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add evocative examples for BitOr and BitXor - #35926
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Let's slow down a bit here. There was an interesting debate on the nature of bitwise operations here: #35927. I plan to update |
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I've taken the improvements in #35993 and applied them to this PR. I figured that a simple |
These are exactly equivalent to PR rust-lang#35809, with one caveat: I do not believe there is a non-bitwise binary "xor" operator in Rust, so here it's expressed as (a || b) && !(a && b). r? @GuillaumeGomez improved documentation a la PR rust-lang#35993
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Thanks! @bors: r+ rollup |
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📌 Commit 8ca9fa1 has been approved by |
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… r=GuillaumeGomez add evocative examples for `BitOr` and `BitXor` These are exactly equivalent to PR rust-lang#35809, with one caveat: I do not believe there is a non-bitwise binary XOR operator in Rust, so here it's expressed as `(a || b) && !(a && b)`. Alternative decompositions are `(a && !b) || (!a && b)` and `(a || b) && (!a || !b)`. Let me know if you think one of those would be clearer. r? @GuillaumeGomez
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… r=GuillaumeGomez add evocative examples for `BitOr` and `BitXor` These are exactly equivalent to PR rust-lang#35809, with one caveat: I do not believe there is a non-bitwise binary XOR operator in Rust, so here it's expressed as `(a || b) && !(a && b)`. Alternative decompositions are `(a && !b) || (!a && b)` and `(a || b) && (!a || !b)`. Let me know if you think one of those would be clearer. r? @GuillaumeGomez
sophiajt pushed a commit
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Aug 31, 2016
… r=GuillaumeGomez add evocative examples for `BitOr` and `BitXor` These are exactly equivalent to PR rust-lang#35809, with one caveat: I do not believe there is a non-bitwise binary XOR operator in Rust, so here it's expressed as `(a || b) && !(a && b)`. Alternative decompositions are `(a && !b) || (!a && b)` and `(a || b) && (!a || !b)`. Let me know if you think one of those would be clearer. r? @GuillaumeGomez
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These are exactly equivalent to PR #35809, with one caveat: I do not believe there is a non-bitwise binary XOR operator in Rust, so here it's expressed as
(a || b) && !(a && b).Alternative decompositions are
(a && !b) || (!a && b)and(a || b) && (!a || !b). Let me know if you think one of those would be clearer.r? @GuillaumeGomez