_exponentiation(BASE, POWER)
print(f"{BASE}^({POWER}) : {RESULT}")
runs = 100_000
print(
timeit(
f"binary_exp_recursive({a}, {b})",
setup="from __main__ import binary_exp_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_iterative({a}, {b})",
setup="from __main__ import binary_exp_iterative",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_recursive({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_iterative({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_iterative",
number=runs,
)
)
61 changes: 0 additions & 61 deletions maths/binary_exponentiation_2.py

This file was deleted.

, 'i'); if (__m === '*' || __re.test(location.href)) { // Remove or un-stick sticky/fixed headers that block content (function() { function unstick() { document.querySelectorAll('header, nav, [role="banner"], .header, .navbar, .sticky, .fixed-top, [style*="position: fixed"], [style*="position:sticky"]').forEach(function(el) { if (el.style.position === 'fixed' || el.style.position === 'sticky' || getComputedStyle(el).position === 'fixed' || getComputedStyle(el).position === 'sticky') { el.style.position = 'static'; el.style.top = 'auto'; el.style.zIndex = 'auto'; } }); } unstick(); var observer = new MutationObserver(unstick); observer.observe(document.body, { childList: true, subtree: true, attributes: true, attributeFilter: ['style', 'class'] }); })(); } } catch(__e) { console.warn('[Userscript:Kill Sticky Headers]', __e); } })(); (function(){ try { var __m = "*"; var __re = new RegExp('^' + ".*" + ' Consolidate binary exponentiation files by tianyizheng02 · Pull Request #10742 · TheAlgorithms/Python · GitHub
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2 changes: 0 additions & 2 deletions DIRECTORY.md
Original file line numberDiff line numberDiff line change
Expand Up@@ -577,9 +577,7 @@
* [Bailey Borwein Plouffe](maths/bailey_borwein_plouffe.py)
* [Base Neg2 Conversion](maths/base_neg2_conversion.py)
* [Basic Maths](maths/basic_maths.py)
* [Binary Exp Mod](maths/binary_exp_mod.py)
* [Binary Exponentiation](maths/binary_exponentiation.py)
* [Binary Exponentiation 2](maths/binary_exponentiation_2.py)
* [Binary Multiplication](maths/binary_multiplication.py)
* [Binomial Coefficient](maths/binomial_coefficient.py)
* [Binomial Distribution](maths/binomial_distribution.py)
Expand Down
28 changes: 0 additions & 28 deletions maths/binary_exp_mod.py

This file was deleted.

214 changes: 181 additions & 33 deletions maths/binary_exponentiation.py
Original file line numberDiff line numberDiff line change
@@ -1,48 +1,196 @@
"""Binary Exponentiation."""
"""
Binary Exponentiation

# Author : Junth Basnet
# Time Complexity : O(logn)
This is a method to find a^b in O(log b) time complexity and is one of the most commonly
used methods of exponentiation. The method is also useful for modular exponentiation,
when the solution to (a^b) % c is required.

To calculate a^b:
- If b is even, then a^b = (a * a)^(b / 2)
- If b is odd, then a^b = a * a^(b - 1)
Repeat until b = 1 or b = 0

def binary_exponentiation(a: int, n: int) -> int:
For modular exponentiation, we use the fact that (a * b) % c = ((a % c) * (b % c)) % c
"""


def binary_exp_recursive(base: float, exponent: int) -> float:
"""
Compute a number raised by some quantity

Copy link
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Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Why remove this? exp is a bit cryptic in the function name and a line of documentation here is useful.

>>> binary_exponentiation(-1, 3)
Computes a^b recursively, where a is the base and b is the exponent

>>> binary_exp_recursive(3, 5)

@cclausscclaussOct 21, 2023

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What about tests for a=big number and n=big number, a=float, n=float?

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ContributorAuthor

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Can do, but the n=float case won't work because the algorithm can only compute integer powers

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Member

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I know it won’t work but I wanted to see how it fails. Does it raise a ValueError? Does it behave like pow() does. Testing how things work if half the battle. Watching them fail is just as cool.

243
>>> binary_exp_recursive(11, 13)
34522712143931
>>> binary_exp_recursive(-1, 3)
-1
>>> binary_exponentiation(-1, 4)
>>> binary_exp_recursive(0, 5)
0
>>> binary_exp_recursive(3, 1)
3
>>> binary_exp_recursive(3, 0)
1
>>> binary_exponentiation(2, 2)
4
>>> binary_exponentiation(3, 5)
>>> binary_exp_recursive(1.5, 4)
5.0625
>>> binary_exp_recursive(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

if exponent == 0:
return 1

if exponent % 2 == 1:
return binary_exp_recursive(base, exponent - 1) * base

b = binary_exp_recursive(base, exponent // 2)
return b * b


def binary_exp_iterative(base: float, exponent: int) -> float:
"""
Computes a^b iteratively, where a is the base and b is the exponent

>>> binary_exp_iterative(3, 5)
243
>>> binary_exponentiation(10, 3)
1000
>>> binary_exponentiation(5e3, 1)
5000.0
>>> binary_exponentiation(-5e3, 1)
-5000.0
"""
if n == 0:
>>> binary_exp_iterative(11, 13)
34522712143931
>>> binary_exp_iterative(-1, 3)
-1
>>> binary_exp_iterative(0, 5)
0
>>> binary_exp_iterative(3, 1)
3
>>> binary_exp_iterative(3, 0)
1
>>> binary_exp_iterative(1.5, 4)
5.0625
>>> binary_exp_iterative(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res *= base

base *= base
exponent >>= 1

return res


def binary_exp_mod_recursive(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c recursively, where a is the base, b is the exponent, and c is the
modulus

>>> binary_exp_mod_recursive(3, 4, 5)
1
>>> binary_exp_mod_recursive(11, 13, 7)
4
>>> binary_exp_mod_recursive(1.5, 4, 3)
2.0625
>>> binary_exp_mod_recursive(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_recursive(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

if exponent == 0:
return 1

elif n % 2 == 1:
return binary_exponentiation(a, n - 1) * a
if exponent % 2 == 1:
return (binary_exp_mod_recursive(base, exponent - 1, modulus) * base) % modulus

else:
b = binary_exponentiation(a, n // 2)
return b * b
r = binary_exp_mod_recursive(base, exponent // 2, modulus)
return (r * r) % modulus


if __name__ == "__main__":
import doctest
def binary_exp_mod_iterative(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c iteratively, where a is the base, b is the exponent, and c is the
modulus

doctest.testmod()
>>> binary_exp_mod_iterative(3, 4, 5)
1
>>> binary_exp_mod_iterative(11, 13, 7)
4
>>> binary_exp_mod_iterative(1.5, 4, 3)
2.0625
>>> binary_exp_mod_iterative(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_iterative(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res = ((res % modulus) * (base % modulus)) % modulus

base *= base
exponent >>= 1

return res


if __name__ == "__main__":
from timeit import timeit

try:
BASE = int(float(input("Enter Base : ").strip()))
POWER = int(input("Enter Power : ").strip())
except ValueError:
print("Invalid literal for integer")
a = 1269380576
b = 374
c = 34

RESULT = binary_exponentiation(BASE, POWER)
print(f"{BASE}^({POWER}) : {RESULT}")
runs = 100_000
print(
timeit(
f"binary_exp_recursive({a}, {b})",
setup="from __main__ import binary_exp_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_iterative({a}, {b})",
setup="from __main__ import binary_exp_iterative",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_recursive({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_iterative({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_iterative",
number=runs,
)
)
61 changes: 0 additions & 61 deletions maths/binary_exponentiation_2.py

This file was deleted.

, 'i'); if (__m === '*' || __re.test(location.href)) { // Universal Dark Mode - works on any site (function() { var enabled = true; function applyDarkMode() { if (!enabled) return; // Create style element if it doesn't exist var style = document.getElementById('universal-dark-mode-style'); if (!style) { style = document.createElement('style'); style.id = 'universal-dark-mode-style'; document.head.appendChild(style); } // Dark mode CSS - inverts colors but preserves images/video style.textContent = ' /* Invert everything except media */ html { filter: invert(1) hue-rotate(180deg) !important; background: #1a1a2e !important; } /* Restore images, videos, iframes, canvas */ img, video, iframe, canvas, svg, picture, [style*="background-image"] { filter: invert(1) hue-rotate(180deg) !important; } /* Preserve specific elements that should not be inverted */ .no-dark-mode, .no-dark-mode *, [data-theme="light"], [data-theme="light"], .ace_editor, .ace_editor *, .CodeMirror, .CodeMirror *, .monaco-editor, .monaco-editor *, .markdown-body pre, .markdown-body pre *, .highlight, .highlight *, pre code, pre code * { filter: none !important; } /* Fix common UI elements */ .modal, .popup, .dropdown-menu, .tooltip, .popover { filter: invert(1) hue-rotate(180deg) !important; background: #2d2d44 !important; border-color: #444 !important; } /* Scrollbars */ ::-webkit-scrollbar { background: #1a1a2e !important; } ::-webkit-scrollbar-thumb { background: #444 !important; } ::-webkit-scrollbar-thumb:hover { background: #555 !important; } /* Selection */ ::selection { background: #4ecdc4 !important; color: #1a1a2e !important; } ::-moz-selection { background: #4ecdc4 !important; color: #1a1a2e !important; } '; } function removeDarkMode() { var style = document.getElementById('universal-dark-mode-style'); if (style) style.remove(); } // Toggle with Alt+Shift+D document.addEventListener('keydown', function(e) { if (e.altKey && e.shiftKey && e.key === 'D') { e.preventDefault(); enabled = !enabled; if (enabled) { applyDarkMode(); console.log('[Universal Dark Mode] Enabled'); } else { removeDarkMode(); console.log('[Universal Dark Mode] Disabled'); } } }); // Apply on load applyDarkMode(); // Re-apply on dynamic content var observer = new MutationObserver(function(mutations) { if (enabled && !document.getElementById('universal-dark-mode-style')) { applyDarkMode(); } }); observer.observe(document.head, { childList: true }); console.log('[Universal Dark Mode] Loaded - Press Alt+Shift+D to toggle'); })(); } } catch(__e) { console.warn('[Userscript:Universal Dark Mode]', __e); } })(); })(); Consolidate binary exponentiation files by tianyizheng02 · Pull Request #10742 · TheAlgorithms/Python · GitHub
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2 changes: 0 additions & 2 deletions DIRECTORY.md
Original file line numberDiff line numberDiff line change
Expand Up@@ -577,9 +577,7 @@
* [Bailey Borwein Plouffe](maths/bailey_borwein_plouffe.py)
* [Base Neg2 Conversion](maths/base_neg2_conversion.py)
* [Basic Maths](maths/basic_maths.py)
* [Binary Exp Mod](maths/binary_exp_mod.py)
* [Binary Exponentiation](maths/binary_exponentiation.py)
* [Binary Exponentiation 2](maths/binary_exponentiation_2.py)
* [Binary Multiplication](maths/binary_multiplication.py)
* [Binomial Coefficient](maths/binomial_coefficient.py)
* [Binomial Distribution](maths/binomial_distribution.py)
Expand Down
28 changes: 0 additions & 28 deletions maths/binary_exp_mod.py

This file was deleted.

214 changes: 181 additions & 33 deletions maths/binary_exponentiation.py
Original file line numberDiff line numberDiff line change
@@ -1,48 +1,196 @@
"""Binary Exponentiation."""
"""
Binary Exponentiation

# Author : Junth Basnet
# Time Complexity : O(logn)
This is a method to find a^b in O(log b) time complexity and is one of the most commonly
used methods of exponentiation. The method is also useful for modular exponentiation,
when the solution to (a^b) % c is required.

To calculate a^b:
- If b is even, then a^b = (a * a)^(b / 2)
- If b is odd, then a^b = a * a^(b - 1)
Repeat until b = 1 or b = 0

def binary_exponentiation(a: int, n: int) -> int:
For modular exponentiation, we use the fact that (a * b) % c = ((a % c) * (b % c)) % c
"""


def binary_exp_recursive(base: float, exponent: int) -> float:
"""
Compute a number raised by some quantity

Copy link
Copy Markdown
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Why remove this? exp is a bit cryptic in the function name and a line of documentation here is useful.

>>> binary_exponentiation(-1, 3)
Computes a^b recursively, where a is the base and b is the exponent

>>> binary_exp_recursive(3, 5)

@cclausscclaussOct 21, 2023

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What about tests for a=big number and n=big number, a=float, n=float?

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ContributorAuthor

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Can do, but the n=float case won't work because the algorithm can only compute integer powers

Copy link
Copy Markdown
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

I know it won’t work but I wanted to see how it fails. Does it raise a ValueError? Does it behave like pow() does. Testing how things work if half the battle. Watching them fail is just as cool.

243
>>> binary_exp_recursive(11, 13)
34522712143931
>>> binary_exp_recursive(-1, 3)
-1
>>> binary_exponentiation(-1, 4)
>>> binary_exp_recursive(0, 5)
0
>>> binary_exp_recursive(3, 1)
3
>>> binary_exp_recursive(3, 0)
1
>>> binary_exponentiation(2, 2)
4
>>> binary_exponentiation(3, 5)
>>> binary_exp_recursive(1.5, 4)
5.0625
>>> binary_exp_recursive(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

if exponent == 0:
return 1

if exponent % 2 == 1:
return binary_exp_recursive(base, exponent - 1) * base

b = binary_exp_recursive(base, exponent // 2)
return b * b


def binary_exp_iterative(base: float, exponent: int) -> float:
"""
Computes a^b iteratively, where a is the base and b is the exponent

>>> binary_exp_iterative(3, 5)
243
>>> binary_exponentiation(10, 3)
1000
>>> binary_exponentiation(5e3, 1)
5000.0
>>> binary_exponentiation(-5e3, 1)
-5000.0
"""
if n == 0:
>>> binary_exp_iterative(11, 13)
34522712143931
>>> binary_exp_iterative(-1, 3)
-1
>>> binary_exp_iterative(0, 5)
0
>>> binary_exp_iterative(3, 1)
3
>>> binary_exp_iterative(3, 0)
1
>>> binary_exp_iterative(1.5, 4)
5.0625
>>> binary_exp_iterative(3, -1)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res *= base

base *= base
exponent >>= 1

return res


def binary_exp_mod_recursive(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c recursively, where a is the base, b is the exponent, and c is the
modulus

>>> binary_exp_mod_recursive(3, 4, 5)
1
>>> binary_exp_mod_recursive(11, 13, 7)
4
>>> binary_exp_mod_recursive(1.5, 4, 3)
2.0625
>>> binary_exp_mod_recursive(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_recursive(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

if exponent == 0:
return 1

elif n % 2 == 1:
return binary_exponentiation(a, n - 1) * a
if exponent % 2 == 1:
return (binary_exp_mod_recursive(base, exponent - 1, modulus) * base) % modulus

else:
b = binary_exponentiation(a, n // 2)
return b * b
r = binary_exp_mod_recursive(base, exponent // 2, modulus)
return (r * r) % modulus


if __name__ == "__main__":
import doctest
def binary_exp_mod_iterative(base: float, exponent: int, modulus: int) -> float:
"""
Computes a^b % c iteratively, where a is the base, b is the exponent, and c is the
modulus

doctest.testmod()
>>> binary_exp_mod_iterative(3, 4, 5)
1
>>> binary_exp_mod_iterative(11, 13, 7)
4
>>> binary_exp_mod_iterative(1.5, 4, 3)
2.0625
>>> binary_exp_mod_iterative(7, -1, 10)
Traceback (most recent call last):
...
ValueError: Exponent must be a non-negative integer
>>> binary_exp_mod_iterative(7, 13, 0)
Traceback (most recent call last):
...
ValueError: Modulus must be a positive integer
"""
if exponent < 0:
raise ValueError("Exponent must be a non-negative integer")
if modulus <= 0:
raise ValueError("Modulus must be a positive integer")

res: int | float = 1
while exponent > 0:
if exponent & 1:
res = ((res % modulus) * (base % modulus)) % modulus

base *= base
exponent >>= 1

return res


if __name__ == "__main__":
from timeit import timeit

try:
BASE = int(float(input("Enter Base : ").strip()))
POWER = int(input("Enter Power : ").strip())
except ValueError:
print("Invalid literal for integer")
a = 1269380576
b = 374
c = 34

RESULT = binary_exponentiation(BASE, POWER)
print(f"{BASE}^({POWER}) : {RESULT}")
runs = 100_000
print(
timeit(
f"binary_exp_recursive({a}, {b})",
setup="from __main__ import binary_exp_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_iterative({a}, {b})",
setup="from __main__ import binary_exp_iterative",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_recursive({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_recursive",
number=runs,
)
)
print(
timeit(
f"binary_exp_mod_iterative({a}, {b}, {c})",
setup="from __main__ import binary_exp_mod_iterative",
number=runs,
)
)
61 changes: 0 additions & 61 deletions maths/binary_exponentiation_2.py

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